« first day (653 days earlier)      last day (4360 days later) » 

12:12 AM
@robjohn Are you beta-testing Davide's mathjax extension?
 
@BillDubuque which extension is that?
 
13
Q: A prototype for incremental preview updates

Davide CervoneOverview StackExchange's live-preview-with-$\rm\LaTeX$-support gives you the ability to see your mathematics properly typeset as you compose your post, but it has some drawbacks (as everyone who has edited anything substantial on the site knows). In particular, the fact that the entire question...

 
@BillDubuque Ah, I didn't see that. I will have to install GreaseMonkey.
 
12:32 AM
Hey, silly set theory question here. $L_{\omega} = \omega$ right?
 
@anon: I finally came across a real question today. I don't think my answer will get many votes since it requires knowing some inversive-geometry :-)
 
Hmm, I'll check it out.
 
@anon You and Srivatsan are the only ones that I know have talked about inversive-geometry.
 
I just checked and there are 12 tagged questions on the entire site.
 
pretty low count :-)
 
12:39 AM
Apparently I need to tag mine that way. I'll do that later when I reminisce sometime.
Well, someone upvoted you just now
 
I can't find a single post about "analysis situs" on this site.
 
@anon whee!
 
I'm failing to understand the top-right circle.
 
@IsaacSolomon these supposedly mention it: 1 2 3 4
 
@robjohn, I'm not sure if I'm impressed or confused.
 
12:46 AM
@IsaacSolomon why would you be either?
@anon lemme look
 
I meant it as a poor joke, and then, in classical MSE fashion, received a thorough answer.
 
@anon The top right image is the top left image inverted through the point $Q$
The blue and green circles are added
 
wrt what circle around Q? An arbitrary one?
 
@anon arbitrary, they are all the same up to scaling.
the circle $C$ is mapped to a line since $C$ passes through $Q$
 
What are the blue circle and the vertical line?
 
12:52 AM
the vertical line should be labeled $C$
 
wait nvm
 
The blue circle is added to find the inverse of $P$ across $C$ ($I$)
Then the rest of the answer deals with constructing the blue circle.
 
"blue circle on the left" I think you mean your other left :P
well, left side of the circle, nvm
 
I meant the blue circle when mapped back to the left.
It doesn't show up until the diagram below
 
Man, I just am not in geometry mode right now.
 
12:56 AM
Perhaps I need to rework some of it to be clearer.
It is hard to describe since we are working in two spaces at once (normal space and inverted space)
It's like dealing with functions and their fourier transforms.
except here there are lots of players on each side.
 
1:21 AM
off to the park bbl
 
Does anyone care to explain math.stackexchange.com/a/145277/22144 to me? I feel like the issue is that it's inherently ignoring the idea of induction. A'' isn't ensured to be of all the same age.
 
@l
@Limitless, the problem is that, when n=2, a_2 doesn't belong to A'
No, I should say -- When n=1, a_2 doesn't belong to A'
 
@ablmf wait, why is that?
 
When n=1, A'= {a_1}, A'' = {a_2}
So, the statement that a_2 belongs to both of them is false.
 
Could you say that since A'' excludes a_1, the induction isn't possible. (You're metaphorically removing the first falling domino, so no dominos can begin to fall?)
 
1:36 AM
I think your metaphor is OK.
But you need to understand, to make the induction work, every domino has to be able to push done the one behind it.
 
Yes. I use understand that. That's what inspired the metaphor. The metaphor allows me to see the structure of the argument beyond words and ideas, if that makes sense.
Subtract "use" from that.
 
 
1 hour later…
3:06 AM
aww... one of my answers was migrated to physics :-(
 
@robjohn Which one?
 
@PeterTamaroff this one
 
BTW, can anyone help me out here? This is a question of mine that hasn't received an anwer, and it doesn't seem too hard.
@robjohn I see. Do you have an account in physics?
 
@PeterTamaroff nope.
@PeterTamaroff consider the $\log$ of both sides of $\frac{t_i}{t_{i-1}}=\text{constant}$
 
3:25 AM
@robjohn That was it! I feel like cursing now. I was thinking about $\exp$, but it is clearly the same idea, just you hit the nail in the head. Thanks for that.
 
Your integral is $\int t^{p+1}\frac{\mathrm dt}{t}$
that is a R-S integral
(because $dt/t=d\log t$)
 
@MarianoSuárezAlvarez Right. That is what robjhon is saying I suppose. The integrator is the logarithm. That is the idea of the problem right?
 
and $\log(t_i)=s_i$ brings these together
 
that "integrator" is pretty well-known: it is the Haar measure for the multiplicative group $(0,\infty)$
 
@MarianoSuárezAlvarez $\Huge ? $=)
@robjohn Yes!
 
3:29 AM
you'll learn what that means in time :D
 
@MarianoSuárezAlvarez It is super mean to throw that out like that and not explain it, at least a little bit!
Is it really that complex?
 
no, but it is pointless :)
at this point, it will only be mumbo jumbo
 
@MarianoSuárezAlvarez I see. Does "multiplicative group" have anythingto do with a "group" in algebra?
 
every locally compact group has a unique left-invariant measure, and $dt/t$ is that measure for the group $(0,\infty)$.
sure
$(0,\infty)$ is a group under multiplication
 
@MarianoSuárezAlvarez Right. I follow that.
I really don't know about measure theory. $\mu$i**da!
 
3:32 AM
the usual integral on $R$ is the Haar measure for the additive group
that is why all this is mumbo jumbo
 
@MarianoSuárezAlvarez Is measure theory studied in general in the mathematics career or is it an optional course?
 
real analysis here is basically integration theory
and that is, more or less, measure theory
 
@MarianoSuárezAlvarez OK. BTW; I have the first Analysis midterm next wednesday!
 
@MarianoSuárezAlvarez Yeah. Our professor tried to spook us today into studying, but I guess I'll be fine.
 
3:36 AM
haha
well, we all have to do that :D
 
@MarianoSuárezAlvarez I guess so! He said he corrected exams and had to put $0$ as a final mark. Has it ever happened in higher levels to you?
 
@MarianoSuárezAlvarez I supposed so.
 
i have a challenge: i wish for someone here to convince me something has been proven by induction.
i am quite willing to allow a great deal of lattitude in "what" has been proven.
 
3:52 AM
@DavidWheeler Let's see-
 
i have plenty of time :)
 
4:07 AM
it's not so easy as it seems, i fear
if you allow the "principle of the excluded middle" and the existence of a well-ordered infinite set, then the well-ordering implies the principle of induction is true (since we cannot find a least counter-example)
so really, my question is: how do we know that the natural numbers exist (except by postulation)?
 
4:25 AM
@DavidWheeler Sorry, are you considering the natural numbers to be part of the "construction" [I don't know any set theory or logic so I'll use scare quotes] of induction and hence I can't use the usual recursive definition of $\mathbf N$?
That is, $0 = \varnothing$ and then $n + 1 = n \cup \{n\}$?
 
i'm fine with that definition of $\Bbb{N}$ provided...we know sets can get that big
 
I am one of these horrible people that claim to live in ZFC but have no idea what the axioms are.
 
Doesn't the existence of the natural numbers follow from the axiom of infinity?
 
the axiom in question that guarantees the existence of an infinite recursively-defined set is called "the axiom of infinity", i believe
 
I think what you need is in the wiki page en.wikipedia.org/wiki/Axiom_of_infinity
 
4:36 AM
so, certainly, if one just accepts ZF (which includes the axiom of infinity), then mathematical induction is part and parcel of that
 
Oh. I wouldn't even want to think of not accepting those. I have enough problems already :(
 
so, i suppose in general, i am talking about the subtle difference between a "proof" and a "proof schema"
 
I mean, I can't prove anything without ZF
and really I like to have choice hanging around too.
 
There are people who probably know a lot about this but I don't see them now. Matt and Zhen are not here; Asaf is in exile.
 
A set theory question?
I can try and help.
 
4:41 AM
why should i accept the axiom of infinity?
 
Morally?
 
you can make any case you wish (although i may or may not find it satisfying)
 
You're free not to accept it if you want. There are people who don't like it (most of them aren't mathematicians, mind you).
 
it is my understanding it is independent of the other ZF axioms, placing it in a similar position as AC
so...if i don't accept it, how can i justify a proof by induction?
 
You can't, formally speaking. But then again, if there's no finite set $\omega$, you don't need induction. You just repeat the inductive step enough times for each specific instance you need.
*infinite set $\omega$
 
4:46 AM
or to put it in a slight sarcastic form: "a proof by induction is an article of faith of belief in infinite things"
 
If you don't accept infinity, why do you need induction?
 
@IsaacSolomon i understand that. but typically, one is claiming to prove things for ALL natural numbers $n$, when invoking induction.
 
The set of all natural numbers? Sounds like infinity to me.
 
the thing is, if the set of ALL natural numbers isn't one (isn't a set), that still doesn't mean that the various statements "proved" by an inductive proof still aren't true for various natural numbers which i DO believe in
 
Hmm. How are you defining natural numbers without omega?
 
4:54 AM
good question. any ideas?
i mean, can you see my dilemma: there's a certain impredicativity in defining the natural numbers.
 
You can think of omega as a class, I suppose.
But it's a wellordered class, so induction can still work I think.
 
it seems to me, when people are first exposed to induction...that they are being asked to accept more than what is presented...that there is actually a "back-ground machinery" which is subtler than the naive way induction is presented. this seems "unfair" to me.
 
That is true, but only to the extent that in accepting formal mathematics you are probably signing a contract with ZFC. Ignoring the way we think of it today, induction is a very old technique that "intuitively" makes sense, and students can learn it in that naive framework.
 
5:11 AM
so, ultimately: proof by induction is "proof by tradition"?
 
To high school students, it's proof by "naive and intuitive understanding of the natural numbers"
 
well, i am concerned that to mathematicians, "truth" is starting to mean "a conservative extension of ZFC"
 
Haha. I wouldn't use the word "conservative" so freely.
And of course nobody thinks that reality is precisely ZFC and nothing else. I mean, it's a complete extension, if anything.
 
well, i am thinking of what happened with euclidean geometry. i think non-standard set theories (or topoi, perhaps, i need to know more about those) should be explored in more detail
 
Why? It seems a bit like a black hole, personally. There are all sorts of set theories you can imagine.
 
5:19 AM
because i think we are too firmly rooted in "history".
 
In what sense?
 
if one looks how mathematics is actually taught, it is taught "historically", the older concepts are taught first. it may take 2 decades or so before one is learning "current stuff". that seems inefficient.
 
Isn't that because mathematics is inherently hierarchical?
Older generally translates into simpler and more elementary.
 
not always. there's nothing very complicated about the concept of "trees" for example. why should one learn about these long after "numbers"?
 
Trees in graphs?
*as in
 
5:23 AM
yes
 
It's certainly elementary, but a lot less useful than other things.
At least for most people.
 
in my experience, the utility of a concept is often dependent on how wide-spread it is. in a sense, we reinforce the utility of arithmetic simply by placing so much emphasis on teaching it. it becomes a self-fulfilling prophecy.
 
Really? You can't see why arithmetic is more useful than graph theory?
 
nope.
 
It's necessary in most sciences, social or natural. People need it to manage their finances.
It's important for running a business, etc.
 
5:30 AM
only because of its "priority" (a dual use of the word). we've used numbers for so long we have a compact language (arithmetic) for manipulating them.
when it came time to develop computers, numbers weren't such a good language, boolean gates were.
 
This is a bit tangential, as we are now discussing why we as society still employ numbers.
 
arguably, arithmetic "mod 2" is considerably easier to grasp then "ordinary arithmetic", and as far as i can see, very widely applicable. so what reason for the delay in teaching it?
 
Well, that's a little meaningless, no? It doesn't affect mathematics in the slightest.
 
as far as i can see, the main reason is "historical precedent".
 
By the same reasoning, we should all switch to Esperanto.
 
5:35 AM
i'm sure there are people who believe that.
 
So long as it does not functionally inhibit our ability to arrive at mathematical truth, what's the harm?
 
a baby example: often students struggle with the fact, that in groups, ab = ba may not be true. but the idea of "commutativity" isn't one we are born with. we LEARN it. so students learing group theory for the first time have to UNLEARN it. how is that efficient?
 
@DavidWheeler And we’ve used them for so long precisely because they were found necessary. The claim that we find them necessary because we’ve used them for so long inverts the facts.
@DavidWheeler No. The main reason is everyday utility.
 
David, it's always easiest to start with the most relatable, concrete examples. Does one teach abstract topologies before open sets in R^n? Sometimes we need sacrifice optimal efficiency so that people can understand what's actually going on.
 
@BrianMScott i think that underrates the inventiveness of humanity.
 
5:43 AM
@DavidWheeler It’s a factual observation pure and simple.
 
@IsaacSolomon i understand that teaching the most general way possible isn't always feasible.
 
@IsaacSolomon Actually, that’s precisely how I learnt topology, and in general it’s my preferred approach to mathematical ideas. I know from years of experience teaching, however, that this is rather unusual.
 
@BrianMScott Most people can't handle that level of abstraction without seeing something concrete first.
 
@BrianMScott but how are we to gauge the utility of an unknown concept? it doesn't exist yet, but if it did, it's utility would be > 0. olders concepts always have more "utility" in the sense that they are applied more often, but that is often because people only use what they have.
 
@DavidWheeler I was talking about a comparison that you made between two known concepts, ordinary arithmetic and arithmetic mod $2$. Obviously we don’t teach unknown concepts, so they’re irrelevant to the question of what to teach.
 
5:52 AM
well, arithmetic mod 2 has applications to "logical thinking" (something even used outside of mathematics), whereas most of the applications of "ordinary arithmetic" are internal to mathemematics, in some sense. understand, i'm being somewhat "tongue-in-cheeck", it's ludicrous to attempt to teach advanced math to kindergarteners.
 
@DavidWheeler I would say that the everyday applications of ordinary arithmetic are wholly external to mathematics, and that the application of arithmetic mod $2$ to logical thinking (as distinct from the abstract field of formal logic) is marginal at best.
 
this conversation began as a discussion of induction, in particular "why is it true?" it has, along the way, devolved to a discussion of pedagogical practices, which is a thornier subject
 
Yes, I saw the earlier discussion of induction.
 
my point being, "infinite sets" are something we choose to make part of mathematics, but which are not intrinsically so. one could, for example, deal with the universe of hereditary finite sets. that is just one of many choices which can be made in deciding what is, and is not mathematics.
 
No, no such choice is available.
 
6:01 AM
explain, please?
 
Even if some ‘we’ were to decide tomorrow to limit ‘our’selves to HF, the rest of set theory and the further complications of category theory would still be part of mathematics.
 
hmm...that's not quite what i meant.
 
I’m really rather at a loss to see what you’re driving at in the whole discussion, going back before I dropped in.
I keep wanting to ask what color the sky is in your world!
 
in my world, the sky is different colors at different times. at noon, on a cloudless day, its "blue" ( i could probably get a frequency range in angstroms, if you need that)
 
But then, I’ve never understood why people get all worked up over infinity. In my view the formal notion of induction, be it a consequence of ZF or an axiomatic assumption as in PA, is merely a formalization of very nearly as obvious as $2+2=4$.
 
6:05 AM
or is that wave-length (i forget)
 
@DavidWheeler Wavelength: the ångström is a unit of length.
Deprecated nowadays, as I recall.
 
@BrianMScott well, explain to me how induction is "obvious"
 
@DavidWheeler No, thanks! If it isn’t obvious to you, it isn’t, and I’m unlikely to be able to change that, especially in this medium.
 
@BrianMScott Not entirely; I've seen people always quote both nanometers and ångströms for lengths.
 
i understand that if you take it as an axiom it's "true by default", and if you accept that there exists a well-ordered infinite set, it's true because there's no counter-example (assuming that the principle of the excluded middle is a given)
 
6:11 AM
@JM My understanding is that it’s still in fairly common use, but the international committee that standardizes such things deprecates it, since the exponent isn’t a multiple of $3$.
@DavidWheeler At the intuitive level, utterly divorced from formal systems, I find it almost as obvious a logical principle as modus ponens.
 
@BrianMScott Well, yes, it's not SI, so we shouldn't be using it as much, but since when did people listen to standards? ;)
 
as i said earlier, why should i believe in infinite sets? if i do, believe me, i can rattle off the name of several (like R[x], for example).
 
@BrianMScott Hello Brian, did you see this?
 
@DavidWheeler Why shouldn’t you? They’re obvious intellectual constructs. As I said before, I simply don’t understand why people tie themselves up in knots over such matters.
 
@JM Hm. Is this the diet version of the donut? : )
 
6:14 AM
inductively (yes, an ironic use of the word), if i believe in infinite sets, the existence of uncountable and inaccessible cardinals seems much more plausible
 
If I may ask a stupid question: how do you then consider a line segment to be continuous if you dispose of the notion that there are infinitely many points within the line segment?
@MattN Yes, and it has holes within holes. :) Here is a bigger picture.
 
@MattN No, I hadn’t. Hang on a bit while I take a look.
 
@JM Oh!
@BrianMScott Lovely, thank you : )
 
@MattN Should be crunchy due to being so hollow... ;)
 
@JM that is a good question. continua may have to go.
 
6:17 AM
@JM <Jonas> Holey monkeys! </Jonas>
 
@JM Yes... and taste like graphite : ) I'm still hoping for a tasty looking one with pink icing and rainbow sprinkles or something on it.
 
or perhaps more intelligibly: infinitesimals don't make much sense without hyperfinite numbers.
 
@MattN I might indulge your wish in a few weeks, if my experiments pan out. :)
 
@Matt: It looks okay; do you have a link to the question handy?
 
@JM Om nom nom... : )
 
6:18 AM
@BrianMScott That's what I thought. :)
 
@JM Now you need to have Gandalf blowing it as a smoke ring.
 
@BrianMScott Sure, here.
 
Let's go back to my dumb question: what would be your replacement for the notion of continuity if you can't or won't accept infinite sets?
 
@JM You should ask WM...
 
well, we can still form the abstract notion of a topology, even for finite sets. so we can use the inverse image is an open map criterion.
 
6:22 AM
@MattN Sorry, I'm slow today; who's (s)he?
 
@BrianMScott I assume plus one means that it's right?
 
@MattN Yes, that’s fine. If you now modify it by making each rational an isolated point, you have something similar to mine, though not quite homeomorphic.
 
unfortunately, all our metric spaces will be discrete, but ah well.
 
@JM Wolfgang Mueckenhausen.
 
@BrianMScott Bzzzzz! :D
 
6:24 AM
@JM Actually, this one here.
"Voting irregularities", huh? : )
@JM I started a new series: do you know Misfits?
 
but on the "plus side" we get some "extra" "continuums" because their "gaps" will be too small for our finite mesh to detect.
 
It's really good.
 
the one about the super-heroes doing community service?
 
@MattN I have seen it; quite nice, that. :)
 
: )
 
6:27 AM
Can anyone explain how dividing/multiplying $\theta$ in a polar coord affects the cartesian coordinate in the abstract case. i.e. if $r\cos(\theta) = x$, then what does $r\cos(\theta /2) = $?
 
I'm getting dangerously close to the rep I want. Another +15. I hope I won't fly past.
 
@stariz77 use a half-angle formula
 
As applied to what?
 
Hi guys. It is freakin' early.
 
@JonasTeuwen 'tis!
 
6:28 AM
@stariz77 Certainly, in the case of a line, your line is now less steep...
hey Jonas.
 
@MattN Yes!
 
@BrianMScott Thanks!
 
@JM 8-).
 
@stariz77 If $x=r\cos\theta$, $x$ cycles from $r$ to $-r$ and back to $r$ with period $2\pi$. If $x=r\cos (\theta/2)$, it still cycles from $r$ to $-r$ and back to $r$, but it takes twice as long: the period is now $4\pi$, because $\theta/2$ changes only half as fast as $\theta$.
@MattN I’d like another 130.
 
@BrianMScott Ok, I'll remember that : )
 
6:31 AM
Here’s a fellow making good use of his gravatar and mini-bio.
 
@stariz77 you get $r \cos(\theta/2) = \pm r\sqrt{(1 + \cos(\theta))/2}$, which square root you take will depend on where on the circle $\theta$ is.
 
@BrianMScott He seems to be missing that Russia is not a democracy...
 
Right, ok yah I could visualize what was happening ok, it was just I'm used to quickly substituting $rcos(\theta)$ for x when needed without thinking what was happening, and drew a blank just then when $\theta$ was divided by 2 in the eq. Thanks.
 
Ok, I'll see you later!
 
Hello @Zev.
 
6:34 AM
@JM Hi!
 
@BrianMScott A good cause is as good a reason as any, I guess. :)
 
@JM I’ve been following a link or two, and it does look like a good one.
 
true story: as i was waking up this morning, i found myself thinking about the uncountable particular point topology, although that's not what i called it.
 
@DavidWheeler Did you call it anything printable? :-)
 
well i was thinking about the irrationals, and how to make a topology that always contained the rational point q in any non-empty open set.
i was just playing around, i had no idea that anyone had given anything of the sort a name, sheesh. then i had some coffee, and forgot all about it.
 
7:02 AM
what could possibly be meant by the group U5(105)?
 
@DavidWheeler It’s $U_5(105)$; $U_k(n)=\{x\in U(n):x\equiv 1\pmod k\}$, where $U(n)$ is the multiplicative group of units in the ring $\Bbb Z/n\Bbb Z$.
 
ok, i know what U(n) is, just wanted to be sure of what $U_k(n)$ was.
so basically, list all the integers between 1 and 104 ending in 1 or 6, and strike out the multiples of 3 and 7.
this should have order |U(3) x U(7)|, yes?
 
7:30 AM
Sounds right.
 
so to check the order of $4U_5(105)$ in the quotient $U(105)/U_5(105)$ it suffices to observe that 16 is in the factor group.
by factor group, i mean the subgroup we're factoring by, not the quotient
 
Where’d all this come from? When I went digging, I found it only in Gallian’s book and a paper by him and someone else in the Monthly.
 
it's a question someone asked on another forum, if you must know. i answer such things to see if my brain still works. man's gotta have a hobby.
 
By any chance answers.yahoo.com? I saw the question there on the Google returns when I went hunting, though I didn’t look at the link.
 
i learned the other day that for a prime p, the legendre symbol is a homomorphism.
@BrianMScott indeed, you are correct.
 
7:37 AM
@DavidWheeler I’m always a bit surprised to find such technical questions in what I think of as very general Q&A sites.
 
@JonasTeuwen ayt?
 
He looks pretty pale and washed out.
 
True dat.
 
Do you suppose that he might actually have been sensible and gone back to sleep?
 
@BrianMScott well, most of the questions asked there are very simple: like what is 1/3 + 1/18? occasionally, one finds more substantial questions.
 
7:40 AM
@DavidWheeler 1/21, clearly!
 
@DavidWheeler It was easier for them to ask than to type the thing into Google? :)
 
@BrianMScott No, I'd guess he got himself a fine cup o' coffee and set about work.
 
@JM I think that a great many people aren’t aware of that feature of Google.
@MattN You’re probably right. How are you feeling?
 
well, i proceed as follows: first, i only know how to add and multiply integers, so first i form the field of fractions of the integral domain Z. next, i note that Z is in fact a euclidean domain, so applying the euclidean algorithm to 3 and 18....
 
@BrianMScott Good point... *sigh*
 
7:42 AM
@BrianMScott Slightly better, thank you.
 
@MattN Well, I hope that you can soon remove the slightly.
 
@BrianMScott Yes, thanks, me too. But it's just a flu, no biggie. : )
I hope I don't get any more upvotes on answers of mine.
 
@MattN Do I remember correctly that what you want is an acceptance, so as to hit a target?
 
@BrianMScott Not anymore. Now I want an upvote on a question of mine. : )
(I'm at 6661)
: )
 
@MattN Going for four of a kind?
 
7:46 AM
@BrianMScott Yep : )
 
@MattN (after which you get two upvotes on your questions)
 
@JM : D Not yet though!
Oooh!
screenshots
 
Sitting on 49,870, myself. And you just hit your target.
 
I have more modest goals. All I want is to have rep that's a multiple of five, and badge counts that are a multiple of three...
 
@JM Multiples of 5 is a very modest goal. Why so modest?
 
7:49 AM
At one point I think that I had badge counts of 3-27-81, which was rather nice.
 
Thanks to you who upvoted one of my questions! : )
 
@BrianMScott Nice!
@MattN I used to aim for having a multiple of ten, but acceptances keep throwing that off...
(and on the off chance that I get a fourth gold badge, then I would want my badge counts to be a multiple of four...)
 
@JM It just means you aimed at not getting any downvotes?
 
@JM Mine are currently 4-32-82, so the last one rather mucks things up.
Heh. I just noticed that I picked up another upvote on my all-time winner (Are half of all numbers odd?): it’s now at 75.
 
@MattN Something like that. :)
 
7:54 AM
: )
 
@BrianMScott That was quite the blockbuster.
 
That really surprised me, too.
 
@BrianMScott Not by me, I upvoted that ages ago.
 
@MattN Every once in a while I get an upvote on a question that I barely remember answering. Which I suppose shows the site serving one of its purposes.
 
@BrianMScott Same here : )
 
7:58 AM
Sometimes, when I get reminded of my old answers from upvotes and/or comments, I go "Wow, I really wrote that?" :D
 
I’ve felt that way a couple of times on rereading papers that I wrote.
 

« first day (653 days earlier)      last day (4360 days later) »