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Feeds
Feeds
5:08 AM
 
 
5 hours later…
SBM
SBM
9:38 AM
Merry Christmas.
 
fejfo
fejfo
Merry Christmas
 
 
3 hours later…
Simply Beautiful Art
Simply Beautiful Art
1:11 PM
@SBM @fejfo @user21820 @user170039 @Zophikel @AnantSaxena @amWhy @Riker @YokaiTheMonster @Ovi @LeakyNun @LastIronStar @KulsDroid @Mithrandir @DavidReed
 
user131753
@SimplyBeautifulArt Same to you.
 
Zophikel
Zophikel
2:57 PM
@Simply Merry Christmas :>)
anyone got an hint :>)
2
Q: Absolute convergence of $\sum\limits_n\left( \log (1-\frac{z}{n})^{n^{k}} + \sum\limits_{m=1}^{k+1}\log e^{n^{k-m}z^m/m} \right)$?

ZophikelI'm having trouble verifying my appoarch to the problem in $(1)$, much of efforts can be seen in the sections titled $\text{Lemma}$, I'm specifically stuck where $(1.6)$ would the absolute convergence of the double series imply anything about the absolute convergence of the product in $(1)$ ? $(...

sequences-and-series infinite-product
 
Zophikel
Zophikel
3:20 PM
@Simply you got a Hint I just realized the series on the RHS side of $(1.2)$ doesn't converge :'( i'm thinking of changing the outer product to an infinite series and using the convergence of that and going further
 
 
2 hours later…
SBM
SBM
5:02 PM
Hello.
 
 
5 hours later…
fejfo
fejfo
9:53 PM
HI.
 

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