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3:19 PM
@Frank Hubeny - regarding the question re. diagonalization... in reply to your last comment: the even and odd natural numbers are in 1-1 correspondence yet neither set contains a single element of the other....and you do not destroy the correspondence by listing more elements for either set
 
3:37 PM
@21stCenturyParadox I am glad to see you can now enter these chat rooms. I did open another up for this question: chat.stackexchange.com/rooms/84742/… I will be back later in the day. One quick answer. With the even/odd set up there was no way to tell if the enumeration was hidden in B or not. With the new bijection to R we can.
 
OK... I'll move over to that room. I will have to reply later as I need to get to work here at home.
 

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