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01:09
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Q: Is it true that $\#(\mathrm{Ker} f)^⊥=\#\mathrm{Image}(f^*)$ when the pairing is non-degenerate?

Poitou-TateLet $f: A → B$ be a homomorphism of a finite abelian groups. For a pairing $A × A → \Bbb{Q}/\Bbb{Z}$, we denote the orthogonal complement of $\mathrm{Ker} f ⊂ A$ by $(\mathrm{Ker} f)^⊥$. When the pairing is non-degenerate, is it true that $\#(\mathrm{Ker} f)^⊥=\#\mathrm{Image}(f^*)$ ? Here, $f^*...

I suppose the newly created tag (algebraicnum) is a typo? What tag was supposed to be there? — Martin Sleziak 6 secs ago
 
1 hour later…
02:15
2
Q: Spivak's differential geometry: Chapter 8 Theorem 11

KadmosI am having trouble understanding this claim about the existence of the sets $U_j$ in the following theorem from Spivak's differential geometry textbook. I tried proving like this: Firstly, we may take a covering which has no subcover and refine it to produce open sets $U_j$ diffeomorphic to $\...

 
3 hours later…
05:39
The tag is gone.
 
7 hours later…
12:40
0
Q: Is it true that $\#(\mathrm{Ker} f)^⊥=\#\mathrm{Image}(f^*)$ when the pairing is non-degenerate?

Poitou-TateLet $f: A → B$ be a homomorphism of a finite abelian groups. For a pairing $A × A → \Bbb{Q}/\Bbb{Z}$, we denote the orthogonal complement of $\mathrm{Ker} f ⊂ A$ by $(\mathrm{Ker} f)^⊥$. When the pairing is non-degenerate, is it true that $\#(\mathrm{Ker} f)^⊥=\#\mathrm{Image}(f^*)$ ? Here, $f^*...


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