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7:26 AM
Hello
That cube root thing is trivial :(
Just divide everything by $5^{1/6}$ to see why
 
 
2 hours later…
9:47 AM
@Mathphile (n!)^n+1 is prime for n = 0,1,2,4 with search limit n = 147. Is there another prime of this form ?
(n!)^n-1 is prime for n = 2 with search limit n = 100. Same question
 
 
8 hours later…
5:56 PM
The eigenspace of A and A^k would be same right?
Because the same set of x's satisfying Ax = lambda x will satisfy A^x = lambda^k x
Could someone please verify?
Hi guys!
 
Who can find a factor of ( 512! ) ^ 512 + 1 ? Hint : We only need to check the primes of the form 1024k + 1. Nevertheless, I have not found a factor yet.
@Archer Aren't nilpotent matrices a counterexample ?
 
6:12 PM
@Peter oh yeah
 
 
3 hours later…
9:13 PM
Sorry guys I'm a bit busy. I have school things due and I can't fail
I might have to stop doing math for a bit because I'm falling majorly behind :/
At least when I get back on track, I'll be focusing on a new thing other than nested radicals, continued fractions and other quirky math: integrals :)
 

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