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Question
How to evaluate $$\int_0^1 \frac{\arctan(x)}{x} \ln^2(1 - x) \, dx$$
My attempt
\begin{align}
\int_0^1 \frac{\arctan(x)}{x} \ln^2(1 - x) \, dx &= \int_0^1 \int_0^1 \frac{\ln^2(1 - x)}{1 + x^2 y^2} \, dy \, dx \\
&= \int_0^1 \int_0^1 \ln^2(1 - x) \cdot \frac{i}{1 + x^2 y^2} \, dx \, d...