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3:15 PM
how to find the longest run of 1s in a boolean array?
so 1 0 1 1 1 0 will give 3
 
3:30 PM
ok i think i came up with something
ngn/k, 15 bytes: 1++/{x=y+1}':&:
idk if that works for every case
 
 
2 hours later…

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