Hello o/

@cairdcoinheringaahing CMCs or old challenges \o?

CMCs?

sure

CMC: Given x and y, determine the largest integer divisible by x that is less than y. x and y can be any number that isn't 0. You can assume that such a number exists

Ok, yeah we should do that one

Test case?

Example: 3, 100 => 99

7 bytes.

7 bytes. Takes input reversed

Like 100, 3?

Yeah

Mine does 3, 100.

Let me try 100, 3 too

7 bytes, takes input normally

@cairdcoinheringaahing 6 bytes by taking the input in reverse.

Hi Hyper

Hello

Hey Hyper

[Opening tabs...] :P

[3 years later...]

5 bytes with argument reversed

6 bytes using 100, 3

6 taking it normally

4 bytes, reversed.

3 bytes using 100, 3

Yeah 3 bytes... That's so obvious

ಠ_ಠ Do yours use ḍ?

We are really overcomplicating stuff oftentimes...

@cairdcoinheringaahing No.

Neither.

3 bytes here

MD5 Hash: 9720EB50AD606409704B9B9666EB97DD

MD5 Hash: 70E503C27C18AE643E85D296EFAAC198

Another 3-byter with MD5 Hash: 70E503C27C18AE643E85D296EFAAC198

@Mr.Xcoder Same hash as mine

FWIW, mine was :×⁹

:×⁹ or :×⁴

My previous ones were: rọ³$ÐfṪ, ọ⁴$ÐfṪ, ọÐfṪ

A bit late but md5: 9720eb50ad606409704b9b9666eb97dd

I had ḍ@ÐfṪ

Mine was Rḍ@ÐfṪ and then :×⁴

CMC: Given a list, determine its partition with the minimum length and with all the partition sums equal (you may assume such partition exists, if there are more return the one with the least sublists)

@HyperNeutrino Ðf implicitly casts to range

oh cool

@Mr.Xcoder Test case?

Making one.

9 bytes, md5: 376ec1ff209f2ff3a7adab4757e90339

[1, 2, 3, 4, 5, 5] -> [1, 2, 3, 4], [5, 5] (boring case)

> with the minimum length

hm?

You have to return the sublist with the minimum length

(except from itself)

oh right

I was verifying against an edge case lol

Like [1,2,3,4] doesn't give [1,2,3,4], it gives [[1, 4], [2, 3]]

10 bytes, dm5: 0c5b3b7f2c3817332218d9e1936fa547

(the lowest number of sublists)

[5, 6, 3, 8, 2, 9] -> [[5, 6], [3, 8], [2, 9]]

oh wait

partitions won't work lol

This is beginning to feel too long..

11 bytes. I think it is valid.

15 bytes, md5: 080cfec79f50fb41626bad92c2ef0eae

(not looking at the 11-byter yet)

No mine's invalid.

rip

13 bytes, It is valid now.

Gtg now o/

o/

12 bytes here

@HyperNeutrino you still here?

hi

sorry was working on fixing proton bugs

o/

Yeah, sure

12 bytes

Œ!ŒṖṖ$€ẎS€E$ÐfṪ

@Mr.Xcoder That's mine

I though so too

School

tomorrow

G'nite

G'nite \o/ Yay for half-term holidays