@Balarka:

$f:\Bbb N\to\Bbb N$, with $f(mn)=f(m)f(n)$, $f(2)=2$, and $f$ strictly increasing

Or, rather, why can't you?

@SohamChowdhury Without that property you could define $f(2^p)= 2^p$ and $f(q) = 1$ if $q$ is odd and then extend multiplicatively. Now if $m = 2^k \cdot a$ and $n = 2^\ell \cdot b$ where $a$ and $b$ are odd, then $f(mn) = f(2^{k+\ell} ab) = 2^{k+ \ell} = f(m)f(n)$.

'Cuz $f(ab) = f(a)f(b) = 1$

I don't understand what you mean by FTA. Fundamental theorem of algebra? How?

With strictly increasing property this is obvious, of course