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5:18 AM
@JohnRennie hi
 
@Nobodyrecognizeable morning :-)
 
@JohnRennie do you know scilab?
 
@Nobodyrecognizeable no, I don't. Sorry :-(
 
@JohnRennie somewhat like matlab
 
I've never used matlab either ...
 
5:23 AM
OK. Have a nice day professor. Goodbye.
 
psa
I've used matlab
I haven't used scilab though
@JohnRennie I asked a prof if he could give me some QFT stuff to think about and it's actually quite fun! Every question is extremely hard though, mostly because it's stuff I'm unfamiliar with.
quite mathy indeed
 
@psa yes :-)
 
@JohnRennie hi
Are u free
 
@Aladdin I'm answering a question on thermodynamics, but I shouldn't be too long.
 
5:44 AM
Pk
 
6:06 AM
@Aladdin hi. we're done with thermodynamics now.
 
 
1 hour later…
7:21 AM
@JohnRennie0 I showed the code to teacher to mam snd it worked
Thanks a lot
 
:-)
 
 
2 hours later…
9:33 AM
@JohnRennie do u know how to add graphic
To codes in python
 
@Aladdin there's a graphics module for Python. I've used it for graphing. I've never done more general graphics but I'm sure it's straightforward. What sort of graphics do you want to do?
 
Like for the sentence generator,I should add a graphic upon which it will show a message ' click here's and upon clicking it tells the user to enter two words
 
Ok, so effectively use Python to create a graphical Windows app.
 
Idk how to do. . Can you link me article
 
This is a good description. But it's a lot of extra work.
 
9:38 AM
Ok. I would ping you with doubts
 
 
1 hour later…
10:41 AM
@JohnRennie hello sir :) Can I ask you a question?
 
@user8718165 yes
 
@JohnRennie sir, why can't all heat be converted to work? Even in a Carnot Engine
 
@user8718165 did you read the Wikipedia article I linked?
 
@JohnRennie Yeah sir...I read I it now but still :(
@JohnRennie sorry! I didn't read it yesterday.
 
11:14 AM
@JohnRennie hello sir
 
@user8718165 hi
 
11:30 AM
@JohnRennie hi.
 
@Nobodyrecognizeable hi
 
@JohnRennie how to approach?
 
@Nobodyrecognizeable That sounds like a parabolic mirror to me ...
 
@JohnRennie ok
What's next.?
 
11:49 AM
Well it's a property of parabolic mirrors that they focus all parallel rays to a single point. Contract this with spherical mirrors where only parallel rays close to the optical axis get focused to a point. So I assume the question is talking about a parabolic mirror.
So I'm guessing the question means a mirror like this.
So if the light is focused at the origin it will look something like:
Where I'd guess they mean $a$ to be the focal length of the mirror.
So the equation is going to be something like $x = Ay^2 + B$ for some constants $A$ and $B$.
Or rearranging: $y^2 = Ax + B$. And answers (a) and (c) have that form.
I don't know offhand whether (a) or (c) is correct and I can't think of an easy way to tell. You'd have to know about the geometry of parabolic mirrors.
 
12:30 PM
@JohnRennie hello sir...I still didn't get...Need your help
 
I need to go in 10 minutes, so I don't have time to go through the argument now. Sorry :-(
 
@JohnRennie okay sir...
 
 
3 hours later…
3:05 PM
@JohnRennie I need your guidance!
the question: An artificial satellite is moving around the surface of earth. If the magnitude of the gravitational constant starts decreasing at a constant rate, then what would the effect on the path of the satellite be?
(Would it spiral outwards? inwards?)
0
Q: How would the path of a satellite be affected by the gravitational constant decreasing?

Madhav NairAn artificial satellite is moving around the surface of earth. If the magnitude of the gravitational constant starts decreasing at a constant rate, then what would the effect on the path of the satellite be?

the question has been asked before, yet I couldnt understand any of the answers.
 
 
1 hour later…
4:10 PM
@McSuperbX1 hi :-)
@user8718165 I'm around for an hour or so if you want to discuss that heat engine question.
 
@JohnRennie hello sir :) Did you have your lunch?
 
@user8718165 hi, yes, I'm all finished and free to talk about heat engines if you want.
 
@JohnRennie well....yeah sir
 
Ok. Do you know what the Carnot cycle is?
 
@JohnRennie yeah sir
 
4:17 PM
So you know what a Carnot engine is since it operates using the Carnot cycle?
 
@JohnRennie Sir I got an explanation...can I tell you sir?
 
Yes, go ahead.
 
@JohnRennie yeah sir...
 
@user8718165 are you going to say how you think it works?
 
@JohnRennie Sir I'm thinking like this...Is it incorrect sir?
 
4:23 PM
That isn't how the proof works ...
 
@JohnRennie okay sir sorry
@JohnRennie you please tell...
 
OK. The key thing about a Carnot engine is that it is reversible. So you can use it as an engine, i.e. let heat flow from hot to cold and do work, or you can use it as a heat pump i.e. put in work and pump heat from the cold to the hot end.
 
@JohnRennie yeah
 
The efficiency when used as an engine is:
$$ E = \frac{T_h - T_c}{T_h} = 1 - \frac{T_c}{T_h} $$
 
@JohnRennie yeah sir...I was just typing XDXD
 
4:28 PM
That's a standard formula for a Carnot engine that you should be familiar with. For any cold temperature above absolute zero $E < 1$.
 
@JohnRennie yeah sir...what happens at absolute 0?
 
When used as a heat pump the efficiency is greater than one i.e. the amount of heat pumped from the cold to the hot end is greater than the work you put in. In fact when used as a pump the efficiency is simply $1/E$ i.e. $E_{pump} = T_h/(T_h - T_c)$.
 
@JohnRennie okay sir
 
So the proof we need is that no form of heat engine can be more efficient than a Carnot heat engine. OK so far?
 
@JohnRennie yeah sir...I read it..I have a different question sir...I got the proof :)
 
4:33 PM
@JohnRennie Hello, im here!
 
Ah, OK, I thought that's what you were asking ...
@McSuperbX1 hi :-)
 
Are you free to answer my question or busy with someone else?
I can wait if you want me to :)
 
@user8718165 shall I answer McSuperbX1's question now, then get back to you?
 
@JohnRennie sir still thank you very much for telling me....I was asking sir...what happens to a carnot engine at 0K?
@JohnRennie okay sir...sure :) I'll wait
 
@user8718165 It becomes 100% efficient.
If $T_c = 0$ the efficiency is $E = (T_h - 0)/T_h = 1$
 
4:35 PM
@JohnRennie okay sir...you can help user McSuperbX1...I have a few more qns.
@JohnRennie yeah sir...got it :)
 
@McSuperbX1 suppose we start with a satellite in a circular orbit.
 
Ok.
 
In a circular orbit the centripetal acceleration $mv^2/r$ is equal to the gravitational force. Yes?
 
Yes
 
But if we decrease $G$ slightly we decrease the gravitational force and that means the circular orbit should have a reduced velocity to keep the centripetal force and gravity equal.
 
4:39 PM
Okay.
 
So our satellite is now moving too fast for a circular orbit. Instead it will at the perigee of an elliptical orbit.
 
Ahh okay
Right makes sense
That is what I guessed but wasn't too sure!
 
So reducing $G$ means on average the distance of the satellite from the Earth will increase.
 
Correct.
 
The actual trajectory isn't trivial to calculate. You'd start with some dependence of the force on time and use that to calculate the trajectory. It would be a spiral of some form but you'd probably have to do a numerical calculation to get the exact form.
 
4:41 PM
Fortunately the question does not intend to ask that
It was an MCQ asking whether the object spirals outwards or inwards or neither
though it would be interesting to find what really happens to the trajectory
 
Orbital dynamics is one of those things that looks like it should be simple, but the equations describing the orbit rapidly get scary complicated :-)
 
Ah. I've never dipped my toes into the subject really haha.
Thanks a lot @JohnRennie
 
You're welcome :-)
 
@user8718165 If you want to ask questions, feel free to do so.
(not from me, lol)
 
@user8718165 your turn! :-)
 
4:46 PM
@JohnRennie hello sir
@JohnRennie why can't we convert all heat into work?
@McSuperbX1 yeah sure...
 
@user8718165 but that's the Carnot theorem, which you said you understood ...
 
@JohnRennie yeah sir...I got what it says...but not the reasons sir :(
 
So you're asking for an intuitive explanation?
 
@JohnRennie yeah sir...Is it that transferring some heat to the surroundings is inevitable?
 
@user8718165 I must admit I don't know an intuitive explanation why a heat engine cannot be 100% efficient (except at $T_c = 0$).
Aha, wait!
@user8718165 A Carnot engine is reversible so the total entropy change when it completes a cycle must be zero. Yes?
 
5:01 PM
@JohnRennie no worries sir... :) That's absolutely fine
@JohnRennie yeah sir...I got that reason :)
 
So the entropy loss of the hot end $Q_h/T_h$ has to be equal to the entropy gain of the cold end $Q_c/T_c$.
So:
$$ Q_c = \frac{T_c}{T_h} Q_h $$
 
@JohnRennie yeah sir...
 
And that can only be zero if $T_c = 0$.
 
Got it
@JohnRennie Aha that's the 0K case...right sir?
 
Yes.
 
5:05 PM
@JohnRennie okay sir...got it...One last question sir
 
Yes?
 
@JohnRennie What is the reason behind the formula for entropy? $dS=\frac{dQ}{T}$
 
Don't know. Next question? :-)
 
@JohnRennie Okay sir...no worries at all...
@JohnRennie That was the last question for today :) I'll study tonight and will ask you qns tomorrow XDXD
 
@user8718165 OK :-)
 
5:09 PM
@JohnRennie yeah sir :)
 

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