1:56 PM
There @LeakyNun ?

@LeakyNun FInd he number of ways of selection of atleast one vowel and one consonant from the word TRIPLE.
Let me explain my method
(IE)(TRPL)
Therfore number of ways = $\dbinom{2}{1}\times \dbinom{4}{1} \times 2^3$
First choose onevowel.
Then one cons.
Then the rest have 2 choices each. - enter the group or not.
Why is this wrong @LeakyNun?

2 mins ago, by Abcd
@LeakyNun FInd he number of ways of selection of atleast one vowel and one consonant from the word TRIPLE.
select how many?

@LeakyNun the only constrain is 1 vowel, 1 const should be there.
you can also have 2 vowels 1 const
then 1 vowel 3 const
etc..

exactly

2:01 PM
yes?
3 mins ago, by Abcd
Therfore number of ways = $\dbinom{2}{1}\times \dbinom{4}{1} \times 2^3$
2^4, not 2^3 in the end..
@LeakyNun are you there.

I don’t want to think about it right now