I am attempting to solve the integral of the following... $$\int_{0}^{2 \pi}\int_{0}^{\infty}e^{-r^2}rdr\Theta $$ So I do the following step... $$=2 \pi\int_{0}^{\infty}e^{-r^2}rdr$$ but then the next step is to substitute $s = -r^2$ which results in... $$=2 \pi\int_{- \infty}^{0}\frac{1}{2}...