You're right. IMO, the user can't be a good example of a good user of MSE. They have stayed quite a while, yet that action seems like a newly joined user.
Hi, @quid! Yodeling is good for messaging others across mountains, that separate them!! Disclaimer. Nothing serious I'm yodeling you for. Just want to say, hello!
@quid Quite nice: warm (almost too warm, so soon), sunny. I got a lot done last night and early this morning, so this afternoon, I'm relaxing a bit!. How about your weekend! You're lucky, 'cuz your favorite day is tomorrow! Also, my birthday is one week from today; coincides with Mother's Day in the US. Sort of bitter sweet, because I lost her in 1996.
@quid Good for you! You wouldn't want to be ill prepared for your favorite day! I spend Friday evening, last evening, and this morning finalizing my final exams the spring term.
@hyper-neutrino And yet they remain. Unless you can guarantee that the two remaining lurkers won't enter and leave every twenty seconds, I'll call them out for who they are. If even I can see they are are suspended for a year, they are already publicly understood to be suspended. What do you consider the problem? Let them harass your chats, not outs. All three are here, so clearly the problem has NOT been dealt with!!
@amWhy Do you remember this sentence of mine? I leave comments to people who know MathJax but do not add any effort to their question. For users who do not know MathJax, we can make some discounts. We have to organize their questions and motivate them on their first try. This is the question type I'm talking about. I did not leave a comment on this question. Because I think OP knows the policy better than I do.
Determine all positive integers $a$ for which the equation
$$\left ( 1 + \frac {1} {x} \right ) \cdot \left ( 1 + \frac {1} {x+1} \right ) \cdots \left ( 1 + \frac {1} {x+a} \right ) = a - x $$
has at least one integer solution $x$.
For each such integer $a$, determine the corresponding solutions.
Yes, I see that; they were around a long time ago, but seem to be asking contest math questions now. That was a poor post, which I downvoted and voted to close; thanks for pointing me to it.
@amWhy $\ddot\smile$ I'm being a little soft. I can't go to downvote :) Something on my mind. What time is it in the country where you are now?Can I ask $\ddot\smile$
@amWhy Yes, it would be nice to sleep 3 hours ago. I was solving the Michael Penn's (YouTube) contest problem. I made it. I can sleep now. I say good night to you. But although it is little interesting. I wish you health and well-being.
Determine all positive integers $a$ for which the equation
$$\left ( 1 + \frac {1} {x} \right ) \cdot \left ( 1 + \frac {1} {x+1} \right ) \cdots \left ( 1 + \frac {1} {x+a} \right ) = a - x $$
has at least one integer solution $x$.
For each such integer $a$, determine the corresponding solutions.
