@0celouvskyopoulo7 Anyways, I don't think so: the initial topology $\mathfrak{T}_{\lVert \cdot\rVert}$ on a Banach space is finer than the weak topology $\sigma(X,X')$, and therefore $f\in C((X,\mathfrak{T}_{\lVert \cdot\rVert}),T)$ may very well be discontinuous in $(X,\sigma(X,X'))$, and almost surely not even semicontinuous.
I understand Partitions, just imposing restrictions like "r = some constant" in a space with co-ordinates $(r,\theta)$, and then you're left with different sets of points for different r that, if Union'ed, give you the whole space.
But I still don't understand Equivalence relations
@Slereah Here's the problem. Let $M^n$ be a compact $\partial$-manifold, $1\le p<\infty$ and $f\in C_c^\infty(M)$ (that is, $f|_{\partial M}=0$). Is there a constant $C>0$, independent of $f$, such that $$\int |f|^p\le C \int |\nabla f|^p?$$
He confirms that the star operator is indeed a relation and that $A \star B \neq A$ means indeed $A \star B$ and $B \neq A$
He also adds "Anyway, I would discourage you from wasting you time on reading this part of the paper. All worthy was extracred from it, reformulated, clarified, and published in arxiv.org/abs/1408.6813 "
My favorite sentence in a Davis document : "Puthoff’s polarizable vacuum general relativity model is the only alternative theory of gravity that has been successfully applied to explain the physical, anti-physical and physiological characteristics & performances of UFOs"
@Koolman Binding energy can be a bit confusing. Remember that the binding energy is the energy released when the nucleus is formed. That it, if we take a proton and a neutron and bind them together to make a deuteron then it releases 1MeV per nucleon.
The binding energy conventions so regularly confuses people that it should could with big, neon, blinking warning-sign that says "You're not going to like this, but stick with it and do it our way."
@Koolman Imagine taking the deuteron and lithium nucleus and splitting them up into individual protons and neutrons. To split up the deuteron takes 1 x 2 = 2MeV i.e. we have to put in 2MeV.
Can anyone please just help me with one thing? Would the equivalence class that describes the partition $D$ of a space, where $D$ is the set of all circles, be $E = [x,y \subset AxA \vert \text{x and y are the same distance from the origin}]$
@JohnRennie I'm teaching thermal physics this semester and the parts I am most successful at teaching seem to be the bits that made me cry in the misty days of yore. The few bits that came easily have been the ones I've struggled to convey clearly.
user228700
@JohnRennie :-) Nice! Do tell me what u buy and all.
