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Anonymous
5:04 PM
@Tanuj There's a chat room named "The Periodic Table" on Chemistry SE.
 
Anonymous
Also, I'm a bit busy now. Not sure I can help you. You can ask nevertheless and hope someone comes by
 
"The matter couplings of chiral multiplets are **conveniently** described in the language of Kahler geometry"
...
 
5:23 PM
@Blue Yes, all products of groups exist (and "are groups", but in some definitions that's already included in saying they exist) whether finite or infinite. Their order is completely irrelevant for the notion of the direct product.
 
@Tanuj you mean you have a question?
 
And indeed taking the direct product of some A as often as the cardinality of some other B is isomorphic to the maps from B to A, which is why you can find $A^B$ as notation for all maps $B\to A $.
 
Anonymous
@ACuriousMind Woah, that's a good point
 
Anonymous
It's a pity that my Algebra textbooks - Gallian and Artin don't go into much depth when discussing direct products
 
@Blue Exercise: the power set is $2^X$, where $2=\{0,1\}$
 
Anonymous
5:33 PM
@0celo7 I don't understand the notation $2=\{0,1\}$
 
It's a good notation.
 
Anonymous
I mean I don't know what it means
 
Anonymous
Are you labelling the set as 2 ?
 
Yes
 
it's a generic set with two elements
 
5:34 PM
It's in accordance with the PA definition of natural numbers, or ZFC thereof
 
but as Balarka says, in PA you define numbers as sets
and 2 is the set with 0 and 1
 
Anonymous
Ok, and what do I have to find? Power set of 2 ?
 
power set of $X$
 
Anonymous
What is $X$ ?
 
any set
 
5:36 PM
Any set
 
@BalarkaSen do you gork the layer cake representation
 
idk what it is
 
gork?
 
grok
I think it's actually super trivial but the proofs people give are all quite complicated
 
5:53 PM
@blue @JohnRennie are you guys avaialable? I just need 10 minutes of yours.
 
@Tanuj JR is not available when he is offline.
 
Turns out Kahler manifolds are easier than Riemannian ones on a basic level
 
@DrSatan1 @0celo7 On it
 
6:22 PM
So if we take the empty set to be a Lorentzian manifold
What is its causal structure
I mean, it's true that $\forall p \in \varnothing, p \ll p$
Is the empty set a Lorentzian manifold
It's a $4$-manifold
With the coordinate chart $(\varnothing, \varnothing)$
Mapping to the subset $\varnothing \subset \Bbb R^4$
 
It admits a Lorentzian metric vacuously
 
It has the vector bundle $\pi : \varnothing \to \varnothing$, with the local trivialization $\psi = \varnothing$
I wonder if everything works vacuously or if, at some point, you encounter an obstacle
Maybe I should make it a PSE question for fun
 
Anonymous
@0celo7 I didn't write it down formally. But here's the idea: Let $S$ be the set of functions from the set $X$ to $\{0,1\}$. Say we have a set $X=\{a,b\}$. The possible functions are $f_1(a)=0,f_1(b)=0$, $f_2(a)=0, f_2(b)=1$, $f_3(a)=1, f_3(b)=0$ and $f_4(a)=1, f_4(b)=1$. I can always make an one-one onto correspondence between these functions and the elements of power set of $X$.
 
Anonymous
For example, here the function $f_1$ can be mapped to the element $\{\}$ of the power set, $f_2$ to $\{b\}$, $f_3$ to $\{a\}$ and $f_4$ to $\{a,b\}$.
 
Hm
 
6:37 PM
@Blue that's the idea
a formal proof goes along these lines
 
If $Y$ is a subset of $X$, define $f : X \to \{0, 1\}$ as $f(x) = 1$ if $x \in Y$ and $f(x) = 0$ otherwise.
This is a bijection (check)
 
If $A\in \mathcal P(X)$, then define $f_A\in 2^X$ by $f(x)=1$ if $x\in A$, and $f(x)=0$ if not
 
Anonymous
Uh, yeah. Gotcha
 
For the other way, assign to $f\in 2^X$ the set $A_f=\{x\in X:f(x)=1\}$
 
Boo
 
6:46 PM
@CooperCape oh, you're a Klansman?
 
Ahh yes I am very pleased it's another burn tonight :)))))
 
@ACuriousMind ^ my god
 
Although once I did make a cross out of two splints and burn it in a chem class
I mean if I can't convince you away from it I may as well be so outrageous that you refuse to mention anything near it it again.
 
did you also sing violent black metal while doing it
 
@CooperCape you have completely misjudged me if you think that's a valid stategy
 
6:48 PM
Ehh I'm trying a few methods
Apparently "Hey ocelo I am not racist" doesn't work either so like whatevs
 
you've been banned multiple times for racism
 
Once, I called you a whatsit. The next time I joked and said "I can't even call you a wotsit"
wow I have no continuity
 
turns out I am jewish
 
Oy vey
 
Anonymous
@0celo7 I thought most Ungers are Germans...
 
6:50 PM
@0celo7 Were you offended by it?
 
I have been banned for saying something unintentionally racist and I think it's well-deserved.
 
Anonymous
There could have been inter-mixing though
 
@Blue Germans can't be Jewish?
 
German jews disappeared a lot in the 40's
 
I didn't think getting banned for what I said wasn't well-deserved. I think this is 6 months later and ocelos suggesting I am a member of the kkk for it.
 
6:51 PM
Not sure why
 
@0celo7 According to you know whom
 
@Slereah holocaust denial is probably the worst thing to do in this chat
 
Anonymous
@0celo7 I mean that's quite rare. And you know why
 
I ain't denying no holocaust
 
@Blue No, I don't know why. There's lots of Jews in Germany.
Hitler didn't get all of them
 
6:53 PM
It's not rare I do not think.
 
How has this discussion started from me saying 'boo'
like for real
 
hey @JohnRennie is there a better dupe for this one? physics.stackexchange.com/questions/384139/…
 
Anonymous
@BalarkaSen That's a double negative :P
 
@BalarkaSen We've established Blue's ignorance of Western society often enough
 
@Blue A missing comma, not a double negative
 
6:54 PM
@Blue My great-great (great?) grandfather was an orphaned Jew who was adopted by Germans
and my great-grandfather came to America before WW1
 
You want a sticker/
 
Anonymous
@0celo7 Well, I'm at least learning new things from you guys. I already admitted long ago that my knowledge of Western history is quite shallow (mostly because of my hate for history classes during school :p)
 
Oooh how about a sta... w..waaa...wait.
 
you want me to put a Jude patch on my arm?
@ACuriousMind I'm triggered
 
According to wikipedia the core Jewish population in Germany is 0.9% of the total population
Not bad
It's less than Russia though
Which is 1.4%
Soviet Russia also gave Jews a hell of a hard time though (this sentence is not correlated with the data I wrote above)
 
6:57 PM
I swear 50% of the time I'm here a discussion on some kind of 20th century history involving some sort of genocide takes place.
 
Talking about something is not necessarily a bad thing.
 
@CooperCape wonder why, david duke
 
@BalarkaSen Yeah well it's how it begins is the issue
 
How it begins is how people get freaked out about conversations like you're being now
 
@BalarkaSen scroll up bb
 
6:59 PM
@BalarkaSen ok measure theory time
@Blue
 
Anonymous
@0celo7 ?
 
Let $f$ be a nonnegative measurable function on some measure space (doesn't matter which)
 
Anonymous
I solving weird circuits now
 
Define $\mu_f(t)=\mu\{x\in X:f(x)>t\}$
the distribution function of $f$
 
okie
 
7:01 PM
uh hold on
@BalarkaSen I'm trying to write a proof of something tautological that has taken me hours to think about correctly
I'm trying to make it more clear but don't know if I can
 
Write it up once you get it; I'll have a look once I wake up
Going to sleep now
 
I do get it, I just don't know how to write it down
 
Gotcha
 
In mathematics, the layer cake representation of a non-negative, real-valued measurable function f defined on n-dimensional Euclidean space R n {\displaystyle \mathbb {R} ^{n}} is the formula f ( x ) = ∫ 0 ∞ 1 L ( f , t ) ...
read this before you sleep
 
Anonymous
@BalarkaSen Unusually early for you. Guess you are awake for >24 hrs?
 
7:07 PM
wonder if Reed and Simon have a picture I can emulate
@BalarkaSen the layer cake formula is really trivial
it just says that if $f$ is nonnegative, one can obtain $f(x)$ by going to $0$ above $x$ and then going up to the graph
like, completely tautological
but very useful
 
 
1 hour later…
8:15 PM
The dow, thanks Trump
 
 
1 hour later…
 
1 hour later…
10:17 PM
proof that ZFC is incorrect i.redditmedia.com/…
@BernardoMeurer please evaluate
 
10:44 PM
@dmckee
2
Q: Looking for cause of unexpected preemption in linux kernel module

EvanI have a small linux kernel module that is a prototype for a device driver for hardware that doesn't exist yet. The code needs to do a short bit of computation as fast as possible from beginning to end, with a duration that is a few microseconds. I am trying to measure this with the intel rdtsc...

 
11:08 PM
@JohnRennie thanks for the reply about my photoelectric effect question :)
 
@Slereah I think the Italians win when it comes to Sobolev inequalities
the french guy does some insane Morse theory argument that saves him a few instances of "almost everywhere" down the line
 
11:45 PM
@ACuriousMind I made a reference to TW3 in the math room and was told to not make obscure video game references there :'(
 
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