@AntonioVargas Oh, I see. That's a bit bad, I guess. But, never mind. If there was an hard problem which you cherished solving, I'd like to know too. :)
@KannappanSampath I just parse that as follows: $g\in \mathbb{Z}_p$, so $g=[k]$ for some $k\in\{0,\ldots, p-1\}$. If that is the case then indeed the above arguments answer the question
@AntonioVargas i got distracted b/c a friend called. been moving slow. i just extracted eclipse straight to C://, now i'm trying to find out what to open there
i'm not stuck
i may be crashing really soon, i'm kind of burnt out. hopefully i can finish in a few minutes and make a quick hello world
btw the line "Now, if you don't want that dialog to appear, it's possible to import the certificate before starting the installation process" is pretty explicitly saying that step is optional
@Matt: is it clear that you can choose such a $\delta$? you want to choose $\delta$ small enough that $\int |f^\prime_n | dx < \frac{\varepsilon}{N}$, but $N$ gets bigger as $\delta$ gets smaller.
Do we have a better tag than elementary-number-theory for questions about number-theoretic properties that combine arithmetic with string manipulation on base-10 representations? They are a somewhat popular "recreational mathematics" topic, but do not really match the tag description which mentions "congruences, greatest common divisor identities, divisibility, etc."
@MartinSleziak I'm not convinced myself there is a problem either. I'm not really sure about adding (recreational-mathematics) to such questions -- it feels a bit like unilaterally adding (homework) without really strong evidence that the tag applies.
The concern is that retagging existing questions as (recreational-mathematics) could be understood by the OP as a criticism: "your musings have only recreational value" (which is probably often true but it's still a bit dickish to point it out explicitly without good reason).
No it's not explicitly recreational. I do have some trouble imagining what other motivation it could have, but that might well just be a failure of imagination on my part.
@Templar It's the set of every elements that is in all of {a,b} and {a} and {c,d} and {e}. That is, unless some of your letters are equal, the empty set.
@robjohn So far? They're using it as a sales point: "Because Intaglio is designed to work exclusively with Mac OS X, it’s able to take full advantage of ..."
@MarianoSuárezAlvarez I think they use more than that. There are some geometric drawing routines built into MacOS, but I don't think they are too hard to port. There is a project at Google that ports QuickDraw GX to many platforms. Much of code that I have written is on the Android
@MarianoSuárezAlvarez PDF is a document preparation format. Do you mean PostScript?
there is a little difference between the graphics models in ps and pdf; quartz is more or less (or was, initially?) more or less an implementation of the same graphic model as pdf
The fact that much of the code that I have written is on the Android is why Steve Jobs hated Android (not that he cared about my code, but the fact that much of QuickDraw GX was ported).
Well, the actual drawing parts of PDF (encapsulated in more layers of different wrappings than one would think necessary) is essentially a subset of PostScript, with the drawing operators given short one- or two-letter aliases.
@MarianoSuárezAlvarez Correct. All of the conditional and looping constructs are absent; the PDF creator is supposed to expand that itself. That was a quite nice philosophy, since the Turing-complete parts of Postscript are essentially just DoS-enabling bling. But then PDF somehow acquired support for embedded JavaScript instead.
Let $f,g$ non-negative functions. Let $0\leq\eta\leq f+g$. Let $\eta_1=\min(\eta,f)$ and $\eta_2=\eta-\eta_1$. The clearly $\eta_1\leq f$ but I can't see why $\eta_2\leq g$. Can someone help me please?
$\eta$ is bounded and supported in a set of finite measure
