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8:45 AM
@Danu hey :D long time no see
 
9:01 AM
@Phonon seriously!
what happened to you?
 
@Danu just univ mate :(
@Danu too much solid state physics...
 
So solid
Uni is back on for me too
but I'm doing OK so far, even with the excessive amount of time I spend on SE :)
 
@Danu not that the courses are too difficult necessarily, but the task on your shoulders for every week is overwhelming
@Danu 5 compulsory exercise sheets to hand in every week...
oh yeah? and how is it?
 
pretty cool
really mathematical
 
nice!
 
9:06 AM
so it's difficult because I have no formal math. background whatsoever
 
name some of the courses
 
Math. QM, GR, QED, DiffGeo
that's it
 
oO
differential geometry as well?
 
yeah
 
wtf this program? ... :( freaking scary
 
9:07 AM
I wanna take the chain of courses: DiffGeo -> Riemannian Geo -> Complex and/or Symplectic and/or Algebraic Geometry
 
good luck with that mate :) sounds interesting but also very challenging I'd say :)
so which one keeps you busy mostly? thus far
 
MQM
 
liking it at least?
 
meh
proving bounds on hamiltonians
 
:))
 
9:09 AM
starting to get worried about DiffGeo too
I hate that nobody follows books here
so it's hard to read the proper material
 
yeah I can imagine, same here honestly
but all in english right?
 
Yeah, I'd be seriously screwed otherwise, haha
 
hahaha
we're only 5...ridiculous :)
 
Oh, but that's great, that means you can get a really specialized treatment
 
yeah^^
 
 
8 hours later…
5:26 PM
@KyleKanos hey man, how are you? btw have you seen this post before? really funny :)
http://math.stackexchange.com/questions/820686/obvious-theorems-that-are-actually-false
 
@Phonon @Phonon: I am doing well, yourself?
I have seen that post before
Half of it is lost on me, of course
 
5:42 PM
@KyleKanos thanks not bad either, yeah same :),
 
 
1 hour later…
6:54 PM
Could anyone help me with a problem? Basically: A person falls off a ridge into a snow bank. Distance from ridge to snow bank is $3.6\,m$. Person descends into snow bank $0.80\,m$ before stopping. What is the acceleration in the snow bank?

I figured the first $3.6\,m$ follows the position function $y(t) = -1.635t^3$. Therefore, it takes $1.3\,s$ to fall from the ridge to the snow bank. $\vec{v_0}$ in the snow bank is then $-8.289\,m/s$. How do I figure out $\vec{a}$ in the snow if I don't have time?
 
@noahnu Hint: It's one of the 4 kinematic equations
 
Oh.. haha. Thanks.
 
7:24 PM
@KyleKanos Hi You active?
 
In and out
I did get your message the other day
And the answer is still, sadly, that I have not gotten to it
 
Oh...I could make out from your conversations that you have been quite busy.But never mind -just pls read it when you got the time.
I have time till the end of this month.
After that i have a BIG exam on 2nd nov.
@Kyle Kanos I can actually post it as a question for the main site but that would mean saying the answers given were wrong...and i dont want to do it.May be i am misinterpreting somewhere-so i just wanted to consult you.
 
If you think the answers are wrong, the best thing to do is offer a bounty
 
@KyleKanos But that would not bring W.L's writing in highlight would it?Before i saw it i did not have the slightest confusion about the answer i.e your answer.
 
I started skimming the document you gave me...I think I know what's confusing you
He says, on Page 3, that using E+ iR - L(di/dt) = Delta V is DEAD WRONG
That is what user3814483 was mentioning in the comments
That you either have to use Faraday's formalism, my equation 2, which always works or you have to introduce some "fudge factor" to account for the non-conservative nature of the field
 
7:40 PM
@KyleKanos Yeah and in his lecture he says potential drop across an inductor is 0.
So what do we conclude -that KVL is not applied right?
 
@soumyadeep For most cases in academic courses, it is correct because inductors generally aren't present.
When inductors are present in the circuit, you have to modify your equations
As I stated in my answer, Lewin's interpretation of Kirchoff's law is misleading
 
@KyleKanos Umm,can you explain how?I am again lost..:(
And the issue that is hitting me again and again is that voltage drop across an inductor is 0.I simply cannot get it.
 
So Lewin says that Kirchoff 2nd means the closed integral of the electric field is zero, $\oint \mathbf E\cdot d\mathbf s=0$
That's not really how it's taught in textbooks these days
It's generally given as $\oint\mathbf E\cdot d\mathbf s=-d\phi/dt$, which is Faraday's law
 
@KyleKanos Really?so now i get the source of all this confusion.However in my text the first equation is written.
But that does not matterI think i have got it.
Except for the fact that voltage drop across inductors is 0.
On a side note-Cant we write proper Mathjax equations here?
And what is the time at your place?
 
@soumyadeep There's a link in the top right, For MathJax use meta....
That will link you to a page to embed MathJax in chat
And it's 15:53 (or 3:53 pm to some people)
 
7:57 PM
@KyleKanos ohh here its 01:26(1:26 a.m.) which is why i rarely find you in chat.
 
Yeah, I'm an East-coast American
 
@KyleKanos And i am an Indian
anyways i suppose we should go back to voltage drop across inductors.
@KyleKanos Lewin appears to have explained that voltage drop across inductors -at least in the way he concludes it.
 
Yes, he explains that the measured value would be the inductor with the voltmeter
Again, this is him being misleading because every measurement with a voltmeter is that of the object and the voltmeter
 
@KyleKanos Yes what is the problem with that? he says the voltmeter will give a reading and thats the time rate of change of flux through the voltmeter.
 
8:13 PM
Oh, I see now
He's going back to the two ways of handling the inductors in a circuit
Way 1 involves Faraday's law and thus there can't be the potential drop across an inductor
Way 2 involves the "fudging" of saying there "is" a potential drop
He's using the voltmeter bit to say that Way 2 is the wrong way to think about it
 
@KyleKanos Exactly.And i have understood all of Way 1 except for the last bit.
 
If $\oint\mathbf E\cdot d\mathbf s=0$ was right, then there would be a (conservative) electric field in the inductor
But since there isn't such a conservative field, there can't be something called a potential there
What is there is a time-rate of change of the magnetic flux, $d\phi/dt$
And that is what you'd measure.
 
@KyleKanos Ohhh I forgot the basics of potential difference...
NOW i get it....
 
Awesome sauce!
 
However he claims in his lecture that electric field in an inductor is 0..
And i think it has something to do with that loop in the last bit of his document.
@Kyle Kanos I somehow related the potential part with the electric field being 0...I think Lewin does that too.But since you cleared that potential bit, this arises as a separate problem.
 
8:24 PM
In the "one-loop inductor" there is nothing there to reduce or increase the electric field
So since the integral there is zero, then E must be zero as well
 
@KyleKanos And Lewin opposes exactly this idea.
second last line of page 4.
 
Hmm, I'm not sure then
 
@KyleKanos So...I suppose we should end it here?
 
That's the best I can do
 
Thanks a lot though.I really do see things more clear now.
Bye.
 
8:54 PM
@ACuriousMind hey man, there?
 
@Phonon Yup, I'm here :)
 
@ACuriousMind can I ask one stupid question? :)
 
I've read you're quite busy at the moment?
 
yeah :(
 
@Phonon Of course
 
8:56 PM
@ACuriousMind isn't any superposition of Bell states necessarily an entangled state? (apart from all 0 cases)
@ACuriousMind asking in relation to this post, physics.stackexchange.com/questions/141143/…
 
I'm currently writing something on that question ;)
 
aha :) cool
don't let me hold you then, go ahead ;)
 
And I don't think that all superpositons of Bell states are entangled, since they are a basis for the full space (so every vector is a superposition of Bell states), and there's a non-trivial subspace there that is not entangled
 
okay, thanks for the clarification, then I guess my asnwer to that post, as it is, stands completely wrong, or?
 
Now that I've read it more closely, I think it is - all you conclude at the end (that I see) is that the vector is a superposition of basis vectors, which is proving nothing.
 
9:06 PM
okay, I understand. But isn't the 3rd term alpha_1 beta_0 being 0 and all the rest non-zero, already enough to say that it has to be an entangled state?
 
Yes, it is, by the contradiction the OP already alludes to. But since I saw two explicit answers for this state, I thought I'd take a more general approach to thinking about entangled states for 2D Hilbert spaces
 
k, right, good idea
 
9:28 PM
I think I've never before seen a question with four answers at zero score :D
On a different note: "This is classic Luke Skywalker stuff : ditch the variables and equations, instead hold true to the basic definitions. "
The things you see in the LQ queue...
 
9:48 PM
haha yeah :)
 
10:13 PM
@ACuriousMind hahaha you ll love this one xkcd.com/849 :))
 
@Phonon Hehe :D You haven't really lived until you stood at a blackboard and said that ;)
 
;))
@ACuriousMind xkcd.com/171 :)
 
That one's just mean (but funny ;P) (I will refrain from commenting on its veracity until I know more about string theory)
 
10:36 PM
And now I must rest, the nights aren't that long now that my semester has finally started
 
user54412
11:32 PM
So, there are 58 questions tagged and a similar number about white dwarfs, but there is no tag for the latter. Should this be remedied?
 
user54412
Actually 13 + 5 more + 1 more white dwarf questions
 
user54412
(side note - does anyone know how to use or in searches for phrases along with is:question?)
 
11:47 PM
Here's the search info on meta:
188
Q: A new search engine for Stack Exchange

Nick CraverAfter the performance problems we have run into with Lucene.NET we've decided to make a change, we're moving the network on to elasticsearch. Here's where to get started: http://stackoverflow.com/search What works: All search operators should be in Many changes below from the old search behav...

I actually don't see anything about an OR operator
And yes, I would favor adding a tag for white dwarfs. Seems like a pretty clear case to me.
 
user54412
This suggests or only works between tags
 

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