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7:00 PM
@Chris'ssis I changed the variable for t=tan(x) then did polynomial division
@Chris'ssis but it seems easier your way
 
how do i see that $Aut_q(S^2) \cong \mathbb{Z}_2$ where $q:S^2\to \mathbb{R}P^2$ is the covering map that sends a point on the sphere to the line through the point and the origin
 
@Mircea Just another way :-)
 
it seems clear that the only homeomorphisms $\varphi:S^2 \to S^2$ with $q \circ \varphi = q$ are the identity and the map that sends $x\mapsto -x$
but how do i prove that there is no other?
 
@Mircea $\frac{x^4}{1+x^2}=x^2-1+\frac1{1+x^2}$
 
@Chris'ssis how's your work comming along?
@robjohn that's exactly what I did
 
7:04 PM
@Mircea I've been working on my book and so far things are excellent! Thanks! :-)
 
@Chris'ssis glad to hear that
 
Huy
Not much going on in the chat today. :(
 
@Mircea Then $\int_0^{\sqrt3}(x^2-1)\,\mathrm{d}x=0$ and $\int_0^{\sqrt3}\frac{\mathrm{d}x}{1+x^2}=\frac\pi3$
 
@Chris'ssis I got an offer from Uni of Liverpool for the Computer Science & Mathematics course :D
 
@Mircea aaa, awesome!!! :-) Glad for you!
 
7:05 PM
@robjohn yes, I solved it
@Chris'ssis Thanks! Now I'm waiting for the other unis I applied to to answer
 
@Mircea Where would you like to study?
 
@Chris'ssis I'd mostly want to get into Lancaster University
 
Huy
@Mircea: Are your parents rich?
 
@Huy not really but I'll take a study loan
 
@Mircea I see. Is there anything special for that you'd like to study there?
 
7:07 PM
They're good, @robjohn, though I guess you deleted that message. Keeping busy. Teach linear algebra in a couple hours.
 
Huy
@MikeMiller: Remember all the cool applications we gathered for you!
 
@Chris'ssis Well, it's one of the best universities in UK and I also really like the curriculum of the CS&Math course
 
@MikeMiller I deleted the message since Hippalectryon made a bad joke which prompted the deletion.
 
Huy
@Mircea: How do you measure it being one of the best?
 
7:10 PM
@Huy 3 different rankings
@Huy or actually 2
 
Huy
@Mircea: Which ones?
 
@iwriteonbananas Deck transformations respect the covering map. Pick a basepoint of $S^2$; there are only two places it could go. (Why?) Now show that this choice of where the basepoint goes determines the whole automorphism (think paths and the unique homotopy lift)
 
@Huy well the first would be the complete university guide and the second I have to think a bit to remember
 
@robjohn Ah... he's got my number :)
 
7:12 PM
@MikeMiller oh i see
 
Huy
@Mircea: Ah, okay, cool. Too bad they only list UK unis. Any particular reason you want to study in the UK?
 
@Huy I don't know any other language besides romanian and english; UK offers student loans that cover all of the university fees; It's not as far as USA; I was too late to apply in USA
 
Huy
@Mircea: Okay.
 
@Huy I got it =)
 
Huy
@N3buchadnezzar: Good. :)
 
7:18 PM
@Huy Finished your work?
 
Huy
@N3buchadnezzar: Not before 2016.
 
heellooo
 
hi there
 
@user153330 Hello
 
7:23 PM
@user153330 welcome
 
@Chris'ssis @Mircea how're you? = )
 
@MikeMiller mike, do u know where i can find old exams on this topic? (anything from point set topology to automorphism group of a covering)
 
@user153330 Not that bad, thanks! ;)
 
@user153330 Pretty good, thanks for asking!
 
@N3buchadnezzar may I ask you a question?
 
7:24 PM
Sure?
 
Would anyone be willing to share their thoughts on a good measure theory text?
 
@N3buchadnezzar where did you learn Tikz? from a book?
 
I just did stuff, and asked when i got stuck
 
@dustin I liked Tao
 
7:26 PM
@Mircea I am looking for a book more than lectures online
 
@dustin then idk
 
@dustin sure
 
Nope @iwriteonbananas
 
7:28 PM
@user153330 I was thinking of updating that answer :p
 
@MikeMiller ayte
 
@N3buchadnezzar key thanks = )
 
Just draw an amount of pictures with a nonzero measure, then you will be a tikz-master.
 
@Chris'ssis oops wasn't there could you repost that last one ?
ok thanks
 
@Hippalectryon That one is a very nice integral. If you don't approach it properly, it will make you suffer. :-)
 
7:37 PM
I'm in the metric space $(\mathbb{R},d)$ where $d(x,y)=\frac{|x-y|}{1+|x-y|}$ and i have to prove that $I_n=[n,+\infty[, n\in \mathbb{N}^*$ is closed, is it right to take a convergent sequence $(x_k)\in I_n$ so $ x_k\geq n,\forall n\in \mathbb{N}^*$ then, $\lim_{k\rightarrow +\infty}x_k\geq n, \forall n\in \mathbb{N}^*$ i.e., $x\in I_n$ so $I_n$ ??
Thank you
 
@Chris'ssis Anyway, how goes the book ? How many pages already ? :P
 
Also this integral is pretty precious $$\int_0^{\pi/4} (x-\tan(x))^2 \ dx$$
 
@N3buchadnezzar lol advice loaded
 
Precious ?
 
@Hippalectryon hehe, I won't share these things now. :-)
 
7:41 PM
@Chris'ssis ok ok
negociations failed. next stage : spying
 
@Hippalectryon lol :-)
 
Anybody want to give any input on this problem? math.stackexchange.com/questions/1103069/…
 
@user153330 ? :p
 
oh
nevermind
 
7:45 PM
@MathyPerson Use the up arrow to edit messages
 
aha
got it
 
test Confirmed, [title](banana link)
 
7:47 PM
@N3buchadnezzar advice loaded = your advice is now installed in my head
 
:p goodie
 
lol
Any advice on this? Math.SE problem
 
@MathyPerson cry
 
hi people
 
@N3buchadnezzar already did
 
7:53 PM
@Sawarnik hiiiiiii
 
@user153330 hey :D
 
@Sawarnik how is it going??
 
@user153330 well what? :D
 
@Sawarnik wuuut????
 
Why Mathematica is not able to compute the value of $$\int_0^{\pi/4} \frac{\tan(x)}{x} \ dx$$?
 
8:02 PM
I'm going to sleep. Good night/day, everyone!
 
Maybe should I write them an email and asked for more details about this issue?
@Mircea Good night! Take care!
 
@Chris'ssis Thanks! See ya!
 
i have three problems left ahh
(in math)
 
@Chris'ssis Why does it seem strange to you ?
 
@Hippalectryon I don't see where is the difficulty, but maybe I miss some crucial points.
 
8:06 PM
@Chris'ssis There isn't a single one out there which can compute it, I believe
Except Sage, maybe. Let me check.
 
@Hippalectryon OK
@robjohn did you attend the integral above so far?
 
Do you have a nice form for $\int\cos(x^a)dx$ ? The usual one looks bad.
Sage is offline for me :/
sage
 
@DanielFischer If a set $X \subset \omega$ is bounded then $(\exists k \in \omega)(\forall y \in X) y \leq k$. If a set $X$ is not bounded, then $(\forall k \in \omega) (\exists y \in Y)y>k$.
I have I understood that $(\forall k \in \omega) (\exists y \in Y)y>k$ is the negation of the statement that has to hold when $X$ is bounded.. But could you explain me why $(\forall k \in \omega) (\exists y \in Y)y>k$ has to be true?
 
Ups, I have done something wrong here $$\int_0^{\pi/4} \frac{\tan(x)}{x} \ dx$$ (let me reconsider my calculations)
 
8:26 PM
@Chris'ssis eazy
 
@N3buchadnezzar Show me your way
 
@Chris'ssis I was thinking $\tan( a \arctan x)/x$
Lemme ponder
@Chris'ssis Darn. I was thinking abut $$ \int_0^{\pi/2} \frac{x}{\tan x}\,\mathrm{d}x $$
 
@N3buchadnezzar hehe, that's a different story :-)
 
Yeah, there $x = \arctan( 1 \cdot \tan x)$ works fine ;)
 
@N3buchadnezzar Yeap.
 
8:37 PM
@Chris'ssis Are you talking about $\frac{\tan(x)}{x}$?
 
@robjohn Yeah.
 
@Chris'ssis Well $$ \int_0^{\pi/4} \frac{\tan x}{x} + \left( \frac{\tan x}{x} \right)^{-1} \,\mathrm{d}x = ?$$ ^^
 
@N3buchadnezzar What do you mean?
I can do that, but I need to work some more, I have the whole way in mind.
 
8:55 PM
Hi everyone. Sorry if this isn't the appropriate place to ask, but I don't think it warrants its own question at Meta. What is the usual practice regarding questions like math.stackexchange.com/questions/851945 , which are easily answerable but very old, and the OP hasn't been active for 6 months?
 
Easily answerable?
 
rsz
hi all
 
hi rsz
 
@TedShifrin Maybe I misread. I thought the question was about ruler and compass constructions. Never mind.
 
@Espen: I have no clue whether there's any merit to the question or not, but I certainly have never seen anything about it.
 
rsz
9:08 PM
i am stuck with some task which i can't figure out, i think that there is something really simple in fact but can't get to it, if some of you guys could point me to something it would be helpful,
((2^63)-1) this is the number in base 10 which i would need to convert to base 16
i am thinking of converting the number somehow so i can get something reasonable, has anyone of you some idea about it?
 
If the only allowed operations are with straightedge and compass, it cannot be more expressive than the persian geometry which allows intersections of conics. It is known that this geometry can at most express 5th roots.
 
@rsz: Start with $2^{63}$. Can you figure that out in base $16$? Easier, what about $2^4$, $2^5$, $2^6$, ...
Well, no, @Espen, we can construct a regular 17-gon with ruler and compass, for example.
 
@TedShifrin But you are still limited to constructing field extensions of order $2^n$. Constructing a 7th root will give a field extension of order 7, right?
 
no, order $6$, still not a power of $2$, though. I'm just quarreling with your statement that you can't get past 5th roots. Gauss knew all this stuff :P
 
@TedShifrin When I said "past 5" I meant in the sence that 5 is the greatest prime divisor. I guess I didn't express myself clearly. :P
 
9:15 PM
I'm still confused, @Espen. What about 17?
 
@TedShifrin It has to do with constructible angles. The cosine of $2\pi/17$ can be expressing using iterated square roots.
 
I understand all that. I don't see how it fits with your 5 stuff.
 
rsz
@TedShifrin: i can deduct the fact, that the result gets always multiplied by two, but that what it should do, how can this help me?
 
What are the place values base 16, in terms of powers of $2$, @rsz?
 
@TedShifrin Argh, it seems I was confused. The geometry of conic sections does not support 5th roots. Only roots of order divisible by 2 or 3. The point still stands, though, that given a parabola in the plane, there is no way, using only a straightedge and compass operations, or taking intersections of conics, to produce a 7th root of unity.
 
9:23 PM
I don't know anything about using conics other than circles to construct points. I've never seen it discussed. Cool questions ...
 
It's actually suprisingly hard to find good treatments of it.
But this is one of them, it seems. math.cornell.edu/~dwh/papers/geomsolu/geomsolu.html
 
if the last two digits of a number are 00 does that mean it is divisible by 4?
 
well, Alex, is 100 divisible by 4? :)
Hi, btw
 
rsz
@TedShifrin i don't understand your question
 
yea 25
 
9:28 PM
@Espen: Thanks. I have one of Hendersen's elementary geometry books, but I don't think it's in there.
So, then any multiple of 100 will be divisible by 4, right, Alex?
 
yes i think so
 
@rsz: What is the base 16 representation of $2^4$?
wondering how I got stuck on algebra duty today
 
rsz
it's 10
 
And what is $2^8$?
 
@TedShifrin It's a shame. This is the kind of geometry that all 2nd year math students should learn. =)
 
9:31 PM
LOL ... We have enough problems with just basic stuff, even with most math majors, @Espen.
 
rsz
that is 100 in base 16
 
Teaching abstract algebra to 3rd and 4th year math students in the US, many of whom are going to teach high school, I discovered years ago they didn't know laws of exponents.
OK, @rsz. Now can we figure out $2^9$ or $2^{10}$?
 
rsz
yes those are like 200 and then 400 and the next one would be 800 and so on
 
ok, so, what is $2^{63}$?
 
@TedShifrin Wow! I think this is a common theme though. The curriculum moves so fast that most don't have time to become sufficiently intimate with the basics. I often find myself experiencing the same symptom...
 
9:35 PM
well, basics from elementary school is a bit depressing :(
 
That's true.
 
I'm teaching a senior-level differential geometry class and I have to remind students of basic trigonometry and first-term calculus.
 
Haha, they probably didn't think about those concepts after handing in their exams. :P
 
not to mention hard stuff like $u\cdot v = \|u\|\|v\|\cos\theta$ :D
 
(Full disclosure though, I conducted the geometry discussion above with my Galois theory book open...)
 
9:38 PM
Well, I've taught it a few times, @Espen :P
 
It's hard to compete with 35+ years in the business. :P
 
rsz
@TedShifrin the number is 8000000000000000
 
I'm quitting soon enough, don't worry :P
Right, @rsz. Now subtract 1 :)
You'll need your letters for (base 10) 10, 11, ... , 15.
 
hi @TedShifrin thanks for the help the last few days btw
 
Well, it was nice talking to you, Prof. Shifrin. I have to get back to writing my thesis.
 
9:41 PM
Have fun, @Espen. My pleasure too. I didn't know about cube roots with parabolas. Very cool.
Most welcome, Alex.
 
i also learnt divisibility rules
they are so useful
 
Yup
 
if it is divisible by 4 can i assume that it is divisible by 8 ? same with 3 and 9 ?
 
rsz
@TedShifrin thanks, i think i finally understood how to get to the result, all i needed to understand was the relation between the different levels i mean 2^2,2^3,2^4...
 
That's why I led you that way, @rsz :P
No, Alex. You have those backwards. If a number is divisible by 8, then it's divisible by 4. But 12 is divisible by 4 and NOT by 8.
 
9:50 PM
this is all for military selection process. so many speed distance time questions. learning the fractions has been the hardest part but im getting it now aha !
 
wow, well, it's good skills to have
 

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