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11:00 PM
@DanielFischer But don't the two parameters, the second and the third correspond to the interval of the positions of the array that shall be partitioned? Or am I wrong?
 
What are you doing with Fourier gadgetry, @Alex?
 
@TedShifrin I see you have also put on a silly hat!
 
IT was assigned to me, @Jasper.
 
I think @Alizter looks a bit like @PedroTamaroff, lol.
 
@JasperLoy Not really
 
11:03 PM
@evinda There are two ranges. a) the range we are interested in at the end, where the elements we want to select will be sorted to. And b), the range of the array that shall currently be partially sorted. The range a) remains fixed during the complete recursion, range b) changes in every call.
 
hi @Alizter
 
hi @TedShifrin
I got my report card today
 
@Jasper: Do you find that all white guys look alike?
 
@DanielFischer I see... but why does the range we are interested in at the end have to be a parameter?
 
@MikeMiller Are you still here ?
 
11:05 PM
Is that good or bad, @Alizter?
 
yeah @Hippa
 
@TedShifrin Not really. OK, my last approximation was a bad one.
 
Maths: A
Further Maths: A
Computing: A
Chemistry: B
Physics: C
 
@MikeMiller What is $x$ in your answer ?
 
it alright
 
11:05 PM
Where are literature and history, @Alizter?
 
@Hippalectryon Point in $K$ of minimal norm, @Hippalectryon
 
@MikeMiller I thought it was a coordinate of the closest point, but then you take its norm
 
@Alizter Why did you get B and C?
 
@TedShifrin I am very specialised at 16 years of age
 
11:06 PM
I messed up
 
I always thought math people should be interested in physics, @Alizter.
 
Sorry
Let me edit that
@DanielRust I don't understand why solenoids aren't a counterexample to this question. It seems to me I can write the multiplication-by-$p$ complex with simplicial maps.
 
@TedShifrin me too but I need to study it more
 
I'm opposed to early specialization :(
 
we don't even have a text
 
11:06 PM
nevermind - just saw your comment that they all have to be subgraphs of a finite graph
 
I can recommend an excellent text on mechanics for you, @Alizter.
 
@Alizter Wanna drop one subject?
 
@TedShifrin trying to figure out necessary conditions for a function to converge to the Fourier series of another function
 
@TedShifrin But you would not know their syllabus.
 
@JasperLoy I know that my chemistry grade will improve because I have literally only been studying chemstry
 
11:07 PM
Transform, I mean
 
Not my problem @Jasper
 
@evinda It doesn't have to be a parameter, you can also make that global variables. But the partial sorting function needs to know that range, since that decides whether a recursive call to the front or back part of the currently partitioned slice is necessary after partitioning.
 
@Hippalectryon Fixed
 
I need to study some physics as well
I guess I got bored of the linear equations already
 
@MikeMiller Nope not yet "Because x had minimal distance to the origin"
 
11:08 PM
@Alizter If you are going to study math in Cambridge, it will have a lot of physics.
 
I'm confused, @Alex: There's a sequence of functions? Converging in what norm?
 
@JasperLoy I have no problems with the mathematics.
 
@Alizter: Kleppner-Kolenkow is a fun and excellent text on mechanics, which fully uses multivariable calculus.
 
@MikeMiller each space in the limit needs to be a subcomplex of a single graph $G$ so in you example you'd have to have the number of edges you use to model the circle bounded by some $p^n$, but then the $n+1$st circle can't map simplicially onto the $n$th.
 
It is clear explanations that I suck at
 
11:09 PM
@Hippalectryon superfixed
 
@Alizter I just don't understand why you did so badly for physics when it is highly mathematical. Your teacher must be really bad.
 
@DanielRust Yeah, I noticed that.
 
@MikeMiller Thanks :)
 
There is intuition to be had for physics that is not just mathematics, @Jasper.
 
@JasperLoy I strongly dislike one of my physics teachers
 
11:09 PM
@AlexanderGruber how'd you get that box.
tell me.
 
You can hate me, too, @Alizter, but that doesn't mean you should do badly in my class :P
 
But I got an A in is class
 
@MikeMiller Actually I have a proof of the statement now. It's essentially an application of the same statement but in the category of finite sets. I should probably write it as an answer.
 
I got a terrible grade in the class that I enjoy
 
@DanielRust Prolly. I was just hunting for an unanswered question belonging to someone I know that I could actually attack.
 
11:10 PM
@TedShifrin the context is from probability, I've got sequence of characteristic functions (specially Poisson) and I'm trying to figure out under which conditions it converges
 
That sucks, @Alizter.
 
@TedShifrin I just have to work harder. Nothing else can be done
 
In $L^1$, in $L^2$, how?
 
@Alizter There are so many A level physics and chemistry books, just pick them up!
 
@MikeMiller haha, that's fair enough.
 
11:11 PM
@DanielFischer So don't we write the commands:
low=m/2-(p-1)
high=(m-1)/2+(p-1)
inside the function but we define them as global variables or give them as parameters to the function partialQuicksort?
 
The problem doesn't say but I'm guessing almost sure convergence would be fine
 
I dunno, @Alex ... This is beyond my current probability knowledge :P And my final is on Wednesday.
 
ah, found one. and the friend will even be available after office hours.
 
Wait that may have just answered my question
 
leaves @Mike to his scavenging
 
11:13 PM
Enjoy dinner, @TedShifrin
 
Bubye ...
 
@evinda Yes, these are computed outside the partial sort, and that computation is done only once. Then they are either passed a arguments, or stored in global variables.
 
@JasperLoy My school chose OCR physics B that doesn't have a textbook
mmmm first meal of the day
at 11pm
 
@Alizter Hmm OK. I thought you were using Edexcel all the way.
 
Not for physics
i am doing AQA for chem
just edexcel for math
 
11:17 PM
@DanielFischer Outside the first partial sort? If so, then we have to define them as global variables, right?
 
At least I am not failing discrete math again
 
@Alizter I did CIE, of course.
 
@MikeMiller In the second part, where is the hypothesis $K$ bounded used ?
 
I wish we could choose
But then there would be too little for teachers to do
 
@Alizter I wish we could choose the country and family to be born into.
 
11:18 PM
@evinda No, don't forget that the partial sort is called from the function that at the end selects the $p$ elements closest to the median.
 
@Hippa I didn't look at it closely, but I gotta leave something to you!
 
@TedShifrin I imagine that you are not the kind of teacher that teaches from powerpoint?
 
@MikeMiller :/
 
@Alizter I think powerpoint for math and science really sucks.
 
Never seen a powerpoint in maths
but all my physics lessons are slide show readings
 
11:20 PM
@Alizter I don't know any math professors that use PowerPoint for their lectures.
 
You'll see plenty of powerpoint /beamer presentations at seminars/conferences
 
I wonder who my secret upvoter is.
@MikeMiller Don't they use beamer?
 
I hate learning from powerpoint.
 
@DanielRust I think I will use powerdot and not beamer.
 
They are ideal for conferences/talks but silly for teaching
Also being forced to copy from them is silly
 
11:22 PM
@MikeMiller Harald's answer/hint seems logical "graphically" but I can't make it into a proof
 
I do have the advantage that I type pretty fast so I can dictate the teacher sometimes
 
Most people use pgf, pgfplots and beamer. I prefer pstricks, pst-plot and powerdot, lol.
 
I still don't understand how some people type their notes up on a laptop instead of hand-writing
 
@DanielRust They must type really fast. Maybe all latex experts.
 
@JasperLoy I don't know anyone who doesn't teach from the board.
 
11:23 PM
@JasperLoy Yeah I don't know
 
horray 80wpm
 
I had one lecturer at undergrad who would just talk through his beamer slides, but not upload them for the class. So you ad to basically just copy the slides verbatim.
 
@DanielRust I can't do it in maths. If I use latex I might get away with it but I prefer to write in maths
 
@DanielFischer We have this:
partialQuicksort(A,p,r){
if p<r{
k=medianofMedians(A,p,r)
q=hoare(A,p,r,k)
low=m/2-(p-1)
high=(m-1)/2
if (q>low) partialQuicksort(A,p,q-1)
if (q<high) partialQuicksort(A,q+1,r)


When we pass low and high at partialQuicksort after having calculated them, we have to pass them also at the initial fuction.


Or didn't you mean this?
 
Blackboards have information cycle through however powerpoints clear everything so it is hard to keep up.
 
11:25 PM
@DanielRust That is so silly.
 
I'm not a big fan of projectors but they are like a lazy white board.
 
Startin to look like I should change my name to Alexander Fischer.
9
 
They are not that bad
 
@AlexanderGruber heh.
by the by, tell me how you got the box.
 
Who knows. @DanielFischer might have a sudden storm of downvotes
 
11:28 PM
my guess's been editing or answering old questions, but either mine haven't been old enough, or i haven't done enough
 
Damn it @Daniel! Why did you help me!
I would of loved to run for mod
but I have no time
 
@AlexanderGruber Are yer fishin fur sumethin?
 
@MikeMiller At least give me a hint on the hint :/
 
Also it is a rule that the winners are the top X users with the highest rating. Here X is the number of moderators required.
 
Today is day 94 consec
 
11:30 PM
@evinda The low and high should be parameters.
 
Apparently the primaries are very coarse in terms of it's predictive accuracy
 
@N3buchadnezzar That's only an informal rule.
 
@MikeMiller Editing is correct. Pick a cluttered / misused tag, and clean up some old posts from it. I'm not sure that tag-only edits count, but there's usually an opportunity to fix something in the post itself along the way.
 
@DanielFischer So, should it be like that?
low=m/2-(p-1)
high=(m-1)/2
partialQuicksort(A,p,r,low,high){
if p<r{
k=medianofMedians(A,p,r)
q=hoare(A,p,r,k)
if (q>low) partialQuicksort(A,p,q-1,low,high)
if (q<high) partialQuicksort(A,q+1,r,low,high)
 
11:31 PM
@DanielFischer Tounge in cheek comment. That is the standard, but not a standard I am particuarly fond of. Cough gone cough
 
burps
 
Current challenge: figure out how to type a good question in Android app without killing myself.
 
@Arkamis I voted for you, buddy.
 
@Behaviour Don't do that.
It's masochism.
 
@PedroTamaroff I think I'll type it on the desktop, email to myself, then copy and paste.
 
11:35 PM
@Behaviour Oh God I know, me too
 
@Behaviour Hehe, that seems roundabout.
 
@TedShifrin are you here?
 
@DanielFischer Also, here:
if (m%2==1) m=A[(m-1)/2];
else m=0.5*(A[m/2-1]+A[m/2])
left = (m-3)/2;
right = m/2+1;
if (m%2==1) count = 1
else count = 2;
while(count < p) {
++count;
if (left < 0){
++right;
continue;
}
if (right >= m){
--left;
continue;
}
if ((median-A[left]) < (A[right]-median)) {
--left;
} else ++right;
}

shouldn't we save at m the position of the median element?
 
Or am I wrong?
 
11:36 PM
^ WAAT ?
 
"Question: What would compel anyone to type Mathjax on a phone?"
 
@Hippalectryon I clicked. I hate hats
 
is there an app for these chat rooms, or do you use a mobile browser?
 
"Answer: Hat."
 
@Alizter :/
 
11:37 PM
@Hippalectryon CBA
 
What's CBA
 
Can't Be Asked
 
@MikeMiller I edited an old post. Really can't believe there's a badge for that
Hat*
 
Those 25 hats in a row though
 
@Hippalectryon Let $\varnothing$ denote how much I care :P
 
11:38 PM
@Alizter: Not even from my grave.
 
@AlexanderGruber I can believe it. Anything to make people edit posts other than their own... at least once in a year or so.
 
@Alizter :)
 
@TedShifrin Well yeah. Most of physics is taught like this.
 
@Behaviour but that's the beautiful part, it was my own post
 
But why blame the teacher? The student is obviously bad and should improve
 
11:40 PM
Not by the good physics teachers here ... @Alizter
 
@TedShifrin $F=ma$. HA!
 
Maybe there should be a hat for spam upvoting an alternate account, too.
 
@PedroTamaroff F= (mv)'
 
Force is the change in momentum
 
@TedShifrin remember when I asked if an invertible continuous $f:S^n \rightarrow S^n$ must have degree 1 or -1? You suggested that there is an answer to math.stackexchange.com/questions/1064763/… , which I haven't found yet. However, there's a different approach that seems to work.
 
11:41 PM
@JasperLoy From far away, you look like a floppy disk.
 
momentum is the change in kinetic energy
 
@Alizter Wrong. The rate of change of momentum.
 
@JasperLoy that is what i mean
 
@PedroTamaroff I used to be very handsome, but I have become old and ugly now.
@Alizter Now we know why you got C.
 
@JasperLoy You're not even 40.
 
11:42 PM
@JasperLoy Basically from stuff like that
 
@Alizter Exactly.
 
I've been too busy to ponder it, @cxseven.
 
Hurrdurr strong, stiff are the same thing
 
@TedShifrin by invariance of domain and the compact hausdorffsness of the domain and range we can assume the function has an inverse
 
today I learnt about Lagrangian multipliers
 
11:44 PM
continuous inverse, yes. Then done.
teach @Pedro, @Alizter. He's stubborn.
 
@TedShifrin if we then approximate $f$ and its inverse with smooth versions, the composition of the smooth versions is within an arbitrarily small distance of the identity map
 
Oho epic new avatar :3
 
@AlexanderGruber There's definitely not - I would have gotten it within minutes, of course.
 
Hi all
I asked a new question
0
Q: Why is this integral $\int_{-\infty}^{+\infty} F(f(x)) - F(x) dx = 0$?

mickLet $a_n > 0$ and $b_n$ real. Let $f(x)= x - \sum_{i=0}^{\infty} \dfrac {a_n}{x+b_n}$ Now apparantly for every function $F(x)$ : $$\int_{-\infty}^{+\infty} F(f(x)) - F(x) dx = 0$$ If the integral converges. Why is this true ? I considered contour integrals and substitution but found no pro...

 
you don't need anything smooth, @cxseven.
 
11:45 PM
@TedShifrin and since the degree of a composition is the product of degrees, and the identity has degree 1, the smooth version of $f$ must have degree 1 or -1
 
maybe you can help with it
 
Use homology, @cxseven.
 
@mick Can't vote anymore today sorry
 
r9m
shamelessly asks for a hat ;) .. just a (+1) here and I'll get a new hat ! :D
 
@TedShifrin what exactly from homology?
 
11:46 PM
@mick I would have loved to downvote your question though kidding :)
 
Defn of degree, @cxseven
 
Good night/... everyone
Don't get eaten by Ted
 
Bonne nuit, @Hippa.
 
@TedShifrin I haven't read much about homology
 
Oh, then how did you define degree, @cxseven?
 
11:49 PM
@Hippalectryon sonic !!!
:)
 
either take a suitably close triangulation or smooth approximant and look at a ray that passes through a nice region
 
goodnight all
 
What with triangulations?
 
with triangulations you look at the orientation of simplices
 
You're doing PL transversality?
 
11:51 PM
Bah I feel stupid whenever i ask a question on MO.
 
i don't know what that is
 
And then?
I asked one, @DanielRust, and Robert Bryant, a very smart old friend, made me feel like you. ;)
 
@TedShifrin The answer is always with so much authority and seemingly effortless. Maybe one day I'll not be intimidated by it :P.
 
and then what? you triangulate $S^n$ so that each simplex is within a small enough epsilon ball to keep the to-be-described calculation invariant, and look at the image of those simplices
specifically the image of the points of each simplex
 
So if it's a homeo, you get $\pm 1$ immediately?
 
11:56 PM
no, i'd argue something within a certain distance of the identity function has degree 1, and then that a composition of maps has a degree which is the product of the degrees of the individual maps
 
It can be far from the identity ...
 
@DanielFischer I have to go to sleep now... Good night!!!
Good night to you all!!!
 
an injective continuous $f:S^n \rightarrow S^n$ has a continuous inverse
 
I feel stupid all the time, @DanielRust
 
surjective due to invariance of domain, and continuous inverse since the domain is compact and range Hausdorff
 
11:58 PM
@MikeMiller I feel extra stupid because the answer I was given referenced two papers.... both of which I was reading earlier today...
 
ouch.
 
Ah, ok, @cxseven, although I have no idea how you proved that.
 
In fairness though they're papers in a subject I'm not comfortable with yet
 
@TedShifrin which part?
 

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