JEE Maths Zone - 2023-05-27 (page 3 of 3)

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Rajdeep Sindhu

4:00 PM

I was gonna say that but I already rejected her so

RR.

@Wolgwang That is possible... But, I'm not marrying or dating u

Soulmate=BFF

Rajdeep Sindhu

@RR. I also met a guy on reddit once who was so so so so so so so so so similar to me, like so so so so so similar. we were from the same state, birthday one day apart, and a lot

Wolgwang

@RR. This was #63666000 message congrats.

Rajdeep Sindhu

@RR. I already have one 🤷🏻‍♂️

RR.

@RajdeepSindhu Now that is creepy

Wolgwang

4:01 PM

@RR. You live in mountains, right?

(Your avatar)

RR.

@RajdeepSindhu I didn't say u were my BFF cause I have one

Rajdeep Sindhu

@RR. I NEVER SAID YOU DIID 🤷🏻‍♂️

Wolgwang

What is BFF?

RR.

@Wolgwang That's just a random pic off google

Rajdeep Sindhu

@Wolgwang I wanna live in a log cabin up in the mountains in solitude when I grow up, btw

RR.

4:02 PM

@Wolgwang Best friend foever

Rajdeep Sindhu

@Wolgwang Best friend forever

(the forever part is almost always false)

RR.

So true

Rajdeep Sindhu

(Statistically speaking 🤓)

Anyway so what was the cypher in the program?

RR.

Has happened already... I found a bff... that one didn't work out so found a new one

Rajdeep Sindhu

@RR. I found a bff but things got complicated but we're still bffs

Wolgwang

4:03 PM

Who?

Rajdeep Sindhu

@Wolgwang Samriddhi bruh

Wolgwang

Rajdeep Sindhu

Arjun's a great bff tho, Mayank boi too

Wolgwang

Explain me

I DIDNT GET

Rajdeep Sindhu

@Wolgwang No, I won't, what're you gonna do about it 😼

Wolgwang

4:04 PM

@RajdeepSindhu Heh it got complicated. Elaborate.

Rajdeep Sindhu

@Wolgwang No.

I didn't like her and she didn't like me either, if you were expecting any of that

Wolgwang

@RajdeepSindhu Uhm I cant do anything sire

RR.

@RajdeepSindhu Caesar and substitution

Rajdeep Sindhu

@Wolgwang How many ways are there in which we can go from (1,1) to (5,5) in 8 steps?

@RR. Goddamn that's basic af

RR.

@RajdeepSindhu Ahhh

Rajdeep Sindhu

4:06 PM

I once made a cypher that shifted the first letter by 3 places, second by 1, third by 4, fourth by 1, etc...so according to the digits of pi

Wolgwang

Caesar. LMAO

Rajdeep Sindhu

Btw

RR.

@RajdeepSindhu I told u it was basic

Wolgwang

@RajdeepSindhu The pi program

Rajdeep Sindhu

3.14159265358979323846264338327950288

I forgot the next 15

@Wolgwang True true

Wolgwang

4:07 PM

Its ok

RR.

Always flexing 🤦‍♀️

Rajdeep Sindhu

Now I'll pack a bit

@RR. Reminds me, I gotta send mayank a pic of mah biceps uwu

@Wolgwang Check discord

Wolgwang

@RajdeepSindhu Ok. Safe journey.

@RajdeepSindhu Like really?

@RR. What have you done?

RR.

@Wolgwang Meaning?

Ohhh... u get bisep pics

Wolgwang

NVM

Hmm

RR.

4:08 PM

Enjoy them

Rajdeep Sindhu

@Wolgwang Really, I'm looking for it 🤨

@Wolgwang Thank you!

RR.

Safe Journey... (again)

Rajdeep Sindhu

Ty ty!

Wolgwang

@RajdeepSindhu Nothing

RR.

I'm gonna go grab dinner! Byeeeee

Rajdeep Sindhu

4:10 PM

@Wolgwang Now

I gtg now guys, I'll see you guys tomorrow

Wolgwang

13 mins ago, by Rajdeep Sindhu

@Wolgwang How many ways are there in which we can go from (1,1) to (5,5) in 8 steps?

Why (5,5) ?

And what coordinate system are you using (1,1) is left most and downmost right?

So If I break ths process into steps.

One will have to take 7 Up steps and 4 right steps.

So I just gotta permutate this?

330 steps.

But I have to subtract the steps in which I am going out from the grid. (Example, RRRRUUU...)

Ok to subtract these, the solution has further break the process into through M and N.

Ok got it.

1 hour ago, by Rajdeep Sindhu

$f:[0,1]\to\Bbb R$ is a continuous function such that $f(1-x) = \dfrac1{f(x)}$ for all $x\in[0,1]$. The possible values of $\displaystyle\int_0^1 f(x)\mathrm dx$ are :
a) $\pi$
b) $\dfrac7{22}$
c) $e$
d) $\dfrac 1e$

Interesting

First instinct, 👑 property

Urghhh

Gimme hint

Wolgwang

4:51 PM

If I set $$f(x)=1-\dfrac{1}{x}$$

NVm

Wolgwang

5:07 PM

$$I=\displaystyle\int_0^1 f(x)\mathrm dx\\I=\displaystyle\int_0^1 \dfrac1{f(x)}\mathrm dx\\2I=\displaystyle\int_0^1 f(x)+ \dfrac1{f(x)}\mathrm dx\ge \displaystyle\int_0^12=2\\I\ge1$$

A,C?

Wolgwang

5:22 PM

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