Aim A quick search for duplicates. Question If $|f(z) |\leq 1 + |z|$, show that $f(z) = az + b$ is a recently-posted question. I tried to search for its duplicates on Approach0 but I didn't manage to get something like Showing that $f$ is linear function if $\forall z \in \mathbb{C}$, $|f(z)| \l...
10:47 AM
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Let $f$ be an entire function that satisfies $|f(z)| \leq 1 + |z|$ for all $z\in \mathbb{C}$. Show that $f(z) = az +b$ for fixed complex numbers $a,b$. The hint tells us to try and use Cauchy's Integral Formula on an arbitrary circle. This is my attempt: Consider an arbitrary large circle w...
Ok, so it is in the index, when I tried to copy a formula from that question, it is among the search result.
Interestingly, if I take the search you linked and omit all occurrences of
\left...
and \right....
then it appears near the top. I am not sure whether this should make much difference - I have asked about this in the searching chatroom. — Martin Sleziak 17 secs ago11:44 AM
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Approach0 Searching for a specific formula is often rather difficult. A tool which is very suitable for this is the Approach0 search engine. Some basic information can be found in Guide for New Users (which contains also animations of some examples). If you want to know more about the project, ...
> There is also a distinction between
|x|
and \left|x\right|
, Approach0 treats these two differently as a result of some technical considerations.
> For example, compare the search for $\frac{|x+y|}{1+|x+y|}\le\frac{|x|}{1+|x|}+\frac{|y|}{1+|y|}$ with and ...
6 hours later…
5:55 PM
@MartinSleziak \left \right for "(" or ")" does not change anything, as you said. So if you try this one and this one you get the same result (2nd result is what you are looking for, and they have exact the same score which is 142.042)
As you have pointed out, to find the linked post as mentioned on meta, you need to remove \left and \right around vertical bar |, it is exact the case you mentioned here, there is no easy way to know how to pair vertical bars, because left bar and right bar are the same. That is why I treat them differently.
6:09 PM
BTW. (still excited working on some code at 2am) I have finished a new search engine UI that is mobile friendly. You can preview it here: imgur.com/a/tQJ5Zjv
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In the search of a question
When you are looking for a specific question (using Approach0 ...