When we use the formula to caculate two-qubit's entanglement,like these:
Why we use complex conjugate of density matrix but not its Complex Conjugate Transpose?
Hi, I believe I owe a public apology for all those who voted for me. My moderator status was recently revoked because of my not-so-nice activities on a previously deleted(/suspended) account which was now discovered by the CMs. This incident was a few years back and I didn't think it'd affect me in the future (I was wrong); I was young and foolish then but I do hope I'm a better person now.
Anonymous
Nevertheless, I will try to continue as a good contributer here. I wouldn't want to lose all the friends I've made here.
Well that's.. Unexpected. I'm not sure I should ask for details on the matter, so keeping it on a practical level, how does it work now moderation-wise?
Suppose i have an initial state $|A\rangle=\dfrac{1}{2^{3l/2}}\sum_{x=0}^{2^l-1}\sum_{y=0}^{2^l-1}\sum_{z=0}^{2^l-1} |x\rangle^{\otimes l}|y\rangle^{\otimes l}|z\rangle^{\otimes l}|0\rangle^{\otimes l}|0\rangle^{\otimes l}|0\rangle^{\otimes l}$
Now this state is an equal superposition of all st...
I am trying to implement https://arxiv.org/abs/1802.06002. I do not understand how to take the data set from MNIST and apply it to a quantum circuit.
Suppose i have an initial state $|A\rangle=\dfrac{1}{2^{3l/2}}\sum_{x=0}^{2^l-1}\sum_{y=0}^{2^l-1}\sum_{z=0}^{2^l-1} |x\rangle^{\otimes l}|y\rangle^{\otimes l}|z\rangle^{\otimes l}|0\rangle^{\otimes l}|0\rangle^{\otimes l}|0\rangle^{\otimes l}$
Now this state is an equal superposition of all st...
