The Nineteenth Byte

@BrainSteel I think it's better for now to just do it frame-by-frame. It's relatively difficult to get moving so fast that the program would miss collisions.

quartata

@Doorknob How did you already get Wireless?

El'endia Starman

@Ampora 12 months? You graduate next December?

Doorknob

@quartata wizardry

quartata

brb getting se app

I refuse to let Doorknob have more hats than me.

El'endia Starman

12:15 AM

@quartata I like your hat placement! :P

nom nom

quartata

I am the hat master in all games

BrainSteel

@El'endiaStarman If you're interested, I found some (fairly bad) collision detection code of mine. Pastebin here. (Written in C)

quartata

I will not let Doorknob beat me

Witness my hat power: steamcommunity.com/id/xpxh4pi/inventory/#440_2_3987239306

Doorknob

Good luck getting Weed Eater here, haha

> answer a question qualifying for the Tumbleweed badge that gets accepted

Alex A.

@quartata "DJ quartata"?

quartata

12:18 AM

@Doorknob I don't even see how you could get that on any community other than SO

@AlexA. Yes so

That's not the point

Alex A.

Are you a disc jockey?

quartata

The point is witness my beautiful hat. I am the hat master.

I will have all the hats on SE.

@AlexA. If by disk jockey you mean micspammer on lazypurple's silly server then yes

Alex A.

@quartata I have no idea what that means

BrainSteel

@El'endiaStarman It's possible to take care of the "line has velocity" case in preprocessing (i.e. add the additive inverse of that velocity to the circle), but I'm not convinced that works with acceleration. Maybe.

quartata

Answers upvoted

Where's my headset thingy

Also, the SE mobile app is terrible.

Doorknob

12:22 AM

@quartata Blame caching

Alex A.

@quartata That is false, at least on iOS.

Doorknob

hahaha wonder where all these sudden delete votes came from

Alex A.

Deleting answers doesn't award the hat, just FYI.

Doorknob

I got both on Stack Overflow very, very easily :P

(close and reopen)

Alex A.

Heh

At any given point on SO, something deserves to be closed, reopened, or deleted.

quartata

12:25 AM

What the heck. The votes show up in the votes tab on my profile

And yet I still haven't gotten the wireless hat.

Doorknob

@quartata only for you

Oh, I thought you meant that you thought they were public

quartata

These hats are very broken

I dislike

Doorknob

Blame caching

BrainSteel

shouldiblamecaching.com

quartata

By the way, the cake hat is apparently "garbage-hat"

When you inspect element it...

Actually..

Huh. I must have been imagining that.

BrainSteel

12:28 AM

But it has padding on top.

The best of cake toppers.

quartata

Wait, you can only wear one hat at a time?

Doorknob

Yep.

quartata

Lame.

Alex A.

I was a goose with Spock ears all last winter.

quartata

It should be 3.

Doorknob

12:29 AM

Oh shoot! I need a new username/profile picture!

quartata

Anyways, I now have 2 hats.

BrainSteel

I like my cake hat. It's been good to me.

quartata

Hat Admiration Group

HATS

Necessary

Alex A.

Are you sure?

quartata

Yes.

BrainSteel

12:31 AM

Well, that settles that then.

Cᴏɴᴏʀ O'Bʀɪᴇɴ

\o/ I got the wireless hat

Do hats show up in chat?

Doorknob

yes

quartata

@CᴏɴᴏʀO'Bʀɪᴇɴ Yes.

Doorknob

there should be a ninja'd hat

Cᴏɴᴏʀ O'Bʀɪᴇɴ

@quartata \o/ :D

Shower this answer in upvotes

1

A: Is it possible to define $\lceil x\rceil$ in terms of $\lfloor\ldots\rfloor$?

If $a$ is infinitesimal positive number, and you assume that $\lceil{a}\rceil=1$, then... $$\lfloor{x+1-a}\rfloor=\lceil{x}\rceil$$

Doorknob

12:39 AM

Announcing Winter Bash 2015

Pops on December 14, 2015

Another calendar year is ending, which can mean only one thing. It's time once again for the event that brings joy to all (with a slight helping of dismay for our friends in the southern hemisphere1): Winter Bash!

El'endia Starman

@CᴏɴᴏʀO'Bʀɪᴇɴ This seems oddly familiar.

SuperJedi224

I've now earned the cake hat on 7 sites.

Cᴏɴᴏʀ O'Bʀɪᴇɴ

@El'endiaStarman What does?

El'endia Starman

6

Q: How to prove $\left \lceil \frac{n}{m} \right \rceil = \left \lfloor \frac{n+m-1}{m} \right \rfloor$?

everybody, how can I prove that, for natural $m$ and $n$, $$ \left \lceil \frac{n}{m} \right \rceil = \left \lfloor \frac{n+m-1}{m} \right \rfloor \; ? $$ Thanks a lot.

Just reminded me of a question I answered years ago. :P

quartata

BrainSteel

12:41 AM

Poorly drawn lines!

quartata

yas

Hey, I got Cerro de Potosi.

I like that hat better than the headset.

Anonymous

I LIVE

quartata

Hm.

Anonymous

But I have not yet truly lived

Anonymous

For I need hats

quartata

12:46 AM

I wrote out Alex-style adding, but I don't think it is that interesting.

Anonymous

@quartata 1+1 = n for n != 2?

BrainSteel

Did you include the recursion requirement?

quartata

@Mego No.

@BrainSteel Yes.

Anonymous

@quartata Oh, I thought Alex-style adding would be an operation that resulted in any value except the correct sum

BrainSteel

Just 90% of the time.

quartata

12:48 AM

@Mego

float alexAdd(float a, float b) {
  float f = Math.random();
  if(f < 0.1) {
    alexAdd(a,++b);
  } else {
    return a + b;
  }
}
print alexAdd(2,2);

Anonymous

@quartata ++b is defined for floats? What ungodly language is this?

quartata

@Mego Groovy..?

Anonymous

@quartata Oh that explains everything

quartata

Not really.

Anonymous

Increment doesn't make a whole lot of sense for reals since there's no minimum difference

SuperJedi224

12:50 AM

@Mego Does that work in Java?

Anonymous

@SuperJedi224 Probably, I dunno

Anonymous

@SuperJedi224 Survey says yes

Doorknob

Alright, back to studying history... hat festivities will continue later for me. :P

Anonymous

That's silly

SuperJedi224

@Mego That's what I thought.

LegionMammal978

12:52 AM

How do you set the profile picture for the chat account?

Doorknob

5

I enhattened our Community ♦

quartata

@Doorknob ha

Anonymous

@Doorknob What about the sandbox?

quartata

I'm not sure I want to post this Alex adding challenge

I just don't think it's complicated enough

LegionMammal978

Can you link to the post?

quartata

12:55 AM

I haven't posted it in the Sandbox yet.

Anonymous

@quartata I don't think there's a problem with simpler challenges

El'endia Starman

^

LegionMammal978

^

Doorknob

^

Anonymous

carrot.hat

quartata

12:58 AM

Fine I'll post it

Anonymous

gets ready to downvote

El'endia Starman

readies ><> to smack Mego with

Anonymous

@El'endiaStarman :P

Anonymous

prepares to swallow whole ><> because penguin

Alex A.

Penguin powers have activated

quartata

12:59 AM

0

A: Sandbox for Proposed Challenges

Alex-style Addition Inspired by Alex's glorious Learn you an R for greater good, we are going to humbly recreate Alex's "one true R program" -- but with a twist. Alex-style Addition works like this -- it has a 90% chance of simply returning the sum of the two numbers given and a 10% chance of r...

Hat Admiration Group

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