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9:25 PM
I have been non-stop struggling with this one problem where I want to show a geodesic stays in a submanifold.
It intuitively makes sense what I want to show, but I have never seen any calculations or anything for a similar problem, and so I am at a loss for how to actually show it.
 
is it just like an arbitrary submanifold? because geodesics don't have to do that. there are too many submanifolds to choose from.
 
It's a specific submanifold.
The problem is that every time I give the specific manifold, people get scared.
 
does it have a geometric characterization? a popular version of this question is where the submanifold in question is the set of fixed points of an involution of the manifold.
 
I don't think it should be too complicated, though. I can even make it simpler. Like GL(n) as a submanifold of Diff(R^n).
With the L^2 metric.
I think the idea is that you recognize that if $\gamma$ is a geodesic with initial condition $\gamma(0)(x) = \varphi(x) := Ax$ for $A\in GL(n)$ and $\dot\gamma(0)\in T_{\varphi}Diff(\mathbb R^n)$, then you can find a corresponding velocity field $u$ such that $\partial_t u + u\partial_x u = 0$.
But I want to show that $\gamma$ continues to be in GL(n) and so it's not exactly clear how I can use this to show it (at least, to me).
Unless I can cook up what $u$ is for small t.
That equation for $u$ is just the geodesic equation, $\ddot\gamma = 0$, by the way.
*cries out for @TedShifrin *
 
9:45 PM
What ever happened to @0celo or whatever his name was. He was very Riemannian-like.
Oh, it's Ryan now!
 
what is meant by "the algebra of differential operators in $\mathbb{R}^n$ with constant coefficients"?
 
i took one class in general riemannian geometry and very little of it sank in. i can still remember some of the stuff about curves and surfaces.
 
Hi, a little group theory problem i got stuck all day and cant seem to be able to solve it. I have a group and i'm supposing that it is left orderable. If I know that $yhy^{-1}=h^{-1}$ and that $h^{-k}<y^{2}<h^k$ and $h^{-k}<y^{-2}<h^{k}$ with $h>1, k>0$ how can I show that $yhy^{-1}>1$? I've tried for a while to work it out with "bare hands calculation" but I think I'm missing something
 
p-addict, maybe something very close to a polynomial algebra. where a monomial like $x y^5 z^2$ corresponds to taking partial derivatives with respect to $x$ (once), $y$ (five times), and $z$ (two times), hopefully acting on a function space where these partial derivative operators commute.
 
@leslietownes cat-a-tonic
 
9:51 PM
so you multiply operators like $2 \partial_x \partial_y + 3 \partial_y^2 \partial z$ and $3 \partial_x^8 \partial_z^4$ together like polynomials.
 
@leslietownes ah okay, this would make sense - where i am getting this from it says multiplication is composition of operators (i should have mentioned that) so that sounds right
 
@anakhro You mean proving a submanifold is totally geodesic?
 
"totally geodesic" sounds like surfer slang but isn't
 
@robjohn Goes with a moscow mule.
 
@TedShifrin Indeed
I have a supply of ginger beer, but no vodka
@leslietownes tubular!
 
10:07 PM
i'll never forget the checker at the grocery store who saw i was buying both vodka and ginger beer and said "moscow mules?" causing me to make them later, when i went in with no plans just randomly buying them together
this is what you don't get with delivery
 
@robjohn I have 20 kinds of gin, but plenty of vodka for you.
 
@leslietownes a bless in disguise
 
i generally don't like the idea of humans surveying my purchases and connecting the dots on what i might be doing later, but that time it was OK
 
@leslietownes I was annoyed when I went into the first Amazon Fresh store to see what was there, I bought some oranges, paid with a credit card, but did not fill out any forms or anything and got a receipt emailed to me. They connected my credit card to my email via a web purchase and used that email. I felt somewhat violated about them doing that.
If I don't give you my email address, don't use it.
 
fin
@TedShifrin hi ted
 
10:17 PM
robjohn i wonder if there's been a class action lawsuit about that. it's certainly creepy
 
Hi, fin
 
fin
can i ask u a question
fuck it imma just post it anyways
 
@robjohn The google and Bezos invasions of privacy are boundless.
 
@leslietownes sorry... i'm not sure i totally understand actually. if we defined it as the algebra generated by the partials, where addition and multiplication is as with polynomials, wouldn't we just get $\mathbb{R}[x_1,\dots,x_n]$? or am i missing something
 
@leslietownes My wife was weirded out when Ralphs started sending her tampon discounts synched with when she had been buying such things in previous months.
 
10:20 PM
You care about the action of that algebra on functions. What you wrote makes that opaque.
 
@P-addict as an algebra yes, but presumably this thing is being defined so you can look at properties of how this algebra acts on a space of interest.
ted beat me to it.
 
@TedShifrin The very first Amazon Fresh store opened just down the street from here a little over a year ago.
On Topanga Canyon Blvd in Woodland Hills.
 
fin
@TedShifrin actually could i send you a question through an email
 
It replaced a Toys'R'Us that left (Geoffrey the Giraffe replaced by Jeffrey Bezos)
 
fin
i cant seem to upload photos here
 
10:23 PM
Sure, fin
 
@fin need more rep for that
 
fin
@TedShifrin is it still the uga email?
 
@P-addict e.g. in solving $p(D) f = g$, for $f$ and $g$ in some function space, knowing that $p$ is a polynomial with constant coefficients is only some of the story
 
Yeah, it works.
 
you see this even in one variable, where the 'characteristic polynomial' (or characteristic equation) might tell you something about solutions to the homogeneous equation with constant coefficients, but for a non-homogeneous one, look out
 
10:30 PM
oh okay, that makes sense
i suppose i was confused because the question was asking only about the algebra itself and not its action on a function space, so i thought there was some reason it was asking about the algebra of differential operators as opposed to just asking about the $n$ variable polynomial ring
 
hopefully there is more fun coming later.
note that by e.g. clairauts theorem considerations, or whatever that is called, there is already something interesting happening in your space if you can assume that $\partial_x$ and $\partial_y$ commute as operators on it. they don't have to commute in general
 
Hello, Lie bracket and …
 
ODE/PDE people folk love imposing boundary conditions and stuff that can change the eigenvalues of operators having the 'same' polynomial symbol
they're sick people and you should stay away from them
lie brackets too
 
scary
 
10:49 PM
what actually is a partial differential equation? is there some encompassing definition which captures the idea of an "equation using partial derivatives" in a very general sense? (probably it is not useful for actually solving PDEs, just wondering if such a general theory of PDEs exists)
 
@leslietownes Lie brackets are for liars.
(Pronounced "lee-ers").
 
there's lots of fairly general theory but i dont think there is anything resembling an all-encompassing definition. almost every paper you see has lots of hypotheses on inputs, outputs, coefficients. all examples of the theory but not sub-examples of something.
unless i'm wrong. someone go check ncatlab and see if a PDE is a co-pushout of a reverse fibration of an infinity-homotopy of actegories.
 
lol
 
@leslietownes Yeah, it is definitely one of those.
 
and the "right" way of looking at PDEs is, of course, to do category theory.
 
uh oh
 
i don't even wanna be around anymore.
 
> More precisely, we choose a category of differentiable spaces and differentiable maps between them, on which there is an endofunctor that takes each space U to a notion of tangent bundle TU, which is assumed to be a vector bundle over U, and takes a map f:U→Y to df:TU→TY.
AND SO ON!
 
apparently jet bundles are the concept i'm looking for?
 
10:56 PM
i guess you can easily axiomatize the easily axiomatizable stuff. i'm not sure how you would fit L^infty boundary data into 'differentiable spaces and differentiable maps'
but if i follow that page, i'm sure eventually i'll find out
 
what is the largest $n$ for which one can solve within one second a problem using an algorithm that requires $\log_{2}(n)$ operations? Each bit needs $10^{-9}$ seconds. I did it basically as follows:

$$1 (bit) \to 10^{-9}$$
$$\log_{2}(n) \to t$$

so, we have $t = 10^{-9} \times \log_{2}(n)$, so since algorithm has to run within 1 second, so we have $t=1$, so we have $10^{9} = \log_{2}(n)$??
what do you think pls?
 
jet bundles sounds like a rap name. there was a rapper named stack bundles, rip stack. maybe the most alge-geometric rap name ever.
 
Hi everyone, does anyone know how to show the x axis is an invariant set given x'=x^2 and y'=y^3?
 
if $X_i \not\in L^1$, can $\frac{X_1 + \ldots + X_n}{n}$ be in $L^1$?
$X_i$ randoms variables on the same probability space
 
11:12 PM
if you have a random variable X that is not in L^1, you can take X_1 = X and X_2 = -X, and then yes with n = 2? are quantifiers missing?
 
$X_i$ iid
 
@JoeShmo. What course is this pls?
 
now you tell me.
 
probability :/ But we have stochastic, statistical inference, Bayesian statistics................
Only gosh knows
@JoeShmo. What is $L^1$?
 
11:38 PM
@leslietownes as it turns out the discussion that followed my question is a spew of unnecessary information and the solution to the problem is much easier.
Thanks for putting up with it, though.
 
"spew of unnecessary information" would be a good album title
 
"this is not the album title"
 
@leslietownes you are out of academia totally now, right?
 
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