Stirling says $n! = \Omega(n^{n+1/2} e^{-n})$ so $(n!)^2 = \Omega(n^{2n+1}e^{-2n}) and $n^{n+1}e^{-2n} \ge 1$ @Knight

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Stirling looks like rip off of Taylor swift

lol can u remove that above statement >_<

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oh

has anyone have a good model for stock market

rip grammar

want to invest some money 😈

uhhhh

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That's not a very nice way to talk about Robert

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