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10:00 PM
@Alex is sick of the drama I induce :)
 
@TedShifrin HOW TO FIX LE PROOF
 
yeah yeah yeah its removed :)
 
I told you, @Balarka: You need $r$ smaller than what?
 
still find it funny though , will watch it again :p
 
10:01 PM
$d(x, A)$
 
Yup. Is that positive?
Not duh.
 
YES, as $A$ is closed, @Ted.
 
Yup. Takes proof.
 
@UserX how to do what? Using the reference arrows helps.
 
Right. Thanks Thunks @Ted
 
10:03 PM
@UserX Teach what you know not what you don't know.
 
Yup.
 
@Alizter I'm not teaching anything. Just wanna make a point. @robjohn an integral Ted told me
 
@UserX which integral?
 
oh well my point didn't get across. Back to number theory.
 
@Alizter from my notes? :P
 
10:05 PM
10 mins ago, by Ted Shifrin
$\int_9^1 dt/\sqrt{1+t^3}$, @UserX
 
Lower limit is 0
 
@BalarkaSen Topology pun?
 
uh?
 
@UserX ah... the mistakes get copied, too
 
But yes
 
10:06 PM
Defiance is a great movie. I just watched it on TV.
 
Definance would definitely be a hit
 
@JasperLoy Who watches TV anymore when you have math books?
 
@UserX Looks like a Beta function to me...
 
@Alizter LOL =)))))
 
People will loose all their money watching Definance for sure
 
10:07 PM
I still tell people that I will start watching breaking bad soon.
Not too in with the meth thing you know.
 
breaking bad?
 
@robjohn let me ask this once again. I wanna show to a high-schooler that definite integrals can be evaluated without finding an antiderivative and using the FTC too
 
@BalarkaSen google is your friend
The west seem to like it a lot.
 
So I'm searching for the perfect example
 
@Alizter Oh it's a movie
 
10:09 PM
And no, Gaussian functions aren't taught in high school
 
Well meh
 
tv series
 
whatevs
 
@Alizter tv is cheaper
 
innit
 
10:09 PM
@BalarkaSen just as with everything else huh
 
@mick So is chess compared with smartphones.
 
@robjohn can you think of anything?
 
I feel like I should be using @Ted for some learning. But what to learn...
 
i don't have any phone. decided that i'll never ever get one for myself.
too phony :P
 
@BalarkaSen That is ok if you don't leave the house all day.
 
10:11 PM
anyone who wants to contact me has to mail... and be patient.
 
@Alizter i play chess and watch tv ... so ?
 
sigh @mick too tired to explain again
 
Every comment that says Chris's Sis is arrogant gets highly starred. This is absurd.
4
 
@Alizter goodnight ! :)
 
@JasperLoy oops missed
 
10:12 PM
@JasperLoy Every comment saying anyone is anything gets highly starred
 
@JasperLoy happy ?
 
Jasper is silly
^ star it
 
@BalarkaSen happy ?
 
no. let's not get star-crazy
 
@Alizter :p
 
10:13 PM
@mick Stop staring everything.
 
@Alizter but they asked for it !
:)
star this :p
 
oh noes
 
lol
 
Is Chris's sis really the sister of a Chris?
 
It was Chris before
 
10:14 PM
@UserX You want something that you can't do by FTC, but you can do by some neat substitution?
 
@UserX how about the arithmetic-geometric mean ??
 
@robjohn I don't understand. If you substitute a value then you'll eventually use the FTC.
 
moderators are unstarring i guess
 
yes
 
Children stop.
 
10:16 PM
@robjohn it's clear what I want. An example understandable by a high-school student that evaluates a definite integral without the FTC
 
Is something pedro would say
 
43 views , still no upvote !!
@Alizter yes daddy
 
@Alizter no that'd be STAHP
 
@Alizter He would say STAHP.
 
jinx, @Jasper
 
10:17 PM
@mick someone downvoted lol
 
@Alizter you ?
 
@mick no. I don't care for your question.
 
@Alizter euh .... thanks .... euh no , no thanks
throws table at downvoter ! :)
 
It is two more months to Christmas. I am so excited.
 
@mick Seldom is a custom-made problem interesting to others
 
10:19 PM
things are Always intresting , they just fail to see it ....
thats why i dont downvote !
 
@JasperLoy What do you want Santa to bring you?
 
@Alizter i want a proof of collatz
im silly.
 
@Alizter Hmm, too private to say in this chat, LOL.
 
Back to primes
 
@JasperLoy womenizer ? :)
 
10:23 PM
I have many things I want for myself and also for others.
 
@JasperLoy how cute
 
12 holy books?
 
My greatest wish would be to solve my mental problems soon and live a normal life.
@Alizter I already have those in my shelf.
 
for others, for others
 
Ah, there is something I want to do for others that could get me into trouble with the authorities here...
It is something morally right but possibly legally wrong...
 
10:24 PM
Streak?
 
MSE is no fun when your questions get ignored :(
 
@jasperloy go on
 
@Alizter I don't know what a streak is, but I won't say it here, LOL. When my best friend returns next month, I will discuss with him what I should do about the matter.
 
@mick Stop reminding us. Edit it properly or something.
 
@Alizter its a good question by itself.
 
10:25 PM
 
@mick Noone said MSE is fun.
 
@JasperLoy It is the process of expressing your self by running butt naked in a public area.
 
My 12 holy books by the way cost over 1000 USD.
 
Plus, it's a community network. Ask why does 1+2+3+4+... =-1/12 and you-'ll get more attention
 
@Alizter What does running around naked achieve? Nothing. It is stupidity.
 
10:27 PM
@UserX -1/12
 
@JasperLoy Apparently freedom. Haven't been seeing these results lately.
 
Edited
 
@mick What balarka said
 
@JasperLoy its to express that the event should not be taken so seriously !
 
@Alizter If I have something to say, I would say it without running around naked.
 
10:27 PM
@JasperLoy It is something that sometimes happens at sporting events.
 
I think more girls should do it :)
 
Taken out of context it is a bit crazy.
@mick Why is that?
 
@Alizter That will definitely put me into jail for 2 months here.
 
@Alizter take a wild guess :)
 
@JasperLoy But it is morally right and illegal. Thus your condition is satisfied. Now take $\epsilon > 0$ and let $f\in$...
@mick Hmmm. Nope. What?
 
10:29 PM
@Alizter Are you and Sarah discussing your math problems now?
 
@JasperLoy She has not sent me a single email since last week
Wasn't she here yesterday or the day before or something?
 
@Alizter Hmm OK. I guess she is a busy person. I am very free. But next year I should be very busy. I would be happy to finish 6 holy books next year, but hey maybe I can do all 12.
 
@JasperLoy One for each month?
 
So you guys keep pinging ME when you chat up @Chris'ssis.
6
Because you write "Chris sis" or some such.
 
LOL @Chris
 
10:32 PM
Please cease and desist.
 
@Alizter Yes, if possible. I intend to do nothing but math every day from morning to night next year.
 
@Chris change your name to bob or something :P
 
No, screw you. I had this name first.
 
@JasperLoy Don't forget to sleep and eat.
 
No, seriously guys, let's star that.
He shouldn't get pinged for no reason.
 
10:33 PM
@Alizter Of course, I will also need time to solve my mental problems next year, and some time for window shopping as well.
 
@Chris Ok. Don't complain when we are too lazy to write sis.
 
ty @BalarkaSen
 
Testing. Does @Chris'ssis ping Chris?
 
ok this might sound hostile and arrogant and more stuff like that , but , if you think its so easy to improve my question , why dont you guys edit it ?
but keep in mind that x > 0 is essential.
Apart from changing the order of the sentenses/def's of the question i doubt it can be improved alot !
 
Hold, please.
 
10:34 PM
@chris Can you answer my above question?
 
No new pings.
 
@mick we are trying to help you not lecture you.
 
yes , but like I said apart from maybe relocating x > 0 I do not see how to improve the question alot. " improve " is vague advice ...
If someone asks : how to jump higher ? and you answer " improve your jumps " , that does not help much ...
for instance : adding context ... there is no context to add !?
also adding incorrect tag's seems immoral to me.
its not a bessel function !
 
@mick Alex and I were telling you OUR opinions on what would make the question more popular. Since you are too stubborn to do anything I cannot help you.
It looks like bessel function
$J$ is used for bessel
 
but its not ...
 
10:37 PM
why not name it $f$?
Who is going to know that?
I called my dog cat. But it is actually a dog sorry guys.
 
do you really believe f will get more attention then J ?
 
People will think your dog is a cat.
poor notation
 
Your notation sucks!
 
Calm down Balarka
 
As Lang used to say
 
10:39 PM
Lang invents his own terminology in his books.
 
I Always learned in class that you can " choose any letter you want " :)
 
For example, calling a ring entire.
 
@BalarkaSen Pressure notation in physics sucks. Badum tss
 
@Chris'ssis: I've added about all I can to my Soddy-Gosset answer. The first section is straight from my paper of 5 years ago, but the later sections are improvements on the later sections there. I am pleased with $(21)$ and $(22)$; they have a nice feel to them. I might rewrite the paper using that answer.
 
@mick Yes. You can also call your dog "cat".
But is that a descriptive name?
 
10:40 PM
nothing is worse than $$\frac{\Xi}{\overline{\Xi}}$$ on a blackboard :P
 
ok i will call it " f " then.
 
@robjohn You published 5 years ago, outside of academia? That's amazing. I only have toilet paper.
 
When you tell someone, my "Cat" barks what will they think?
 
@JasperLoy can i borrow it , im out.
 
@mick Have a nice time shitting bro.
 
10:41 PM
@Alizter that it is not math you are talking about :p
 
@JasperLoy Never published, except by mentioning it on sci.math. With the new additions, I might try ArXiv
 
@JasperLoy euh thanks :)
 
sigh Spanish accent: How do eiy reeech dees keeeeds?
 
Look, if you have the guts to star something, don't be a wuss and unstar it, lol.
 
@robjohn where is the paper you talk about ?
 
10:42 PM
Good night all
 
ahem I'm the wuss you are talking about, @Jasper
 
except for mick
mick can fix his question
 
@Alizter See you in your dreams!
So I figure that at chris pings chris'ssis and at chris'ssis pings chris as well?
 
I'm gonna go too.
Byes.
 
10:43 PM
@JasperLoy It is not symmetric
 
Then there is no real solution to the problem, we need a nonreal solution.
 
chris -> chrissis & chris,
bye
 
lol , i replaced J by f ... and now i noticed i commented about J , not f and that cannot be undone :p
 
I just deleted an answer I wrote because I think it may have been erroneous
 
may have?
 
10:48 PM
but I'd like to check here: Is the least upper bound property different than having a least upper bound?
 
yes
 
Ok. It was definitely erroneous.
 
The property asserts that every nonempty set that's bounded above has a least upper bound.
 
@robjohn: did you think of anything new regarding that Fourier series / series summation question that came up? if there's not something obvious i was planning put a new question together
 
Ah, alright. I was unaware of that, and answered as if having a least upper bound and having the least upper bound property were the same thing.
Oh, also, Ted, thanks for your help the other day (a couple of weeks ago, you helped me out w/ some tensor stuff)
 
10:49 PM
There are plenty of ordered sets in which the least upper bound property does not hold.
You're welcome, @Amagical. In the meantime, I've had plenty of downvotes for no good reason, so I'm glad :P
 
Haha. Well, I'd upvote you in chat if I could!
 
Ha ha
 
Is there a way to canonically well-order $\mathbf{Q}_p$? Just askin'
 
there's rarely a natural/canonical well-ordering, @Balarka. Do you have something in mind?
 
Nopes. Thus my question.
 
10:53 PM
What is $\mathbb{Q_p}$?
 
Ah, the 5000 dollar question.
 
$p$-adic rationals, @AmagicalFishy
 
You'll need to explain, methinks, @Balarka.
 
@Semiclassical You might as well put up a new question. I haven't come up with anything, and I need to leave for a while
 
hi @robjohn
 
10:54 PM
ok, thanks
 
@TedShifrin hey, Ted!
 
fractional field of $\mathbf{Z}_p=\{(x_i) \in \prod \Bbb Z/p^i : x_{i + 1} = x_i \bmod p^{i+1}\}$, @Ted
 
did someone post the integral discussed here before on main ?
 
Explanation would be excellent, actually (I am also reading the Wikipedia)
 
@Ted Fun fact: The smooth Poincaré conjecture is true in dimensions 12 and 62.
 
10:55 PM
@mick The one that Chris's sis and I were discussing?
 
Huh? I thought the smooth Poincaré conjecture was true in all dimensions $\ge 5$.
 
@robjohn yes
 
@mick I don't think so... I think we were just discussing it on chat.
 
@Ted That would contradict the existence of exotic spheres, of which there are lots. Topological is true in those dimensions.
 
it was not that difficult
 
10:56 PM
pity
but nice still
 
Hmmm, my h-bordism is rusty.
 
Do you have a quick sentence on their significance, Balarka? (Just so it sticks in my mind what they are. :v)
 
@TedShifrin you should have painted it...
 
yeah, along with all those wanton downvotes, @robjohn ... which continue. I think somebody's afoot.
 
@AmagicalFishy i'm not sure what you want
 
10:57 PM
p-adics are totally not intuitive
 
Let f(x) be an elementary nonrational function
is the integral of f(f(f(x))) ever possible in closed form ?
 
@TedShifrin I have some info that I can pass on to the community managers and see if there is something they can do
 
@TedShifrin i don't agree with you.
they are intuitive if realized as cantor sets
 
I mean indefinite integral
 
thanks, @robjohn. Not like I can't afford the rep. It just offends me. I put a comment on one of the answers asking the downvoters to complain what's wrong ... of course, they won't.
 
10:59 PM
maybe a hard question of me
 
Sort of, @Balarka.
 
@AmagicalFishy The reals are a completion of the rationals with respect to a certain natural norm . But there are other ways to complete the rationals (and get a complete field); these other ways give you the p-adics. They look very different than the reals!
 
@TedShifrin Oh, I understand. I remember when the mods were being targeted, and then I was when the others were not. It is frustrating
 
@MikeMiller bunch of names :P
 
@BalarkaSen: can you elaborate on that? it sounds familiar but p-adics aren't something i know in depth
 
11:00 PM
I still wonder if René has friends he's put up to it, @robjohn :D
 
goodbye friends ...
 
@Semiclassical inverse limit of the canonical inverse system of p^k-cyclic groups
 
When he gets off suspension, I'm sure fireworks will start.
 
@MikeMiller Ah! I had no idea that was even a thing.
Thanks. :D That's awesome
 
whats an inverse limit ?
 
11:01 PM
LOL ... indeed ...
 
for example you have $x^2 = -1$ if you have a solution mod 5^k, you can extend that to a solution mod 5^{k+1} by hensel's lemma
 
@Balarka: You're throwing around jargon. It doesn't help non-experts.
 
(I'm not sure what Hensel's Lemma is)
 
bye
 
OK, dinner guest is here. Bubye, all. Thanks, @robjohn.
 
11:02 PM
@TedShifrin I know I am, I can't possibly start lecturing about basic algebra RIGHT AT THIS MOMENT
 
it's the thing that says you can lift solutions in the way balarka just described (don't mean to be circular, but that's pretty much it)
 
@TedShifrin L8r
 
(Consider this: I am now taking Real Analysis, so I know how to complete the Reals, and that's about it. :P)
 
i think what i'm reaching for in the back of my head is the connection between cantor sets and stuff in symbolic dynamics
 
@AmagicalFishy OK, then look for the p-adic metric.
 
11:03 PM
So the idea of there being other ways of doing it that fruit totally different numbers is crazy
 
which admittedly i'm struggling to remember from a dynamical systems class at least six years ago
 
it's the metric induced by norm $|x| = p^{-k}$, $p^k$ being the largest prime power dividing $x$, @AmagicalFishy
 
so i'm probably talking nonsense :P but i know in that course the notion of different metrics came up
 
that gives you a metric space $\mathbf{Z}_p$
you can also show that it's a field. then take the fractional closure.
a bit of background always helps the helper, @AmagicalFishy
 
actually, looking at wikipedia, i might be remembering sort of correct
 
11:05 PM
@BalarkaSen integral domain, fraction field
 
Sorry 'bout that. (I'm writing down what you're saying so I can do it later tonight)
 
@anon whatevs
 
@Ted We know as a corollary of hCob that if a n n-manifold is homotopy equivalent to an n-sphere, it is indeed homeomorphic. So the smooth Poincaré conjecture is equivalent to the question of whether or not there are exotic spheres in dimension $n$... and it's open when there are.
 
@AmagicalFishy first try showing that the norm i wrote above is really a norm on $\Bbb Z$
 
Thanks, though; this will give me some good stuff to do :D
 
11:07 PM
just found this while searching google
not sure what the hell to think of it
a paper with the title "Human subconscious as a p-adic dynamical system."
 
ROFL, @Semiclassical?
 
Excellent. Show that $|x| = p^(-k)$ is a norm which gives the space $\mathbb{Z_p}$, show $\mathbb{Z_p}$ is a field, take its fractional closure
 
yeah, i dunno
 
@AmagicalFishy no, show it's an integral domain
i typoed, anon corrected
 
as an analogy, it might be a cute one
as a paper? riiiight
 
11:09 PM
Ah! Alright, thanks
 
Actually @AmagicalFishy this should be easier :
 
that would have resulted in some frustrating futility
 
Define $|\bullet| : \Bbb Q \to \Bbb R$ as $|x| = p^{-k}$ where $x = p^k \cdot m/n$, $m$ and $n$ are not divisible by $p$
Show that $|\bullet|$ is a norm. Derive the corresponding metric.
 
@BalarkaSen: btw, here's the line from Wikipedia that caught my eye (and which seems vaguely familiar)
from the page on subshift maps of finite type: "A variety of different metrics can be defined on a shift space. One can define a metric on a shift space by considering two points to be "close" if they have many initial symbols in common; this is the p-adic metric. In fact, both the one- and two-sided shift spaces are compact metric spaces."
 
The metric completion of the metric space $(\Bbb Q, |\bullet|)$ is our $\mathbf{Q}_p$, @AmagicalFishy
 
11:11 PM
the completion is Q_p
 
thanks anon
 
here to help
 
@anon right. sorry.
 
Very excellent.
This will probably show up as a question on the site in a couple of days, haha. Thank you. :)
 
glad to be of no help
gah why am I even helping with my stupid jargon-talk whereas i should get back to topology.
 
11:14 PM
You helped a lot! I meant, if I get stuck during one of the steps or want to verify that I've carried them out well
I'd post it as a question
 
@MikeMiller I studied Baire category today
 
@AmagicalFishy Just be careful with how you do completions; it won't make sense to use the Dedekind cut approach here. You need to think in terms of Cauchy sequences.
 
Noted!
 
@Mike you never say hello to me. blah. am i that (mathematically) silly? :P
 
11:50 PM
One of the answerers there comments that the question is not a duplicate, but answers only the duplicate part. Hm.
All answers only answer the duplicate part.
 
part of what's weird is that the title isn't really reflective of the question
as in, it should really be: "Are there infinitely many $n$ such that $\phi(n)=12?$"
otherwise, judging by title alone would seem to clearly indicate that it's the same question
 
@BalarkaSen I was in a seminar...
 

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