Let $f: A → B$ be a homomorphism of a finite abelian groups. For a pairing $A × A → \Bbb{Q}/\Bbb{Z}$, we denote the orthogonal complement of $\mathrm{Ker} f ⊂ A$ by $(\mathrm{Ker} f)^⊥$. When the pairing is non-degenerate, is it true that $\#(\mathrm{Ker} f)^⊥=\#\mathrm{Image}(f^*)$ ? Here, $f^*...