2
Using the Mellin Barnes technique for a certain Feynman integral, I arrive at
$$
I=
\frac1{2\pi i}
\int\limits_{-i\infty}^{i\infty} dz\;
\Gamma^4\left(\frac12 + z\right)
\Gamma^4\left(\frac12 - z\right)
\psi\left(\frac12 - z\right)\,,
$$
where $\psi(x)$ is the digamma-function. This i...