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12:00 AM
@IceLord : It's because what you are really calculating is $\partial_t \varphi(x, t) |_{t = 0}$
 
oh my god @slereah is that really necessary to prove
I thought it was just a tautology
 
user218912
@Slereah oh.
 
user218912
makes sense, thank you.
 
@Slereah yah so
 
@Obliv will never be a mathematician
 
12:02 AM
then this homework problem is trivial
I have to show that a $\sigma$-compact metric space is separable.
 
user218912
1 min ago, by Slereah
@Obliv will never be a mathematician
 
user218912
@Obliv high-five, physicists ftw.
 
@Icelord high-five for being sane
 
user218912
@Obliv do you play any online games by any chance?
 
user218912
because I saw someone named Obliv, wondering if that was you.
 
12:05 AM
in what? @iceL
@IceLord not as much anymore but when I do it's usually QL or osu just to unwind. how about you @iceL
 
user218912
@Obliv It's too embarrassing to reveal.
 
user218912
and no it's not club penguin or neo-pets.
 
I doubt we crossed paths maybe this name is more popular than I thought.
and my name on steam is currently a gordon ramsay reference lol.
 
there really should be a book on non-standard analysis written by a physicist
It's way too mathy
 
Any $\sigma$-compact metric space is separable.

*Proof.*
Let $(X,d)$ be sigma compact. We showed in class that any compact metric space is separable, that is has a countable dense subset. Let $\{K_i\}_{i\ge 1}$ be a countable union of compact sets whose union is $X$. Each $K_i$ has a countable dense set $D_i$ with respect to the subspace topology. Let $D=\bigcup_{i\ge 1}D_i$. This is countable since a countable union of countable sets is countable. Let $U\subset X$ be open. Then $U$ intersects at least one $K_i$, and $U\cap K_i$ is open in the subspace topology. Thus $D_i$ intersects $U$ s
Seems legit
@Obliv f^*&ing c#$!sucker?
 
12:13 AM
what is even a non-sigma compact space
The long line?
 
Yes
in fact
a Hausdorff locally Euclidean space is a topological manifold iff it is sigma compact
 
@0celo7 try "WHERE IS THE LAMB SAAAAUUUUUUUUCEEEEEE?" or something like that
 
so pick your favorite non-manifold-almost-manifold
long line works
@Slereah Aha
 
I guess the complete feather is also not sigma compact
 
uncountable union of lines
that's not second countable.
thus not a manifol
thus not sigma compact
 
12:15 AM
is it third countable
 
@0celo7 Okay, calm down. Why don't you just prove that the finite set you just made by combining the countable sets is countable in the same way you prove a normal set is countable? Like, by proving there is a bijection or something right?
 
@Obliv Are you trolling me?
I can't tell
 
@0celo7 I guess I don't have context maybe it's more difficult than you make it out to be.
oh wait no I misread. That's a proof to whatever you were doing in class not the proof of the countable union of countable sets is countable.
 
what the hell are you talking about
 
I don't know. What are YOU talking about?
 
user218912
12:21 AM
@Obliv set a profile image you look boring.
 
@iceL I kind of like this yellow. Fine, I'll do it when I get home. I have some good images on my desktop.
hey if I'm generalizing a sine wave to multiple parameters such as $r(x,y,z,t) = r_{max}\sin()$ would it look like this: $r(x,y,z,t) = r_{max}\sin(kx+ly + mz + nt)$ where $k = \frac{2\pi}{\lambda}$, $l = \frac{2\pi}{\gamma}$ and so on
 
ugh what is this?
calc 1 homework?
 
I'M JUST CURIOUS GOD @0CELO7
studying for my physics exam tomorrow on waves & thermodynamics
 
ew physics
you need to explain what "generalize a sine wave" means
 
12:37 AM
your attempts at trolling me will not work @0celo7
Hmm to pull off an all nighter or to not pull off an all nighter.. that is the question
Hmm why isn't the kinetic energy in a transverse wave $\frac{\partial y}{\partial x}$ instead of $\frac{\partial y}{\partial t}$ for $y(x,t) = y_m\sin(kx - \omega t + \phi)$
(multiplied by 1/2 and m then squared of course)
 
@Obliv sigh,
you don't get excited enough any more to be worth trolling
not that I would troll ofc
 
Of course not. That post by david z on the sidebar has nothing to do with your flag on my innocent remark.
 
@Obliv Uh, it has to do with JD.
(as do most things in the chat)
@dmckee Can we reduce the number of pinned messages?
I think the fourth has run its course.
Also the second.
 
well I'm going to be up pretty late tonight and need someone to ask random stuff to so I think you're morally obligated to stay up tonight too @0celo7
after what you did to me
 
I've got a nuclear physics exam tomorrow
 
12:51 AM
yeah I know about nuclear physics just ask me stuff
It'll be mutually beneficial I swear (on your grave).
a uranium atom decays into 182 hydrogen atoms. See? I know my stuff.
 
proof?
 
1+1+1+1+....+1 = 182.
oh i was a little off uranium has 92 protons
close though
 
you're forgetting the neutrons
 
it's not like hydrogen is made of neutrons @0celo7
(is it? just testing you)
 
I don't know actually
not a physicist
 
@DanielSank How come I don't get those pings any more?
 
Don't know what you're talking about.
 
Danke
@DanielSank We used to ping each other with bad question titles...
 
@0celo7 Bitte, baby.
@0celo7 You can't expect me not to have other relationships.
 
user218912
@Obliv where do you live?
 
1:23 AM
Someone quick, ask me a question about quantum mechanics or noise.
::crickets::
 
@DanielSank I have a joke
 
Listening.
@0celo7 Dude?
 
1:43 AM
sorry, talking to someone
it's more of a funny story
so I'm in the music library (quieter, less people, not 60 degrees)
and there's this chinese grad student
the library person picks up a half-empty Dr. Pepper (the drink) and asks "whose Dr. Pepper is this"
and the grad student says "who?"
 
@0celo7 Is 60 degrees hot or cold?
 
shrinkage
60F
 
@0celo7 So, too cold?
 
yes.
 
1:46 AM
anyway, I thought that was funny
 
@0celo7 I don't get it
 
"who?"
you don't get it?
 
@0celo7 Nope.
 
oh well
I gave it a shot
 
user218912
@0celo7 I don't get it either.
 
user218912
1:56 AM
do you mean he thought the drink was referring to a real dr.?
 
The student though Dr Pepper is a person?
@IceLord There's no . in Dr Pepper.
@0celo7 There's no . in Dr Pepper.
 
user218912
kk
 
@IceLord U.S. far away from @0celo7
Lol I got it. Did you laugh at him out-loud obnoxiously @0celo7
 
Who'd you guys vote for?
 
2:14 AM
@DanielSank oh
I don't drink it
I drink only water, nothing else
 
@0celo7 You voting?
 
for?
 
moderators
 
yes I voted
 
for who?
 
user218912
2:15 AM
ACM duh
 
user218912
ACM is the obvious choice.
 
He's my first choice. Then Alfred. Then Jim.
You Icelord?
 
user218912
can't vote.
 
2:15 AM
Oh...
 
watch this
 
user218912
but it would be ACM and idc about the others.
 
@0celo7 is it funny
no screw it I have to study
 
@IceLord Ya know once you reach 200 rep on a site, then you immediately get 100 rep on every site you go to?
 
2:16 AM
@Obliv it is very funny
 
user218912
yes I did know.
 
Ya oughta try to make it there
 
user218912
in december when I'm done learning QFT.
 
user218912
I will answer questions
 
user218912
for now I'm only asking them.
 
2:17 AM
speaking of, where is my Lee?
 
Okay I decided to watch it. @0celo7 fucking hilarious
 
@Obliv exactly
so @SirCumference I will not answer your question
 
user218912
@0celo7 you want your lee? then help me out
 
user218912
we're at 7/15 I think.
 
@0celo7 Sigh...ya needed that video to explain it
Fair enough
But this isn't politics.
It's stackexchange.
 
2:19 AM
are you trying to water down the importance of a moderator on an online q&a site @sirC
!?!?!?!
 
@Obliv yes
Funny enough the fate of this site isn't as important to me as whether Trump or Hillary get elected
 
ok @IceLord I will spoon feed you
 
user218912
@0celo7 ok 8 spoon feeds.
 
give me the spoons
what am I feeding
 
Ah, I think I've invented the ultimate physics joke.
 
2:22 AM
@sirC I'd still prefer the anonymity of who I vote for just until the voting period ends. That way ACM might answer more of my questions.
 
user218912
@0celo7 spoon 1
 
Why did the particle keep losing weight?
 
user218912
@0celo7 what happened there.
 
@Obliv You can always retract them.
 
because you're bulimic
 
user218912
2:23 AM
I understand the $\langle p | x \rangle$
 
user218912
where did the other things go
 
@0celo7 the particle
 
user218912
delta function?
 
I don't, where did it go?
 
user218912
wait what
 
2:23 AM
what's your equation for $\langle p|x\rangle$
I need context.
 
All right, but seriously
Best physics joke ever
Why did the particle keep losing weight?
 
user218912
it's $e^{-ip\cdot x}$
 
user218912
is this a typo or am I being dumb.
 
@sirC why?
 
@Obliv He wanted to be light.
 
user218912
2:24 AM
I remember I understood it during the lecture. @0celo7
 
Get it? Light has no mass.
 
wait no
 
yep as I thought. I will never entertain jokes from @SirC again.
 
oh I'm stupid
 
@Obliv good idea
 
2:25 AM
it's $\langle p|k\rangle$
which is $\delta(p-k)$
 
user218912
yep delta function.
 
user218912
knew it.
 
ok but where does the $\omega$ go
 
user218912
I said it wrong.
 
All right, what did one electron say to the other?
 
2:26 AM
that actually makes me wonder where the word 'light' came from. Whether it was used as a description for the weight of something before the physics term @sirC
 
user218912
@0celo7 uhm...
 
user218912
you mean the $\frac{1}{2\omega}$
 
@0celo7 Neither do I.
 
@Obliv in German the words for light and light are similar, but different.
 
@Obliv They derived from different languages
 
user218912
2:27 AM
@0celo7 I don't know where the extra $\omega$ term disappeared to.
 
user218912
spoon feed me please.
 
I learned it from reddit
 
I don't know
 
The photon-light was derived from the word "white" from some language, and weight-light was derived from the word "lung" in some other language
 
I need the context
 
2:27 AM
But yeah, I got the new joke
What did one electron say to the other?
...anyone?
 
Okay, from that explanation I will give you another chance @sirC What did it say?
 
@Obliv Nothing. It just waved.
Eh? Ehhhh?
._.
 
user218912
@0celo7 this goes in this, that's all the context.
 
yeah I like the light one better
 
2:30 AM
What book is this from?
 
user218912
@0celo7 class notes.
 
Did you check Tong?
 
I made multiple answers here
13
Q: Astronomy Jokes

DumbledoreWhat are the best astronomy jokes you've ever heard? I'm looking for images; however, you can share whatever you like.

Probably not something to be proud of
 
user218912
we're just showing how when the field operator acts on the vacuum state you get linear combination of momentum eigenstates. and then he takes the inner product with the momentum eigenket but idk where the $\omega$ goes now.
 
user218912
and no I didn't
 
user218912
2:32 AM
let me check
 
Hold on just a second..a transverse wave has transverse kinetic energy but not horizontal?
O wait maybe it's referring to the kinetic energy in the string (which is displaced vertically) since the wave itself can't have kinetic energy as it has no mass
yeah it's that one.
 
@IceLord Free field?
 
user218912
@0celo7 yes
 
well now wait a moment
don't you need a Lorentz invariant measure?
 
user218912
@0celo7 yes
 
user218912
2:37 AM
so are you saying it's just part of the measure?
 
you should have notes on what the delta function exactly is
@IceLord I think so.
 
user218912
yes you're right.
 
user218912
I remember him saying that.
 
user218912
okay so that's why it disappears.
 
user218912
@0celo7 what do you mean?
 
2:37 AM
nvm
 
user218912
I know what it is.
 
no
 
user218912
I don't?
 
I mean what it is in this case
you need a different measure
but looking at Weinberg that seems to be right
 
user218912
okay thanks.
 
2:38 AM
let's keep going
#2?
 
user218912
I'm basically reviewing all the notes to make sure I get everything and I'm writing out all the steps he skips.
 
user218912
5 pages left till I catch up to where we are.
 
user218912
so yeah wait 5 mins
 
user218912
10 pages actually. so maybe a bit longer.
 
10 pages can take a long time if it's dense
 
2:43 AM
He read a 600 page book in like a week once.
 
user218912
that is true. but I retained about 30% scattered throughout which by itself has allowed me to progress really far.
 
user218912
@0celo7 line 3
 
user218912
how does it become the commutator?
 
user218912
I bet this is probably really obvious.
 
it is
Is $\phi^+(x)|0\rangle =0$?
Or $\langle 0|\phi^-(y)=0$
 
user218912
2:49 AM
@0celo7 yes ofc.
 
of course?
I have no clue what these symbols mean
 
user218912
@0celo7 because it has only the annihilation operator in its definition.
 
user218912
let me show you the definitions
 
but just expand the commutator and then you'll have $\langle 0|\phi^-(y)\phi^+(x)|0\rangle=0$
plus the term you had originally
 
user218912
 
user218912
2:51 AM
oh
 
user218912
@0celo7 which term I had originally?
 
the one with $\phi^+$ and $\phi^-$ flipped
 
user218912
oh I misread what you said.
 
user218912
yes I get it.
 
user218912
@0celo7 if you were able to remember that I'm 100% sure you have a really good memory and you still remember QFT.
 
user218912
2:55 AM
but I guess you could have guessed it too based off what the answer was.
 
user218912
so idk.
 
@IceLord correct
 

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