12:04 AM
@Adám Charcoal, 5 bytes: `ＩΣＸＡ²`

4 hours later…
4:12 AM
@DJMcMayhem Wren, 20 bytes. Ideal because it has a verbose lambda syntax.
Or am I replying to the wrong person?

3 hours later…
7:04 AM

7:19 AM
10

Zeckendorf's theorem shows that every positive integer can be uniquely represented as a sum of non-adjacent Fibonacci numbers. In this challenge, you have to compute the sum of two numbers in Zeckendorf representation. Let Fn be the n-th Fibonacci number where F1 = 1, F2 = 2  and for a...

2 hours later…
9:24 AM
@NewlyFeaturedQuestions Shouldn't we change the name to "Newly Bountied Questions"?

@Bubbler But bountying a question causes it to become featured, so it is correct.

9:36 AM
@Adám I think the term "Featured" has been officially changed to "Bountied" a while ago

2 hours later…
11:15 AM

1 hour later…
0

Disclaimer: This challenge inspired by me spending the morning debugging recursive functions, which have been frying my brain a little. Here's an example of recursion, from a letter, we keep going to the previous letter of the alphabet, printing out each one as we go, until we hit the letter a, ...

1:14 PM
0

Disclaimer: This challenge inspired by me trying to find pairs in a large pile of socks. Disclaimer: This is looking for a very different process and output to Help me sort my socks!. Please don't claim it as a duplicate until you've read both ;) So, I have a huge pile of socks. Of course I ...

2:07 PM
@NewMainPosts this challenge is so real-world :)

@NewMainPosts I hope my browser is working. I already have a solution but I can't submit it.

2:23 PM
@A_ I've had that before. Save your solution somewhere (text file, TIO etc.) then reload the page

Umm, I tried reloading multiple times after saving my solution somewhere. (I was getting a bit impatient. Now it is working.)

2:44 PM
(For the first time I felt that a very simple question is too hard for me.)

3:16 PM
0

Your task is, given a family tree, to calculate the Coefficient of Inbreeding for a given person in it. Definition The Coefficient of Inbreeding is equal to the Coefficient of Relationship of the parents. The Coefficient of Relationship between two people is defined as weighed sum over all comm...

Sites are moving to first-party trackers through clever CNAME manipulation. Get the latest version of uBlock origin on Firefox to block them: bleepingcomputer.com/news/security/…

3:55 PM

Thanks

4:17 PM
ninja'd

Don't worry, there'll most likely be a few more soon.

3 hours later…
6:52 PM
0

How close are our faces? Each natural number \\$n\\$ has 10 faces: its decimal representations in bases \\$1\\$ through to \\$10\\$. For example, the 10 faces of \\$8\\$ are \\$[11111111, 1000, 22, 20, 13, 12, 11, 10, 8, 8]\\$, and the 10 faces of \\$14\\$ are \\$[11111111111111, 1110, 112, 32, 24, 22, 20, 1...

1 hour later…
8:14 PM
0

Predict the state of a Minecraft inventory after click events Minecraft does inventory management over the network by sending packets describing the clicks that a player does. If you're caching these events, it can be non-trivial to predict what state the inventory is in after the clicks Challe...

2 hours later…
9:56 PM
0

A very-very old (maybe early 2000s) problem: Print out a decimal number \\$n\\$ such as \\$n^2\\$ ends with \\$n\\$ with maximal length your program can compute in 60 seconds In other words it's needed to find some long enough \\$n\\$ such as \\$10^{\lfloor\log_{10}n\rfloor+1}|(n^2-n)\\$. A hint may ...

1 hour later…
11:06 PM
-1

Make a simple calculator which does the basic math operations +, -, * /, one at the time: Input example: 10+12 Output: 22 Of course, lightest code wins. Good luck!