@pH13 Now that's interesting, I'll need to think about it, don't have time right now...thanks for that.

1st is between solid anode and liquid electrolyte

2nd is between solid cathode and liquid electrolyte

2 phase boundaries

each for each part of galvanic cell

plus a double boundary inbetween anode and cathode parts

due to salt bridge

@IͶΔ in my eyes this would mean, that over time more and more users see the sites and therefor more and more users will be there. a rough sketch based on quantcast data tells me you could be right.

@pH13 I could be?

those are the first 1414 days for all *.se sites

the are quite the same, except for math which is a little bit higher

Chem is getting more and more QPD.

qpd?

Questions Per Day.

Qs Per Day

This itself is growing.

okay

Questions Per Day

sure ... with more viewers, more questions come in

So we're getting more and more questions everyday more and morely.

So we'll grow.

:O

I don't see any anomaly.

into something...

We'll EVOLVE! Like Pokemons!

No, like chemists.

had pokemons been banned in iran? do you know them? :O

I would've known them only if they were banned? :P

XD

the other way around oô

Yes it did

@user36790 test

:)

@IͶΔ feel kannad-eyes-ed

*feels

And I think we made a new verb.

@IͶΔ congrats! XD

I do not have the power to install pork chat at work and I don't want to search for those eyes every time ... so :P

@pH13 Y U NO PORKCHAT ಠ_ಠ

where is my star-rain for it???? (╯°□°）╯︵ ┻━┻

google it, porkchat for chrome

@pH13 I didn't star it because

@IͶΔ cannot install stuff and need to use firefox

I have porkchat installed on Chrome.

yeah no ... "Porkchat chrome"

sry for that

Hah

the 'g' and 'I'

And what does 'I' means?

liquid

and s is solid

Also are they standard and what is their use? Can't that be deduced by the chemical formula?

sth like XYZ(aq) means XYZ that is solved in water

Hello can somebody answer me? About my previous post.

they are standard and their use is to tell the reader about it's state of matter ... obviously.

Aha - so it can't be deduced by the chemical formula?

by knowing what your formula means, yes. by the formula itself, no.

so ... C6H12O is most probably solid as it is most probably glucose. N2 is most probably gaseous as it is nitrogen. but N2 can be liquefied at low temperatures so it can also be N2(l).

I mean because some elements are called gases and other solids. But maybe I have miss understood.

So it's the current state they are in, right?

yes

Ah yeas I was it - some elements are called for example gases.

Like He.

yes oô

But that doesn't have anything to do with their current state.

In the reaction.

It's only their category.

I'm not sure what you are asking.

please be more specific

Nothing. I got it. Thanks for the info.

also - we are all here to talk and of course to help others. but we are not here to answer questions and it is not nice from you to post sth like "Hello can somebody answer me?" because we are not your personal dictionary or whatever. if you ask a question, someone will answer it or not.

no, FISOCPP

but in general ... the chat is also no homework completion service

@user36790 what do you think?

why do you think that?

and the hydrogen atoms disappear to nowhere

@user36790 what should I write? I don't get that question :)

what you are describing is the electrolysis of hydrogen peroxide with platinum electrodes, right?

so you know the reaction?

What is this 'ROOR'?

opposed to 2 RO

Yeah I see now.

But what is R?

some >R<est

R is something

a placeholder

Is it standard?

yes

And why in the case it's Alkyl group?

pretty standard notation, yes

if it is ROOR, both R are equal. ROOR' means R and R' are not the same

if it is not defined, it can be a lot of stuff

It's ROOR

I can read ... I just told you that if you read ROOR' sometimes what this would mean

So why in the case it is the Alkyl group as user36790 mentioned?

Or maybe this is the whole thing?

The whole ROOR

we have told you more than twice that is does not need to be an alkyl group

Calm down.

You haven't told me that.

Before now.

Anyway.

R is some part of a molecule which is irrelevant to the reaction in question.

It is kept untouched during the reaction.

Whatever. I understand now. Thanks for the info.

@Wildcat do you know more about my question on two electron integrals? you always seem to know such stuff =_=

@pH13 sadly no, I don't know much about it :(

martin put it on math.se ... maybe someone will know ^^

Anyone else going to the ACS meeting in San Diego? It would be cool to see some of the work that (comes out of/might be affected by/comes from the folks of) Chem.SE. I'll be there... undergrad poster. :)

How do I make this notice go away? ^^

nm, there was a hidden "go away" box. :P