@kam1212 First, 0.00106 W-s is not power, it's energy per cycle. Second, can you please explain how you can get 63W from E = 0.00106 W-s? It's energy per cycle, so the power transferred (or consumed) per cycle should be P = E x Fsw = 0.00106 x 60k = 96W. Explain how you are getting 63W with 0.00106 W-s.
@kam1212 Another part of the story is the inductance. You didn't mention 3.9 uH in your question, initially. But you mention a peak current of 23.2 Amps. From E = 0.5 L I² and V = L di/dt, I found the values I mentioned in my comment. That's all.