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1:10 PM
The best way to start a bibliography
I couldn't find Aristotle's editor, though
 
lol
 
You could've cited the secondary source, from where you got the info.
 
I only read original papers, sir
I read Aristotle's preprint on arxiv
 
Then cite that arxiv article. :)
 
I think it was arxiv's article 000001
Or maybe 2, 1 might be Thales or Pythagoras
Why is that paper saying that chronology is reflexive
Oh wait, he's only talking about causal relation
 
1:28 PM
This is arxiv's first paper
 
1:55 PM
@Slereah - Are you sure that the PDG booklet is free?
I couldn't find any explicit declaration on that link.
 
100% free
Under the assumption that only a madman would order it for himself, I suppose
 
Right.
 
you can also get a free bible
A free quran
A free book of mormon
There's a plethora of free books on the internet!
 
I've ordered for PDG too, just wanted to ensure that there are no hidden costs that spring up when it is too late to disown it.
 
All the major religions, really
Christianity, Islam, Mormonism, high energy physics
 
1:58 PM
lol
 
Hi chat
 
@Slereah You mean hard printed?
 
yes
Although if you want a free religious book they usually aks you for reasons
Do u want some Jesus
Oh btw if you order the PDG people assume you're a doctor
They called me Dr. Lereah in emails
 
Which is good to hear.
 
Can I know why conductitvity of electrolyte is directly proportional to temperature but for metal temperature is inversely proportional?
 
2:01 PM
I'm guessing it's due to the sparsity of charges in a liquid
Versus in a metal
I dunno to be quite honest
 
Same here. Also, I'm not inclined right now to find out, to be honest.
Maybe you could ask on the main site.
Either you get an answer.
Or you get dupe-hammered.
Which also implies you get an answer :P
 
hammer time
Can't touch this
 
On a more serious note: you can use the search function of the site before asking there.
 
@Slereah - I understand for the religious books, they give it away for free because they would want more proponents/appreciators, but does the same also hold for technical literature?
 
2:07 PM
no
Only the pdg that I know of
 
^ That.
Alright thanks.
 
I guess it's financed with TAX PAYER MONEY
 
Actually it is even better.
According to your AMA info, you were at the university of Nantes.
Now that prompts the question:
Which country's citizens pay the taxes that fund PDG publishing? :P
 
Not quite sure
I think it's part of CERN funding
So all members of CERN
 
If XYZ country doesn't participate in that fundraising, those citizens get it for FREE !!
I count 28 members.
 
2:15 PM
maybe it's some rich guy who thinks generating interest in physics is a worthy cause?
 
Through free distribution of Particle Data Booklets?
 
why not?
 
That would be more of a deterrent.
People would run away.
From HEP at least.
 
not the ones who are genuinely interested
 
Yes.
But rich guys would generally tend to promote popular Physics than specialized Physics, so that one could draw more people from a smaller age demographic.
 
2:21 PM
who knows what these rich guys think these days
 
True.
 
Pop Physics attracts a lot of crack pots
 
@TheDarkSide question ban. I asked on chemistry now :D
 
you've been question banned?
 
Yes :(
 
2:27 PM
for how long?
 
That’s common on physics.se for new learners
Maybe 6 months
 
it's one of those automated-by-the system bans @Fawad, isn't it?
 
It's not for 6 months then.
if you fix the questions that have been downvoted/deleted, and ask for help on Physics Meta to figure out how to fix them, you will be allowed to ask questions much sooner.
 
do it^
try to work with the system
people will try to help you
 
2:33 PM
Apr 11 at 6:46, by Secret
@Fawad Me being question banned 4 years ago due to 4 poorly received question (with one of them due to mislead by a crank youtube thing and get hastly downvoted and closed) is the main reason I pop up in this chat. Roughly a month later, the ban wore off, although I rarely had the need to ask questions in main until recently
 
1. a month $\neq$ 6 months.
 
@heather Proof?
 
2. it appears from that comment they didn't try to undo the ban by working with the system.
3. the ban varies from person to person, depending on the starting conditions and what is done to fix it.
 
1 is totally equal to 6
 
@Fawad That's not true, the proportion of users affected by the automated question bans is really tiny, and most users learn what kind of questions we don't like before they get an extended automated ban like you. It's not because you are a "new learner", it's because you continued to post questions that showed no effort at all after being told that you should take care to do so.
 
2:34 PM
@BalarkaSen, @Slereah not helping =P
 
Well, what do you want us to say? 1 = 6 is an established fact of mathematics.
 
What?
How?
 
It's also a Millennium prize problem
 
21 secs ago, by The Dark Side
What?
 
@BalarkaSen Well, it is true in $\mathbb{Z}/5\mathbb{Z}$... :P
 
2:36 PM
1*0 = 6*0
1/0 = 6/0
 
:: Facepalm ::
 
@heather my last question was asked on 9th march 2017 (nearly 4 months before..)
 
Which has 2upvotes.
 
p 365
 
2:39 PM
@Fawad have you done anything to try to fix it?
 
@Slereah Dem filthy logicians
 
how dare you call the father of analyse "filthy"
 
@heather I flagged my -ve voted question to make anonymous but moderators didn’t did anything.. (I was advised not to make question anonymous)
 
@BalarkaSen Modular arithmetic?
 
it's true mod 5 yeah
 
2:42 PM
@Fawad, sorry, ask @ACuriousMind or another mod for help fixing things, but your "anonymous" fix won't help anything. just because it's anonymous to the outside world doesn't mean it's anonymous to the system.
 
i was joking anyway
 
@BalarkaSen We don't have 5 mods in this room right now. :P
Only 2.
 
flag it as "offensive" and we will
mod 2 becomes mod n
 
Mod 3 now !!
Mod 4 now !!
 
wtf, I was JOKING!!!
 
2:46 PM
Bah. Don't flag things that don't need fixing, and leave us poor mods alone.
 
What happened? Did something get flagged?
 
@PearsonArtPhoto this is all my fault, sorry
 
LOL. Don't worry about it, just do better in the future.
 
will do
thanks
 
2:47 PM
bertrand russell is definitely a filthy logician
nothing offensive bout that
 
-_-
 
It all started with a $1 = 6$ joke !!
 
where is the ignore button
 
Hahaha ...
 
Balarka
Actions
invite this user…
hide posts
ignore this user (everywhere)
 
2:49 PM
@Fawad: in electrolytes the mobility of the carriers goes up with temperature because the viscosity of the electrolyte decreases.
 
whatever that boats your goat
i mean, floats your boat
 
@Fawad: In metals the mobility of the carriers decreases with temperature because they get scattered by the thermal vibrations of the lattice.
 
@JohnRennie oh. I need to learn what mobility is. Thanks.
 
@BalarkaSen you almost got me banned
 
your welcome
 
2:51 PM
good job
 
@user685272 That's kind of your fault. If Balarka Sen told you to put your butt in the oven would you do it? :-)
 
lol
tbh I wouldn't put my butt in the oven even if i told that to myself
 
@BalarkaSen your you're
 
... so long as the oven wasn't turned on I suppose.
 
SBM
uh what?
 
2:54 PM
@user685272 i appreciate you're concern about my typos
3
 
:-)
 
Your skullpatrol arent you
Didn't recognize at first.
 
9 mins ago, by user685272
@PearsonArtPhoto this is all my fault, sorry
@BalarkaSen who?
"your" is a possessive, while you're is a contraction for you are
 
when you read too much joyce nothing matters anymore
 
3:00 PM
it will matter when you lose marks
 
he was a genius for sure
 
But this is still not going to help in detecting qualia. E.g. a person with a shifted color spectrum perception may well see 700 nm as a greenish color (what we name for the color at 500nm) and still name it red, for example
Red is more distinctive because... danger?
Or is qualia just like a gauge freedom, that it does not really affect the overall outcome of how the society evolved. Thus it can be possible that most of us see red as a 700 nm like color, but for some might see red (700 nm) as what we see as the color at 500 nm
that is, like most physical qualities, only the relative sense matters and not so much the absolute sense?
 
3:20 PM
it doesn't matter if you're black or white, we all have red blood
 
 
[Random statement]
> Of all organisms on the planet, ONLY human beings are known to deliberately harm each other for pointless reasons
 
Why is approximate symbol used instead of minus sign?
(Topic: Error Analyisis)
@DawoodibnKareem Great Explanation. TYSM!!
 
That does not make sense, absolute error is the absolute difference between the true value and the measured value, thus that should be a minus sign
 
@Secret At many places in this chapter, that sign has been used instead of minus
 
3:27 PM
Do they demonstrate an example calculation with that sign used in it?
 
@Secret They used minus sign in calculation
Anyway, this was one of the many mistakes in my physics textbook.
I'll ignore it
Such books just confuse students!
 
~ only makes sense if they mean there is nonzero absolute error if True value ~ measured value instead of true value = measured value
 
ok'
 
So perhaps that's not an equation, but a conceptual statement, either way, the presentation is very unclear
 
I just couldn't decide whether to have pizza or burgers for lunch ...
 
3:53 PM
so you're gonna eat all that?
 
It has been eaten - all of it! Very nice it was too.
 
with beer
 
Possibly ... :-)
 
4:12 PM
@JohnRennie - you were a colloid scientist?
 
@JohnRennie A short question.
Suppose I have a ball in my hand in an elevator capable of accelerating with 7 m/s^2. The elevator starts descending downwards. The moment it starts, I drop the ball. Could you tell me all the acceleration of the things (elevator, ball) in relative motion(read: acceleration) terms?
 
4:52 PM
@JohnRennie you better be using silverware
 
 
1 hour later…
6:07 PM
@JohnRennie 911
"The network adapter is experiencing diver or hardware related problems"
 
Sid
@0celo7 he he. You still haven't recovered?
You just need to try once..
 
6:21 PM
@0celo7 what happened? Did the wireless network just stop working?
@TheDarkSide Yes, I worked as an industrial colloid scientist.
 
@JohnRennie More 911 help sought from you !!
So, which one of us, me or 0celo7 starts first?
In rough terms, for Mie scattering we would want a scatterer size comparable to, or bigger than the wavelength of light, right?
Whereas for Rayleigh, the scatterer size should be appreciably smaller than the wavelength.
Is that correct, @JohnRennie?
 
Basically yes. Mie scattering is the intermediate case between very small scatterers and very large scatterers where diffraction effects are important.
I haven't done a lot of work in this area, but as I recall Mie scattering is the complicated one to calculate.
 
No problem, nothing theoretical. So, if were to recreate these for a small demonstration, can we create some colloidal suspensions in a solvent, e.g. water?
 
You can buy colloidal dispersions of various sizes and materials. You can make your own, but getting a narrow particle size distribution takes a fair bit of work.
 
Now, if the visible light is 400-700 nm, our rough criteria would be $d<<0.4$ microns for Rayleigh and $d \sim 0.7$ microns or bigger for Mie?
@JohnRennie Yes. I am discovering that part.
 
6:34 PM
The common types are silica and polystyrene. Typically sillica dispersions are grown by hydrolysing siloxanes while the polystyrene dispresions are grown (unsurprisingly) by polymerising styrene.
Mie scattering occurs when the particle size and light wavelength are the same.
So you want particles in the 400-700nm range.
Much bigger than a micron and the dispersions just look white and boring.
 
@JohnRennie Yes. I agree.
 
We used to get our silica dispersions from a firm called Ludox.
 
@JohnRennie Won't that also depend on the path length of the sample?
 
Google, Google, aha the firm is Grace and Ludox is the brand name of the dispersion
@TheDarkSide short path length = pale white and boring, long path length = bright white and boring.
 
@JohnRennie Haha.
 
6:39 PM
That wasn't meant to be a joke!
 
I'm not taking that as one either.
 
But Mie scattering isn't very spectacular. As I recall you don't get vibrant colours or anything very exciting.
 
@JohnRennie All colors are equally scattered, if I'm right. That's why it is "boring".
We would probably want a very narrow size distribution for a very controlled experiment, but any common household stuff that can approximately get the job done?
 
@TheDarkSide No, there is a wavelength dependance, because obviously the particle size to wavelength ratio is important. But I don't recall it making a huge difference.
What experiment do you have in mind?
 
Something of this tune: measure $I/I_0$ for different colors, for the same suspension, using any simple light sensor/intensity meter.
Mie scattering: Almost same for all.
Rayleigh: Huge change.
($I_0$ being the intensity of the respective color only through the solvent)
 
6:45 PM
I don't think it will be a very exciting experiment. Rayleigh scattering is generally weak. The sky only looks blue because there is a lot of atmosphere in between you and the Sun.
 
I agree with that.
But I'm only exploring the following:
 
The Ludox colloidal silicas with c. 50nm particle size just look a bit hazy even at very high silica content.
They do look noticably blue in reflected light and yellow in transmitted light due to the Rayleigh scattering, but the colours are pretty weak.
 
That is when you pass white light through them?
or on them?
 
There are some fascinating optical effects you get with dispersions. It's possible to get them to form ordered structures and then you get opalescence.
And if you can get the dispersion right on the point of phase separating you get critical opalescence
@TheDarkSide If you pass white light through the Ludox and view the transmitted light it looks yellow because the blue light is preferentially scattered out of the beam.
Likewise if you view from the side it looks blue because you're only seeing the scattered light.
 
That's a very useful link. Hopefully, I will return to that problem some time soon.
 
6:51 PM
Critical behaviour is a fascinating area.
 
@JohnRennie Yes. But suppose we pass only monochromatic light?
And measure the intensities. In and out.
We should see some change?
 
@TheDarkSide With monochromatic light you wouldn't see anything very exciting. The extinction coefficients would just increase slightly as you decrease the wavelength.
If you're doing the experiment you'd probably be best putting your PMT at the side so you're detecting the scattered light. That will give you the clearest changes as you change the wavelength.
 
@JohnRennie Now suppose one selects the path length smartly, won't that translate into an intensity difference?
@JohnRennie Yes. That's true.
 
@TheDarkSide yes, there will be an intensity difference. But for the small particle sizes even concentrated dispersions don't scatter very much light.
 
Now, what I am thinking is the following:
let us move away from the scattering, and talk about absorption.
We have the Beer Lambert law.
That exponential factor means that a large sample length of a small concentration is the same as a small sample length of a large concentration.
Is that fine?
 
6:56 PM
Yes
 
So, predominantly, there are two effects occurring in this problem: absorption and scattering.
Suppose my scatterers are not absorbing.
I don't know how correct is that assumption.
 
The material that the particles are made from don't absorb in the optical region. All they do is scatter. So what you are calling absorption is just a decrease in the transmitted intensity because some of the light is being scattered sideways.
 
No, that's for the scatterers.
We also have a solvent.
Which will absorb in general.
 
Most solvents don't absorb in the optical region.
 
7:00 PM
They will just scatter by Rayleigh scattering.
@TheDarkSide Obviously they don't because they're clear.
There will be some very weak absorption. Water does absorb at the red end of the spectrum, but you need several metres of path length to see it.
 
THAT'S EVEN BETTER !!
:: rejoices ::
The absorption of electromagnetic radiation by water depends on the state of the water. The absorption in the gas phase occurs in three regions of the spectrum. Rotational transitions are responsible for absorption in the microwave and far-infrared, vibrational transitions in the mid-infrared and near-infrared. Vibrational bands have rotational fine structure. Electronic transitions occur in the vacuum ultraviolet regions. Liquid water has no rotational spectrum but does absorb in the microwave region. == Overview == The water molecule, in the gaseous state, has three types of transition that can...
> Absorption coefficients for 200 nm and 900 nm are almost equal at 6.9 m−1 (attenuation length of 14.5 cm).
> These values correspond to pure absorption without scattering effects.
So, @JohnRennie, if I read it right, that means exhibiting Rayleigh scattering needs no colloidal suspension in water? (In principle?)
 
The absorption by water in the UV and IR parts of the spectra are because energy is transferred into electronic and rovibrational states of the water molecules.
But this doesn't happen across most of the visible part of the spectrum because there are no states that have transition energies in those regions.
 
Exactly !!
 
Water will Rayleigh scatter just like air Rayleigh scatters, but the scattering is weak.
Rayleigh scattering is generally a weak process.
 
So, the intensity lost in the forward direction is almost purely a scattering loss?
@JohnRennie What if you increase the path length of the sample?
 
7:14 PM
When measuring scattering by dispersions in the usual solvents the intensity loss in the forward direction is almost purely a scattering loss, yes.
 
@JohnRennie Yay.
 
If you make the path length arbitrarily big then obviously you can make the intensity loss as great as you want. But there are obvious experimental difficulties.
 
True.
 
I've kind of lost track of where we are going with all this ...
 
Our basic problem was Rayleigh and Mie scattering.
We are done with one.
R needs no colloidal suspensions in water (in principle).
But of course, any solute in water which can also add to R, shall amplify the effects.
Am I right?
 
7:19 PM
solute? That normally means a small molecule.
Like salt or sugar.
 
$d < < \lambda$
wink, wink.
 
Small molecules will have very little effect. After all salt solutions are still clear.
The sorts of dispersions I used to play with had silica particles in the 50-100nm range
 
No, but if I'm getting this right, the identity of the small scatterer is irrelevant.
Isn't it?
 
Provided the scattering centre is small enough the angular distribution of the scattering is independent of exactly what the scattering is being caused by. However the intensity of the scattering can be very dependent on what is doing the scattering.
 
So, isn't it small enough with salt and sugar?
 
7:24 PM
Because different scattering centres interact with light in different ways. A sugar molecule is different to a 50nm colloidal silica particle.
 
The yardstick is comparison with $\lambda$, ain't it?
@JohnRennie Ahh. You mean, in shape?
 
@TheDarkSide no, both are basically spherical.
But the 50nm silica particle creates a far larger refractive index change
If you look at the equation for the scattering intensity then there's a fudge factor $\alpha$ that is the polarisibility of whatever is doing the scattering.
 
Yes. You are right.
 
This will be different for different scattering centres. It doesn't change the angular distribution of the scattering but it does affect the overall scattering intensity.
Anyhow, I have to be at work in 8.5 hours so I need to clock off and start getting ready for bed.
 
@JohnRennie the magical restart fixed it
 
7:30 PM
@0celo7 Turn it off and turn it on again. It really does fix most problems :-)
 
@JohnRennie Just one last question before you leave.
 
@TheDarkSide Yes?
 
If we drop silica 50 nm particles into water, I hope there isn't any chemical reaction involved !! Also, how about fine mud particles?
Instead of well fabricated silica particles?
 
Fine mud particles are far too large.
 
So, they make the cut for Mie at least?
:P
 
7:32 PM
Mud will be mostly crystals of clays like bentonite or montmorillonite and those are upwards of a micon in size.
They are probably too big for Mie scattering, and they'll have a huge range of sizes.
 
Hmmm ... Yes.
Silica gel adsorbs water. But otherwise, Silica + water is OK?
 
You can't buy dry 50nm silica particles. Ludox comes as a dispersion in water. Typically 20% solids I think. There's no reaction if you dilute this with extra water.
 
Ohh. Great!
 
Silica gel is completely different and won't give you a dispersion when you add it to water.
Making these silica dispersions is quite a complicated business.
I think Ludox is mildly alkaline, but apart from that you could bathe in it if you felt so inclined. It's very safe stuff. There will be a safety data sheet on the Grace web site.
Anyway, I'm off. I'll be around tomorrow if you want to chat further.
 
Alright. Thanks a lot @JohnRennie for this detailed discussion.
(When you see this tomorrow)
 
7:41 PM
@Secret Eh? Even seen video of ape or monkey societies?
They have all the same social $#!? that you experienced in high school, only with more body hair.
 
Hello @dmckee
 
Really? I always thought those are more basic fight for dominance type fights or social class things
 
@Abcd For as long as the lift continues to accelerate downwards at $7 m/s^2$, the acceleration of the ball relative to the lift will be $g - 7 m/s^2$. Is that what you're asking?
So? What did you want to know?
 
@DawoodibnKareem Yes.
@DawoodibnKareem Why g-7?
 
7:57 PM
What else would it be?
You could try differentiating (twice) the difference between the amount the ball moves and the amount the lift moves.
$(\int\int g) - (\int\int 7) =\int\int(g-7)$
 
Use \iint for double integrals
 
Thanks, I'd forgotten that one. Can't be bothered editing it though - my meaning is clear.
 
@DawoodibnKareem ok, ty
 
8:23 PM
guys, we've upstaged Wikipedia
4
user image
5
 
@JaimeGallego or just don't use double integrals
There's literally no reason
 
@EmilioPisanty this is a monumental day
 
8:56 PM
So...
Yesterday I was a volunteer for a astronomy local fair visited by many kids. We used tornardoes in water bottles to depict black holes, saying that rotating black holes are basically whirlpools in spacetime and deep wells that light cannot escape. did I comitted a GR crime for being too inaccurate?
If yes, what's a better way to educate 4-7 yr old kids about black holes as simple but as accurate as possible?
 
imho that is too young
 
well one of the boys did ask how does tornardo water bottles related to astronomy concepts, and the answer I gave is the above, so I am guessing they might be smart enough to understand basic level physics
 
@EmilioPisanty The only blemish there is that it's very prominently tagged ...
 
How is that a "blemish?"
 
@Secret I personally don't think 4-7 year old kids need "educating" about black holes at all. It's fine to just tell them a nice story, that's why it's called a lie-to-children
@LasVegasRaiders Because a) that's the single most controversial tag we have and b) it might yield the impression that "homework and exercises" is something physics.SE is for to casual googlers. I'm not sure I'd have clicked on a result that ostensibly was about homework/exercises back when I found this site.
 
9:12 PM
@Secret Monkey B gets beat up by monkey A for some minor transgression. After a short sulk B goes looking for a more junior monkey and on finding C beats him out of the blue.
Hard to find something more along the line of 'just because I can' than that.
 
classic bullying prorogation dynamics down the hierarchy, ok I think I agree that it is either beaten or being beaten world (to paraphase undertale)
you do it because your opponent is weaker and you have the ability to do so
In other words, pretty much what you said. In that case, I suspect "pointless bullying" may exist in other animals as well, though I am not sure. It will be quite intriguing if it is only restricted to mammals
Actually an interesting question to ask: Are there scenarios where B beats C without being beaten beforehand? that might rule out the simple reason of retalitation by projecting to something weaker as an explanation
 
@ACuriousMind yeah, I know
I'm increasingly less convinced that we need the tag at all
57
A: Can experts identify the model using this part (FOD prevention purposes)?

minsThe device is an old “B.I.C” It can't be said for sure, because there is no marking visible. Still images like this can be found on the externet, Here a very similar one: What is the meaning of “B.I.C” and what is the purpose is another story, this is never explained, and it seems impossibl...

↑ man, is that an instant classic
 
10:22 PM
@EmilioPisanty I didn't think SE allowed jocular answers
 
@0celo7 Why is that so? My multivariable calc knowledge is nil, but I can see the point of double integrals.
 
10:40 PM
@JaimeGallego just don't write two integrals
You never see that in the analysis literature
Write dA if you have to emphasize
 

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