the k tree

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chrispsn

7:19 AM

@ngn excellent, ty

and @dzaima! come to the dark side

unlike the other solns here @dzaima's doesn't have any grading or gt/lt gist.github.com/chrispsn/…

now: improve the where solns

4 hours later…

dzaima

11:36 AM

@chrispsn i like my unicode characters too much to properly use k. i do try to follow along with things though

richie

12:25 PM

Here's another where solution. Avoids take but assumes cat count and iota. w:{,/{{y}[;x]'!y}'[!#x;x]}

chrispsn

12:50 PM

@richie thanks! interestingly segfaults k9 when given w 2 0

chrispsn

1:02 PM

aha, this segfaults 2020.04.14 - have reported. 0 0,()

1 hour later…

Stevan Apter

2:03 PM

avoid the prefix in @dzaima's solution with (0 1#0){,/'@[;y,!y]\:x,,(#*x)#y}/:!

ngn

2:26 PM

@StevanApter ah, so i was wrong. there is a way to give an initial value.

ngn

2:40 PM

@user91994 hi! if you want to be able to chat here, please drop me a line at ".@acgiklmnov"@9 5 3 6 0 9 5 3 6 10 7 10 11 1 4 8 2 5 7 0 3 10 8 (evaluated as k code) and i'll ask the moderators to grant you write access - it may take a while, usually a couple of hours.

4 hours later…

Stevan Apter

6:51 PM

1010data is looking for someone (or a pair of someones) for the k gui team: js and k, and some experience or at least interest in gui design and implementation. let me know if you're interested ...

1 hour later…

Stevan Apter

7:52 PM

on composing adverbs with . and wanting to have more than 8 arguments to a lambda. here's a real example in k3:

:
({branch[a;d;p;y]. x}/).((q;r;s;t;u;v;w);b)}

branch:{[a;d;p;b;q;r;s;t;u;v;w]
:

b is a vector, q-w are vectors describing the state, and a, d, and p are parameters.

sure, we could make q-w rows of a matrix and use deconstructive assignment on the receiving end, or possibly better, elements of a dictionary, but since we will reference them one at a time it makes for shorter clearer code to break them out as individuals.

1 hour later…