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4:40 AM
@naturallyInconsistent Which books are you talking about? All book I know about just establishes a derivation of the wave equation from taking the continuum limit of an infinite chain of harmonic oscillators. I was specifically asking for the mass term. I already understood all the sentences you wrote apart from the last one.
@naturallyInconsistent I need some details on the last sentence. So do you mean to say that we add a $\frac{1}{2} m_i^2 x_j^2$ to the Lagrangian in addition to the $\frac{1}{2} k (\x_j -x_j+1)^2$ like terms or something?
 
1 hour later…
5:55 AM
@Sanjana yes
It needs to be the same m for all of them, though
 
2 hours later…
7:45 AM
@Mithoron Dak'kon's a bit of a stiff
 
1 hour later…
9:02 AM
hi
 
2 hours later…
11:29 AM
Realizing that "exact functor" means both preserving limits and exact sequences
Are exact sequences just limits of the form $\bullet \to \bullet \to \ldots$
11:40 AM
@Slereah No, but the two definitions (preserving limits and colimits or preserving exact sequences) are equivalent in abelian categories, se ee.g. nLab
11:57 AM
hi
i want to understand some sections of this answer https://physics.stackexchange.com/a/14944
the sections : "what finitary means", "ordinal religion", "ordinal analysis" and "other interpretations"
> Given a sequence of ordinals which approaches the Church-Kleene ordinal, the theories corresponding to this ordinal will prove every theorem of Arithmetic, including the consistency of arbitrarily strong consistent theories.
later on :
> To go further requires an advance in our systems of ordinal notation, but there is no limitation of principle to establishing the consistency of set theories as strong as ZF by computable ordinals which can be comprehended.

Doing so would complete Hilbert's program--- it would removes any need for an ontology of infinite sets in doing mathematics. You can disbelieve in the set of all real numbers, and still accept the consistency of ZF, or of inaccessible cardinals (using a bigger ordinal), and so on up the chain of theories.
what does this stuff mean? I know that the consistency of a theory can be proved by a bigger theory, but then the consistency of the bigger theory is in question
is this stuff expressing the same idea
@RyderRude Ron has deeply idiosyncratic opinions about history and philosophy of science and mathematics, and in particular about the foundations of mathematics (see also the MO thread linked in the comment), most of this is not a presentation of mainstream thought. I would not suggest taking it at face value.
@ACuriousMind yes. Thats why i was asking. I found this other post discussing it mathoverflow.net/q/432470
apprently, this is not the "trivial" idea i was talking about.
It is a somewhat deeper theorem
But Ron somewhat overstates its importance. It is debatable if this idea makes things like consistency of Peano provable or more believable than it already was
Ron has an obscurantist writing style - in particular his reluctance to provide specific references for any claims - that makes actually assessing the content of his longer answers on these soft topics at lot of work; I've usually not found it worth the effort since he mixes facts and his own opinion so liberally you have to double-check every sentence against other sources.
He has given some links, but not enough. But yes, his writing style is unique and can be annoying because he brings things out of the blue
12:14 PM
You also have to be careful with Wiki links he provides, since he was also an active Wikipedia editor and these can be his own work, i.e. not actually a reference
oh
i will be careful. in this particular case, the math site says these ideas are standard but their importance is overblown
also, this stuff may mean that the Hilbert program is not dead because of Godel's theorem. But that depends on how crucial these new results are
@Amit The "completely unrelated Latin text" you flagged was the source text of Lorem Ipsum, by the way, i.e. it's not random Latin but the one Latin text you post when you just want nonsense content.
this is not a new result. It was published in 1940s en.m.wikipedia.org/wiki/Gentzen%27s_consistency_proof
its relation to Godel's theorem is discussed in the article
> Kleene (2009, p. 479) made the following comment in 1952 on the significance of Gentzen's result, particularly in the context of the formalist program which was initiated by Hilbert.

The original proposals of the formalists to make classical mathematics secure by a consistency proof did not contemplate that such a method as transfinite induction up to ε0 would have to be used. To what extent the Gentzen proof can be accepted as securing classical number theory in the sense of that problem formulation is in the present state of affairs a matter for individual judgement, depending on how r
this technique proves consistency of PA. But it uses transfinite induction
12:38 PM
@ACuriousMind Right, I actually did find that out but only after raising the flag :) because a bit later I noticed the title was also changed to something containing "Lorem Ipsum" and that phrase rung a bell so I googled it... :)
but it is using transfinite induction upto countable ordinals, which means it is not relying on large ordinals
i think without this technique, one would have to use a strong theory with an uncountable set, in order to prove consistency of PA
For some reason I still find it surprising every time I see someone changing a question's title. My intuition is always that titles are uneditable, perhaps because in many of the older forums it was true
12:52 PM
@Amit hi
hey ryder, wazup?
I'm learning formal logic
are u also interested in this @Amit
I once struggled a few days to understand Gödel's incompleteness theorems and afterwards I realized I don't wanna do this anymore :D
I havent gotten to that part yet. Maybe it wud get boring then
@Amit there is a rule called Modus Ponens. It is like an axiom of the meta language
Like u r writing a proof. U write axioms : 1. A 2.A---->B
and then suddenly u r able to write 3. B, even tho it wasn't an axiom
That reminds me... there was this site that let's you study this stuff by a kind of game
12:57 PM
what kind of game
Pedagogical one :)
Pedagoboxing
There is nothing that proves modus ponens, other than that it works
as in, it has produced useful math so far and is useful in everyday life too
e.g. u see cat footprints on mud, and u conclude that there must have been a cat walking on it
It's clearly an example of something that builds on our "common sense"
Formalizes it as a definition
yes
but common sense is not that trivial. I say it is non trivial empirical knowledge about the universe
we say it's trivial because we learn it early
so this is where i think math meets empiricism
math is so useful for the universe because it too is empirical at its core
I think it's just the math that developed first. Like Euclidean geometry, which makes the more "common sense" assumptions. Later we began to study all kinds of crazy structures, and today mathematicians generally speaking don't really care about empiricism do they?
1:05 PM
yes, but to this day, they r using logical deductions including modus ponens
where did they learn logical deduction? The universe
it is in the empirical phenomena
The question is whether you can build interesting mathematical structures with a different kind of logic
there r variants
but i say they r all based on empiricism
Why? You can take for example a different rule: A, A->B ==> ~B
Interesting
yes, u can do this. Then we can explore ur question
Good luck with avoiding a contradiction down the line there :) lol
1:07 PM
lol
i think u would have to re-define a lot of things. The principle of excluded middle is not safe
It is an interesting question, just how much of logic is forced once you at least accept that A and ~A is impossible. Then in the rule I suggested above, A=B can't work and you can't do it.
but then, u have just invented a game. Why would it be useful for the universe
@Amit yes
so u r keeping the excluded middle thing
@Amit this is really trippy
Yes, it is an equivalent statement
It doesn't look like the excluded middle but it is after applying De Morgan's law
yes
so u have just modified modus ponens
By seeing cat footprints on the mud, u conclude there wasn't a cat there
Then again, even saying that is relying on the existing logic axioms... is there a system where A and ~A = F is not equivalent to A or ~A = T? Dunno...
1:13 PM
@Amit yes
I think the equivalence of these may rely on modus ponens
~(A and ~A) is an axiom
Another is (A and B) <-> (~A or ~ B)
so to conclude A or ~ A, we may need modus ponens
but ofc, u can make De Morgan's law another meta rule, which doesn't rely on modus ponens
okay we do derive contradiction here
Start with (A and B) axiom 1
Another axiom is (A and B)<---> (~A or ~B)
using modified modus ponens, we prove ~(~A or ~B)
But using de Morgan as a meta rule, we prove (~A or ~B)
i think we may be able to make different logic, but we would have to modify a lot of things @Amit
intuitionistic logic says statements can be T, F or U for undetermined
but this logic isn't used in math
Yes see that's the point, I think without adding truth values or somethin like that, there is not another way to create an interesting logic system
yes. some logics go completely crazy and make the truth value a probability
That is, by only modifying the axioms, I think you will immediately run into a contradiction
1:59 PM
Hi everyone
It's been a while since I've done any physics
@DIRAC1930 have you taken a break
@DIRAC1930 hi
I'm still doing stuff tangential to physics but it's more of a mathematical problem rather than the kind of stuff we used to discuss on here
2:16 PM
nice
What have you been interested in recently?
are you doing cond matter or hep rn?
@DIRAC1930 I'm interested in formal logic rn
and philosophies of consciousness
I'm somewhere in the middle of the two
so r u doing both, or is there a field in the middle? :)
Medium energy physics lol
2:26 PM
lol
balanced energy
“Life is like riding a bicycle. To keep your balance, you must keep moving.” Albert Einstein's life advice in a letter to his son Eduard on 5 February 1930.
2:42 PM
But today we now know that to learn to ride a bike do not use the training wheels approach.
@RyderRude answered your questions about what consistency refers to, meanings of finitary and ordinal analysis in Mathematics. The rest I don't know for I am not a logician/set theorist
@Jakobian yes. I just saw
@Jakobian i thought u once mentioned that u r interested in stuff related to continuum hypothesis
That's not true. I am interested in how topology looks with or without CH
yes. your main field is algebraic topology, i think
but u once said something really cool about the continuum hypothesis which i didn't understand
Or, in general, how a given statement independent of usual set theory ZFC affects topology
2:53 PM
maybe it was related to topology
this would be part of set-theoretic topology
@RyderRude general topology
I barely know any algebraic topology
oh
I know so little about this stuff that whenever u say something complicated, i assume u expertise in it :P
@Jakobian interesting
in Mathematics, Apr 29 at 16:50, by Jakobian
@RyderRude One often finds intersections between topology and set theory and I find those very interesting, for example the existence of $P$-points in $\beta\mathbb{N}\setminus\mathbb{N}$ is equivalent to continuum hypothesis. About dimension theory, I like it because of the concept of dimension and its different interpretations and how the dimension functions interact with each other.
this was the msg. It is indeed about relation of continuum hypothesis and topology
@RyderRude Yes but CH isn't the only thing I am interested in. For another example, the existence of countably compact $T_6$ spaces which aren't compact.
@Jakobian what is countably compact
One of the definitions is that any countable cover has a finite subcover
3:02 PM
yes. I just googled it
Existence of such space can be proven if one assumes the diamond principle
See this paper by Ostaszewski
thanks
It's more that I am interested in when existence of some space with particular properties can exist, and it's not that I particularly care about which set theory axioms do I need to assume for this to be true (or false). Of course they are important, but secondary to me
It's really complicated for me rn. It mentions "Godel's axiom of constructibility"
@Jakobian so u work with non-manifold topological spaces?
I think manifold topological spaces are well captured by ZFC
oh but dependence on continuum hypothesis can show up in manifolds
because it's the continuum. I'm just guessing
I work with any topological space, but mostly I care about Tychonoff spaces
Those are precisely those spaces which have Hausdorff compactification
or equivalently, that admit a Hausdorff uniform structure... and so on
3:09 PM
oh
i tried to look up pics, but it is maybe too abstract
And this is not to say I don't work with manifolds
yeah. It's just that ur main interest are these spaces
I am interested in dimension theory as I said before, and this means I am also interested somewhat into subsets of $\mathbb{R}^n$.
Okay - theoretically those can be much uglier than manifolds, but still. Manifolds not excluded
In particular in the problem of compactifying an $n$-dimensional space so that the dimension is preserved and embeddability into Euclidean spaces gets preserved
Which should still be open
oh
do you use visualisations as study aid in this field
yes, but I assume that I don't visualize like you do
3:18 PM
yeah. Visualisation gets trained as we progress further in studying geometry
that's not what I meant
what kind of visualisation did u mean
whatever helps me to think about a given space
I'm familiar. It doesn't need to be a visualisation of a physical object
but ur field is more abstract than what I'm thinking
Hi people. I have a question. I was reading the following statement:
"The point of the thought experiment is to illustrate that any freely falling frame is locally inertial, meaning free from gravity and acceleration, if you look at it over a sufficiently small scale. "

Why do we have to add localy in here?
3:22 PM
e.g. when i think of operator algebras in QM, i have no visualisation in mind. I cant think of anything there
it is too abstract
but maybe it is a topological space, but i haven't learned those aspects of it
also, for a field, i prefer to visualise a heat map rather than a single point in an infinite dimensional manifold
sometimes there are more than one option, and some options are more natural
or rather, i don't have the option to visualise infinite dimensions lol
For infinite-dimensions it's better to try and not visualize things that much. You'll easily get confused.
At least that's my experience with the Hilbert cube
yes. Thoughts are better than visualisations there
But consider for example Niemytzki plane. This is just the normal half-plane but with different topology. So how do I visualize it? By visualizing how would sequences approach a point on the x-axis.
i haven't studied it yet..
@RyderisnotRude. Now we have two Ryder :') @RyderRude
3:37 PM
yeah..
He is your parody. Haha
they are user5019191923726126272
@RyderRude If you find their current username inappropriate, please say so - while users can in principle name themselves however they want, mods can reset usernames that are offensive or otherwise inappropriate.
@ACuriousMind thanks. I'm not too bothered by it and i am on good terms with them. They change username periodically, i think
3:43 PM
alright, just checking
thnx for the ✅
@RyderisnotRude. But pls dont troll or I'll change my mind
@RyderisnotRude. nice
@imbAF e.g. if gravitational field were uniform, then freely falling frame would be globally inertial. But in general, it can be thought of as uniform over a small region, so it is locally inertial
but if you change the region, wouldn't the field still be uniform albeit with a different value, but the value wouldn't change over time
Or is the fact that in different regions, while over time the field is uniform, the field is different in value
hence why we need to denote the locality part ?
3:52 PM
@imbAF When you're freely falling, you don't feel acceleration/gravity where you are, but stuff that's further away from you may still fall/accelerate relative to you
And that means what?
implies locality ?
that's why the "locally" is there
"locally" = where you are, not everywhere
But, if I say, that the object that is freely falling is considered in 5 different instances of different locations in space, in the presence of some gravitatinal field
In every location, if we assume that the object is small enough
the field, locally is uniform
So, in 5 different locations, the field is uniform, albeit different in values, in each case.
And over time of course
yes, when we talk about an object freely falling, we're assuming the object is small enough so that the field is uniform over the extent of the object
And that is the case, if you consider the object in two different locations in space, no?
3:57 PM
I don't know what you mean
An object has one location in space. Why would I consider two locations? I'm not sure what's going on here
If the object in position r_1 and small enough to assume uniformity of the field, then the object represents a locally intertial reference frame
If the object in position r_2 in another scenario and small enough to assume uniformity of the field, then the object represents a locally inertial reference frame
so no matter, where the object is, because of its small size, will always represent an inertial frame of reference
the fact that is inertial, from what I understand, is related, primarily with the size of the object
I mean, not necessarily - if you put it into a gravitational field that varies wildly on scales much smaller than the object, it won't
not where the object is in space
=locality
@ACuriousMind that is an understandable case. But I am assuming the case of a small enough size, where uniformity can be considered
for instance, close to a black hole most objects will eventually undergo spaghettification as they fall in, decidedly something that does not happen in "free fall", even if those objects are fine freely falling in most weaker gravitational fields
Ok I see
Btw I was reading what you linked yesterday
101
Q: How did Einstein know the speed of light was constant?

Pablo FernandezI often hear the story of how Einstein came up to the conclusion that time would slow down the faster you move, because the speed of light has to remain the same. My question is, how did Einstein know that measuring the speed of light wouldn't be affected by the speed at which you are moving. W...

And one of the replies, says:
How does maxwell equation tell you speed of light has to be constant? You would have to know the transformatiln properties in different frames of E and B. Its definitely not that simple.

And another one:
Your three points are right, but the derivation from Maxwell eqns sort of misses the point. The maths is correct, but the whole issue is the nature of "vacuum". Saying "and there you are" at the end assumes the hindsight of knowing how to interpret the role of what we now call vacuum but was thought to be aether.
While I understood the answer to the question.
I didn't think there was an issue with the proof that light speed is constant
But these two replies do say that
And I am trying to understand what are the issues that they raise
Could you help me
Is one of the problems, the fact that the person who answers, is not considering the calculation of the speed of light in different frames of reference
4:06 PM
why are you focusing on the short comments when there's a comment by dmckee that actually explains the issue? :P
This doesn't really address the question because classical physics is full of waves whose wave equation you can derive to find a speed that depends only on constants (albeit constant properties of matter). And the speed of those waves did depend on the motion of the observer because they were only correct relative the medium. This is the reason that many 19th century physicist pre-supposed the existence of a medium for light. — dmckee --- ex-moderator kitten Jul 2, 2019 at 20:31
I don't see how he explains the issue
Isn't he also saying that the derivation part
doesn't really address the question
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Hello Everyone...
How can we see spacetime transformation in SR is hyperbolic?
@123 look at the properties that the Lorentz transform obeys
@imbAF He's saying that if this proved that the speed of light was the same in all frames (rather than perhaps just suggesting it), then the wave equation for waves in water would also prove that the speed of a water wave is the same in all frames, since the speed you can compute from that equation is just a bunch of constants, too
$a^2 - b^2 = 1$
4:10 PM
it's the same point the comments you quoted are trying to get at: Just looking at the equation doesn't prove the result holds in all frames
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@Slereah Yes i have seen it. But i don't find any geometric and step by step proof of this.
I mean you can do it by hand
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@Slereah In SR geometry is euclidean flat space. But distance is hyperbolic. Is that correct?
Depends what you mean by "euclidian"
it's not Euclidian in the sense that the spacetime "distance" isn't the euclidian distance
@ACuriousMind Ok i understand that solving the equation doesn't really prove that the sspeed of light is constant, just because it can be expressed as the result of constants
this is the reason why you say this: "Just looking at the equation doesn't prove the result holds in all frames" ?
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4:13 PM
@Slereah SR is flat space like euclidean space but distance is hyperbolic. Is that correct?
Maxwell's equation was done in the context of classical physics, the assumption was very much that it was not constant
@123 sure
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@Slereah Thanks. :)
@Slereah Is there any proof in which lorentz transformation shows hyperbolic distance in minkowski spacetime?
Or proof name?
@ACuriousMind To my understanding, while the 3 bullet points are a good starting point for the idea that the speed of light might be the same in all inertial frames of reference, ultimately, Einstein, simply, assumes that
And then he performs thought experiments that validate his assumption
4:18 PM
Take the 2D case for instance, \begin{eqnarray}
t' &=& \gamma t - \beta \gamma x\\
x' &=& \gamma x - \gamma \beta t
\end{eqnarray}
If you have to assume instances in science, isn't that somehow showing lack of logic in the way we conduct it? And I am not saying Einstein lacks logic :D
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@Slereah yes
Your SR big rule is that your spacetime interval is constant under Lorentz transform, so $$t'^2 - x'^2 = \gamma^2 t^2 + \beta^2 \gamma^2 x^2 - 2 \gamma^2 \beta tx - \gamma^2 x^2 - \gamma^2 \beta^2 t^2 + 2 \gamma^2 \beta tx $$
@imbAF I don't know what you mean - how would we ever get anywhere without first making some assumptions (based preferably on what we already know) and then testing them against reality?
But I guess, one can argue, that he was provided with sufficient cases where, this assumption might have led him somewhere
4:21 PM
you can't just derive physics formally without making assumptions or doing experiments; physics is not math
But assumptions are not just randomly thought
There must be some instances that lead to it
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@Slereah why my laptop not showing LateX
Rewrite this a little, $$\gamma^2(1 - \beta^2) t^2 - \gamma^2 (1 - \beta^2) x^2 = t^2 - x^2$$
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What i need to install
So I believe in his case, the 3 bullet points are what led him to assume that
while not being certain
4:22 PM
@123 See here
40
A: Any chance of MathJax in chat?

Ilmari KaronenAs a workaround while this request is pending, there exist several client-side workarounds that can be used to enable LaTeX rendering in chat, including: ChatJax, a set of bookmarklets by robjohn to enable dynamic MathJax support in chat. Commonly used in the Mathematics chat room. An alternat...

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Pls w8 i am installing mathjax
@ACuriousMind is it ok for me to focus on the first part of the answer, and not the proof that the speed of light is the result of some constants ?
Anyway, this means that $\gamma^2 (1 - \beta^2) = 1$.
And add that, based one what the first part of the answer says, einstein took a leap of faith in saying that the speed of light should be constant
Which he then proved it, via thought experiments?
One thing you can do is replace any real number $x$ by $x = \sinh(u)$ for some number $u$, since $\sinh$ is a bijection on real numbers
4:26 PM
@imbAF thought experiments don't prove anything
real experiments prove that your theory is right
the thought experiments are just to figure out what "the speed of light is constant" as an assumption would imply, so you know what to test in the real experiments
So, what experiments were done to prove his assumption about the speed of light
Michelson Morley experiment ?
But that was prior to him saying that about the speed of light
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How to setup mathjax in chrome?
@imbAF see Wiki
If you do that to say $\gamma \beta$, that means that $(\gamma^2 - \sinh^2(u)) = 1$
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I have installed it
4:27 PM
Meaning that using that convention, you will have $\gamma^2 = \cosh(u)$
Einstein's theory comes within the context of science methodology of the era where it was in vogue to remove hypothesis that were seen as not indispensible to the theory
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Pls help me i have downloaded mathjax. How can i setup in chrome
Given the lack of results of the Michelson Morley experiment, he tried to figure out if we just couldn't do away with the speed of light having to change at all
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Ahh.. It worked
@Slereah Thanks
np
You can also show the hyperbolic nature of SR in a more visual way too, by looking at the set of points at the same spacetime interval within a lightcone
You will see that it is an actual hyperbola
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@Slereah Where is $t'$ and $x'$ in this equation
4:37 PM
@123 the invariance is that $t'^2 - x'^2 = t^2 - x^2$
$t'$ and $x'$ are expanded in the expression on the left
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@Slereah What this invariance called. Because i didn't read it.
ACM, one question:
Would it be correct to say : reference frame = observer + coordinate system?
@123 That's the invariance of the interval
it is connected to the invariance of the speed of light
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@Slereah Thanks a lot.. :)
 
1 hour later…
5:57 PM
@ACuriousMind If you remember, in a previews discussion of ours, I made a statement about the significance of the LT and the fact that two observers in two different frames of reference would use them, to experience/witness what the other experiences. And I gave the the example with the rod being at rest in the frame S, while S' moves relative to it. I said, that if the observer at S performs the LT, he will
find out what value for the length of the rod, the observer in S' measures, and he will be aware of length contraction. You agreed with my statement. But there is one thing that I missed/didn't notice. Now, if the observer in S' would perform his LT, according to what I said above, he would experience what the observer in S experiences, which means, the observer at S' would measure the proper length of the rod? Is that possiblle?
@Amit could you help me with this confusion ?
@imbAF Normally when we want to say that one observer changes inertial reference frame we say he performed a boost from frame S to frame S' for example. So if physically one observer moves to another inertial reference frame, of course he will measure the same length as another observer in this same frame. They are both now in S'.
That is true but what I am asking is the following
It becomes more a matter of semantics whether you're saying he performed the LT to find out how an observer in S' measures things or alternatively he moves to S' and this change is described by a Lorentz boost (LB - I suppose? :)) and then find out how things are measured in S' in that manner
If the observer in S, that has made his own measurement for which he as x,y,z,t uses LT, he would find the x',y',z',t' right?
You can perform measurements without taking into account any other inertial frame, thank god :)
6:08 PM
Yes but I am considering the case that you have two observers, one in S and one in S'. And both of them measure the length of the rod in their own frame
So each of them will calculate a location for each end of the rod and then find the length
l and l'
Yes...
Then, the observer in S, performs LT in order to find out what the observer in S' measures for the location of the two ends of the rod. And he find the length
What he will measure will be a length shorter than what he measures in his own frame of reference
which is the rest frame of the rod at the same time (I take S to be the rest frame of the rod)
am I correct until now?
Yep
Now, let's do the opposite, the observer in S' performs LT.
If we are consistent
with the above statement, that you agreed with
The observer in S', when performing the LT, must measure for the two ends of the rod, values, such that, when calculating the rod's length he must calculate a larger value than what he measures
right?
The opposite means the inverse of the LT you just did. So there'll be no surprise there
What? Larger than what?
6:14 PM
then the value for the length of the rod as measured by him (observer in S') directly
First of all, you say "the observer in S' performs LT" -- you mean back to S?
of course
he performs the LT, to witness what the observer in S witnesses
So yeah now the length will be "restored" to the proper length and longer by a factor $\gamma$...
so the S' observer, will witness a length extension?
This is trivial because you performed a transformation and its inverse...
6:17 PM
Ok. Yeah It is trivial
but For a moment i got very confused by the fact that the S' observer when performing LT will measure the proper length
but he doesn't know that
obviously
If the observer in S' tries to find out how the observer in S measures the length of the rod, yes, he finds out what you might call length extension. However note that this isn't a useful phrase because this is disconnected from what he phenomenologically, actually measures. You either measure the proper length when at rest wrt to the object, or you measure a contracted length when it is moving...
Of course
And to close it out
When either of them calculates the square magnitude, they calculate the proper length
irrespective of which coordinates they are using
the ones they found by direct measurement or those calculated via LT
square magnitude of what?
of the thing that gives the proper length
I don't remember what we call it
You can define a length measurement in terms of the spacetime interval, if that's what you're looking for. I suppose something like $L=|x_2(t_0)-x_1(t_0)|$ with the key point that both measurements are done at $t=t_0$. The squares really come in when you have more than one dimension :)
6:23 PM
Yes
the spacetime interval
will give us the proper length
Either observer can calculate the space time interval by using the coordinates that they directly measure, or via LTs
in both cases they'd get the proper length
No...
No, what?
It's a very specific no yeah... when you do the LT the point is that $x_2(t_0)$ and $x_1(t_0)$ will not be simultaneous, so if you use my formula in one frame it doesn't keep the same form in the other after LT
I don't understand
Perhaps I need to be more clear in what I said
If the observer in S uses x,y,z,t to find the spacetime interval, will he not get the same result that the observer S' gets, who uses x',y',z',t'?
yes, I suspected that's what you mean. If that's the case, I just wanted to note that the formula I wrote for $L$ will look different in S'. It will depend also on $t'$ and not only on $x'$.
6:31 PM
of course
LT and the inverse LT
 
1 hour later…
7:44 PM
consider the cartesian volume element $dxdydz$.
Can I think of this as a differential form $dx_1 \wedge dx_2 \wedge dx_3$? If yes, then suppose I change coordinates $x_i \mapsto y_i(x_1,x_2,x_3)$. To get the new "volume element" am I trying to solve $\wedge_i dx_i = [\text{something}]\wedge_i dy_i$?
7:57 PM
@SillyGoose It may be better if you start from the beginning, i.e. what's the context
@SillyGoose yes, it's the volume form
you're asking how the volume form transforms?
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