Random question: anyone happen to know how the site decides which tag to put in the HTML page title? Most of the time it seems to be code golf, of course, but my recent question has ascii art instead, despite code-golf being the first tag listed.
> This article may have too many section headers dividing up its content. Please help improve the article by merging similar sections and removing unneeded subheaders. (March 2017)
@Zwei Nothing to lose. Sandbox doesn't affect your reputation and you can get good feedback. You just have to be willing to leave it there several days before posting.
holy shit quill's thingy dones't like moved messages
Dennis moved your message into [240: The Nineteenth Byte] !
Dennis moved your message into [240: The Nineteenth Byte] !
Dennis moved your message into [240: The Nineteenth Byte] !
Dennis moved your message into [240: The Nineteenth Byte] !
Dennis moved your message into [240: The Nineteenth Byte] !
Dennis moved your message into [240: The Nineteenth Byte] !
Dennis moved your message into [240: The Nineteenth Byte] !
Dennis moved your message into [240: The Nineteenth Byte] !
Dennis moved your message into [240: The Nineteenth Byte] !
Chat messages are deleted or trashed and users are kicked or suspended to keep the room on topic. Lengthy arguments after said actions achieve the opposite goal. If you disagree with chat moderation, take it to meta.
@ConorO'Brien 0/10 IS LOWER/IS HIGHER is confusing, use radius IS DECREMENTED/skew IS INCREMENTED/DECREMENT radius/INCREMENT skew (also it's DIE not DICE)
@WheatWizard No, it isn't, which is clear if you just think of what the graph of x^3 + 1 looks like. (Or factor the quadratic over the complex numbers by completing the square, or just look at its discriminant.)
$(x == -1 && ((a < 1 && b == 1) || a == 1 || (a > 1 && b == 1))) || (((a < -x && (b < -x || b > -x)) || (a > -x && (b < -x || b > -x))) && c == (-1 + a b x + a x^2 + b x^2)/(-a b - a x - b x - x^2))$
x^3 = -1, so x^3 = cis(pi + k2pi), so x = cis(pi + k2pi)^(1/3), so x = cis((pi + k2pi)/3). Therefore, x = cis(pi/3), cis(3pi/3), cis(5pi/3), or x = (cos(pi/3) + i sin(pi/3)) and x = (cos(pi) + i sin(pi)) and x = (cos(-pi/3) + i sin(-pi/3))
So the answers are -1, (1/2 + sqrt(3)i/2), and (1/2 - sqrt(3)1/2)
where cis(n) = cos(n) + isin(n)
cis(n)^x = cis(xn) because cis(n) = e^(ni) and e^((ni)^x) = e^(nxi)
Count the number of Hamming distance sequences
The Hamming distance between two strings of equal length is the number of positions at which the corresponding symbols are different.
Let P be a binary string of length n and T be a binary string of length 2n-1. We can compute the n Hamming distan...
@betseg What bugs me most there is the grammar of "483 following, 62.8K followers". I only figured out which was which because of the large difference between the numbers
It should be "following 483, 62.8K followers" IMHO
Count the number of Hamming distance sequences
The Hamming distance between two strings of equal length is the number of positions at which the corresponding symbols are different.
Let P be a binary string of length n and T be a binary string of length 2n-1. We can compute the n Hamming distan...
Write a program in Python 3 to print this pattern in minimal number of lines:
*
Number of rows should a user input.
