no downhill over here....I'm moving up hill :)
it was asking the vector tangent to the curve of steepest ascent on the hill at $(\mathbf{a},c)$. You gave the gradient as $Df(a) = (3,-4)$, so the gradient being normal to my curve means that a taagent vector would be a 90 degree rotation. I used $(4,3)$....in your solution you actually stated it in 3 dimensions: $(3,-4,25)$ wondering if this is a typo? Well part of it seems to be, but where did the 25 come from?