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4:24 AM
@Gasterbiter thanks that's very helpful!
@DenisNardin thanks! I've been thinking about it some more... I think I maybe have some moderately sensible things to say, but I felt like I'd already sent you enough e-mails
 
4:41 AM
@skd hm yeah, this "propagating module" and "universal descent morphism" stuff is very interesting...
And yes, as @Gasterbiter says, it may be possible to re-do d 5.6.6, but that's rather too strong. that's showing that the map is an effective descent morphism (if I understand correctly) but in many cases we have effective universal descent morphisms which are not effective (for the module stack at least), again if I'm understanding correctly.
For instance $S\to MU$ or $S\to X(n)$.
Hm actually, I'm not sure I'm understanding what a "universal descent morphism" is...
Yeah I'm trying to piece things together here... and it looks like he's saying that if the unit map $u:A\to B$ induces an equivalence between $A$ and the limit of the Amitsur complex then... $LMod_A$ is equivalent to the category of $B$-modules equipped with descent data? I.e. this map is an effective descent map?
But how is that possible? For instance it seems to me that $S$ is equivalent to the limit of the Amitsur complex for the map $S\to MU$, but $S\to MU$ is not an effective descent morphism..... is it??
 
skd
5:14 AM
@JonathanBeardsley asking that the Tot-tower of the cobar complex is constant as a pro-object is stronger than asking that the limit of the cobar complex is A
the latter is saying that A is B-complete, while the former is saying, e.g., that the associated bousfield-kan spectral sequence has a horizontal vanishing line at a finite page
 
@skd ah i see, okay. yeah i noticed that it was being asked for that to be an equivalence of pro-objects, rather than just of limits, and was worried I was missing something.
 
skd
so S -> MU is not a universal descent morphism
 
Okay good, that's a relief!
Thanks for clarifying that. :0)
I mean to do a regular smiley, like :-), but I kinda like the one with the big nose.
 
skd
(but, e.g., the map L_n S -> E(n) is a universal descent morphism; this is the smashing localization thm)
haha
what's up @ReubenStern
 
@skd Right. Isn't there some well known counter-example though that shows that not every Galois extension (in the sense of Rognes) is a universal descent morphism?
 
skd
5:20 AM
idk if it's well known but this document gives an example folk.uio.no/rognes/papers/unfaithful.pdf
faithfulness of a galois extension is necessary (and sufficient) for the galois extension to be a universal descent morphism
btw i think some of this stuff is in arxiv.org/abs/1404.2156 but i haven't read it
 
 
4 hours later…
8:59 AM
@skd What does "$B$-complete" mean in this context? Is this a bousfield localization sort of term? I only know about local objects and acyclic objects, what does "complete" mean?
 
 
4 hours later…
1:20 PM
@skd I think "$B$-complete" is supposed to mean in the sense of "nilpotent $B$-completion", i.e., the inverse limit of the Adams tower.
 
skd
yeah, that's what I meant. @CharlesRezk I think you meant to tag @SaalHardali
it's related to bousfield localization; in many cases the B-completion will be bousfield localization wrt B
 
the monoid axiom on cofibrantly generated symmetric monoidal model categories C provides its category of monoids with a model structure created in C. is it a monoidal model category?
 
2:08 PM
@skd If S--->B is a n E_infty algebra is the statement that B-localization is smashing equivalent to the map being a universal descent morphism?
Or did you mean that the implication is only in one way
 
skd
yes, if the map L_B S -> B is a universal descent morphism if B-localization is smashing
idk how to edit this on my phone, but in order for that sentence to parse you should remove the first "if"
 
@skd for future reference, menu button in the bottom left ~> edit last. you can't edit anything other than your most recent message without going to the desktop site
 
skd
ugh sorry the implication is "L_B S -> B is universal descent" => "B-localization is smashing"
ah I see thanks
there's no menu on the bottom left
the idea is that pro-constancy allows you to move smash products past the Tot (which is a limit)
 
@skd oh i see, they redesigned the chat a couple years ago and i opted out so i'm probably seeing something different. my bad.
 
skd
oh well. thanks anyway
 
2:22 PM
Ah, in the new one you click on a message and it pops up the things you can do with it up top, including a pencil icon for messages in the past two minutes. That seems convenient. Maybe I should stop opting out
Sorry to keep interrupting the actual homotopy theory
 
skd
oh I see, that's good to know
actually I'm pretty sure that B-localization being smashing is equiv. to L-B S -> B being a universal descent morphism
 
there is a time limit on the ability to edit. also often mobile interfaces are different and more limited
 
 
4 hours later…
6:44 PM
to reply to my previous question: not necessarily mathoverflow.net/a/195194/6249 (and I knew it a year and a half ago!)
an interesting thought is that, unless I'm making a very silly mistake, if the commutative monoids have a model structure, then it is monoidal model, because the pushout-product map is an isomorphism (by a "pushouts commute with pushouts" argument and the fact that pushouts in commutative monoids are relative tensor products)
 
 
3 hours later…
10:11 PM
ohhhhh jeeez : kerodon.net
7
 

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