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12:01 AM
quiet... too quiet
@J.M.: I haven't seen you on math.SE recently. Have I missed any interesting avatars?
 
12:14 AM
@robjohn I might be back in a week or so. Nope, this is the first new artwork I did after the elections. :)
 
12:30 AM
@J.M. I see you are still blue. I did not hear the outcome of the elections. I should read meta.mma
@J.M. Congratulations! I see officially that your blue status will continue.
@J.M. I made another Mathematica animation for an answer. Not much to write home about, but I did learn about Exclusions :-)
 
@robjohn Thanks. :) I got in barely, it seems.
 
@J.M. I haven't downloaded the election results. I just saw that your name was second on the list.
 
@robjohn It's nice. :) I seem to recall there being a name for the class of curves Peter was looking at, but I'm drawing a blank...
 
@J.M. I will have to look, I have not had a chance this afternoon.
 
12:50 AM
@J.M. Do you know of a simple way to order a list in the sense of OrderedQ at every level?
I'm drawing a blank and the only thing I can think of is to do it explicitly at every level
Hello @robjohn :)
 
@rm-rf hey there. Congrats to you, too!
 
@rm-rf "every level" - nested list, eh?
 
Unfortunately, when I try to run the election, I get an error.
 
@robjohn thanks, and congrats to you too! :)
 
@rm-rf Thanks! They needed more help and so they increased the last election count to 4 from 2 :-)
mixedmath has already been a mod on another site, so I am the newbie mod on math.
 
12:54 AM
Hello WOW
 
@J.M. Yeah, nested and arbitrary
 
An angry kyuubi
Anyway. Hello my pingable @rm-rf
 
@rm-rf Eek, so it can be ragged then? I was thinking of using Map[] with its third argument, but I'm not sure how to prevent things like Sort[3] from happening...
BTW @rob, the other day I wrote something you might be interested in...
 
@J.M. Something like f[x_List] := Sort[x];f[x_]:=x; f //@ list should work
 
@J.M. probably :-)
 
1:01 AM
eulerKnopp[seq_?VectorQ, q_: 1] :=
Module[{n = Length[seq], res, ek}, ek[1] = 0; res = {First[seq]};
Do[
ek[k + 1] = seq[[k]];
Do[
ek[j] += (ek[j + 1] - ek[j])/(1 + q);,
{j, k, 1, -1}];
res = {res, ek[1]};,
{k, n}];
Flatten[res]]
 
@J.M. and what kind of vector should I pass it?
 
@Rojo hello always pingable @Rojo :)
 
@rm-rf Yeah, that works, but there's just something uncomfortable about having to make a dummy function for this...
 
@J.M. Heh, exactly why I asked... it just seemed like something I should be able to do without an auxiliary function
 
@robjohn Remember the Euler transformation for alternating series? This routine does transformations of partial sums. You just pass a list of partial sums to the routine.
@rm-rf I'll have to think about it too... :D
 
1:04 AM
@J.M. Ah, okay. Pretty cool. I will have to play around with it.
@J.M. what is q (when other than 1)?
 
For example: eulerKnopp[N[Table[Sum[(-1)^j/(j + 1), {j, 0, n}], {n, 0, 10}], 20]] would perform the transformation on successive partial sums of Mercator's series.
 
The last comments of @SjoerdC.deVries and @frizzics in my answer here makes me wonder whether we have an extensive discussion about the timing issure of AppendTo here on Mma.SE
 
@robjohn That's a generalization of the Euler transformation I found out about, though so far I've been mostly using the default setting...
 
I haven't found something in the search. Not even on SO.
 
@robjohn Here is the article I found the algorithm in.
 
1:06 AM
@J.M. Hmm... something to look into. Thanks
 
@halirutan Sounds like a plan.
 
@J.M. Yes, especially since I checked my books here and no one discusses this except of David Wagner. But I don't have all Roman Maeder books and the Stan Wagon book.
 
@J.M. Downloaded. I will read it after dinner. Cool!
 
@rm-rf I wonder; maybe If[AtomQ[#], #, Sort[#]] & //@ list might do the trick...
@halirutan Well, Wagon only did a slight segue on the disadvantages of AppendTo[] if memory serves, so I think Maeder is the only thing you'll need to look at...
@Rojo BTW, are you familiar with this:
;)
 
@J.M. That's a picture of my father
 
1:14 AM
Ah, there we go...
 
@J.M. Yes, that should work too
 
Interesting, they're actually hexagonal?
 
Yeah
 
you're a smart cookie, @Rojo... you removed it quickly before we unleashed jokes about yo momma ;)
@J.M. Also, Block[{f}, SetAttributes[f, Orderless]; list /. List -> f /. f -> List]
 
@rm-rf Devious. :)
 
1:25 AM
:)
 
@J.M. I ran that through Google Image Search and got this link as the closest match.
@rm-rf we can still see its lingering image :-)
Taking my dog to the park. See yall later :-)
 
Heheh
 
hi all
 
Alo
 
Heh. I'm still missing that gum... it's hard to get outside America.
 
1:42 AM
 
I'm actually not too enthused about cigar(ettes) myself, so I stick to gum. :)
 
@J.M. You may chew them
 
@belisarius what happened here? Last I saw he had accepted yours...
I saw the transcript... looks like he was completely clueless
 
@belisarius Ugh, no. :P
 
@rm-rf As I say in my (edited) answer. Trying to help him was pointless. He came up with more and more questions in the comments, sometimes incomprehensible ones
@J.M. So perhaps an stylish snuff
 
1:48 AM
@belisarius "He came up with more and more questions in the comments" - a habit of his...
 
@J.M. Yep. I got tired and deleted the whole thing
 
@belisarius Jeez, it's not as if there's no shortage of carcinogens to enjoy at my workplace... :P
 
I was assuming you'd made the assignments a = {1, 2, -3}; b = {-1, 4, 1}; first... — J. M. 10 hours ago
hahaha!
 
@rm-rf I actually slapped my head at that... yikes.
 
@J.M. I remember the joys of working with di-nitro-bencene :D
 
1:52 AM
@J.M. Next time someone asks how to do the eigendecomposition of a 1000x1000 matrix, you should tell them to update their question when this finishes evaluating: Eigensystem@Table[Unique[x], {1000}, {1000}]
 
@belisarius Smells nice, but it'll kill you slowly. Yeah...
 
@J.M. We were heating it. Can you imagine?
 
@rm-rf Cruel, you are... ;P
 
@rm-rf Eigen means own. If it's my own Table, I wouldn't share the results with you
 
@belisarius mind your eigen business?
 
1:56 AM
:D
 
@belisarius In a hood, I'd hope...
 
@J.M. Thoughts on belisarius' meta post?
 
@J.M. Nope. We were doing something with a kerr cell. Polarizing a laser, I think. The capacitors leaked some current and the liquid started to boil. Nice. We powered the equipment off and ran to the street
shouting "La puta madre" of course
 
@rm-rf We definitely should not migrate the toolbag thing. I haven't run through the entire thing for gems to put in here; I should do that...
 
@J.M. That has been already decided. The toolbag stays there.
 
2:00 AM
Whoa... fanatic on meta! Now that's something I didn't aim for
 
@belisarius Mmm, carcinogens...
 
@J.M. Nope. We ran because there is a certain risk of getting tri-nitro, and you know, it's not stable
 
@belisarius Don't worry about it disappearing (re: your toolbag meta post). If it does, one of us will get it undeleted and probably locked
 
I can see the headlines... "Laser experiment went with a bang."
Hmm, I need to buy water. I'll be back in a few.
 
 
2 hours later…
3:41 AM
@SjoerdC.deVries I left the code to download the palette version -1.5 in my meta answer
 
4:05 AM
@belisarius "the whore's mother"? It has been well over a decade (nearing 2) since I've had spanish.
@rm-rf You don't even need to do that. Calculating the characteristic equation of a 12x12 will do it. You don't even need to calculate any eigenvalues!
 
@rcollyer Sounds about right.
 
@J.M. it does, but thought I'd check.
 
@rcollyer ...and you're cruel, too. ;P
 
@J.M. a symbolic determinant should not take that long. Yes, it is factorial growth in n, but give me a break! My old system had serious issues with a 9x9.
 
@rcollyer Nope, It's an idiom
 
4:10 AM
@belisarius well the literal seems fairly provocative, what's the figurative?
 
@belisarius Well, it's the literal translation... of course, it's similar to using "fuck" even in situations that don't really involve copulation.
 
@rcollyer Something like "Damn!"
 
@J.M. compulation? computing while ... ?
 
@J.M. compulation? Ahh I see. You mix work and pleasure!
 
Hey, no fair! It was a great typo!
 
4:12 AM
@J.M. flagged for a flagrant fault to provide universal joy
FFF
 
@belisarius Starred. :D
 
Hey, math guru .. er @J.M. for a slow calculating function, which would be a better scheme at minimization: conjugate gradient or a quasi-newton?
I have a crystal that exhibits an orthorhombic distortion, and I'd like to determine what DFT says is the "correct" distortion. Hence, the need for minimizing the number of functions calls.
 
@rcollyer test ride it :)
 
@belisarius I'd like it done in a week, as that is all I really have left.
 
@rcollyer Once upon a time, I'd have said CG. Nowadays, it's said that the L-BFGS variant of quasi-Newton is sufficiently competitive. Of course, you still need to do tests of your own...
...but yeah, L-BFGS will beat out the older quasi-Newton methods.
 
4:16 AM
Don't need L-BFGS, as memory is not an issue, per se. But, looked into BFGS.
 
@rcollyer "ortho" in Spanish is pronounced like "orto". And "orto" means "ass".
so ...
 
@belisarius that makes such a distortion much more interesting.
 
Damn ... trying to conclude something ...
 
@belisarius The animal or the body part?
 
@J.M. the body part.
 
4:18 AM
@J.M. I thought burro was the animal.
 
@rcollyer burro, asno, mula
 
@rcollyer I know the thing was designed for less storage, but I've found the thing has less overhead as well, at least in the tests I did. Neck-and-neck, see...
 
mule, donkey, ass
 
@rcollyer I know burro, but I wanted to be sure I wasn't missing a synonym...
 
@belisarius it translated well enough. :)
@J.M. What did the burro think of the relationship?
 
4:20 AM
@rcollyer I don't really know. :D
 
@J.M. Well, I don't know much about burros, except that ... oh well
 
@J.M. interesting. I'm leaning towards conjugate-gradient for ease of implementation, but I'll have to look into it.
 
...reminds me of this great line in Shrek: "I've gotta save my ass"!
 
@J.M. DO you have an art major?
 
At my high school, one of the "highlights" of homecoming was donkey basketball. Plenty of shovels were on hand.
 
4:23 AM
@rcollyer For CG, Polak-Ribiere is standard; I'm told there are modern, more efficient variants, but I haven't studied them.
@belisarius No, I just have art as a hobby...
 
@J.M. looking at Fletcher-Reeves at the moment mostly because it is the first that gave me pseudo-code!
 
@rcollyer ...it's more prone to stalling, tho.
 
@J.M. which may or may not be a problem. I know the energy dependence has a non-quadratic dependence on the lower-volume side due to an inherent issue with LAPW.
 
@rcollyer LAPW is the basis set, right?
 
@J.M. yes, where the region around the atom is calculated using atomic like orbitals, and outside that sphere is planewaves.
 
4:29 AM
Ah, I'm looking at the formulae now. Nasty stuff.
 
And, there are a couple of different forms. LAPW is C1 continuous at the boundary. There are alternatives, that are faster so in common use, that are C0 across the boundary.
 
Well, being $C^0$ would give the optimization routines trouble; you'd be forced to use something like Nelder-Mead instead...
So, Scylla and Charybdis again, I guess.
 
Actually, not relevant. I'm only dealing with what's coming out, the energy, not the basis itself.
 
You're saying the energy function won't inherit the continuity properties of the basis set chosen?
 
Not the dependence on lattice spacing. With some caveats.
The big one: the muffin-tin radii. Larger gives better speed, smaller gives lower energy (larger basis due to the number of plane waves increasing).
 
4:36 AM
I see.
 
I tend to fix mine at the beginning at 90% of max, and leave it until I've squeezed it to nearly 100%. The issue of course, the basis size decreases with volume introducing a bias.
Note: this was recommended by the authors of the package. :P
 
@rcollyer Seeing you're in a hurry, I suppose this isn't time for arguments... :D
 
It nets a difference of about 1 eV between 90% and near 100% while keeping the cell size fixed. Not small.
So, at some point, I have to characterize, but not now.
 
...BTW, since you'll be playing with both CG and BFGS: you will need a good line search method.
 
I've noticed. Simple secant method?
 
4:43 AM
You'll want to see this and this.
They claim to be able to outdo More-Thuente (which also happens to be the line search used by Mathematica).
I did a few tests a while back, and it does have a slight edge. Again, you still have to do your own testing.
 
Although, the machine I'm likely to run this one has v6, so I could always use Run to feed the info into NMinimize! :)
Not sure that's advisable, though.
 
Heh. :)
 
My software is already a bit of Frankenstein's monster, no need to further complicate it.
 
Not Rube Goldberg? ;P
 
Although, I thought using awk for running a cluster was a stroke of genius (imbalanced genius, but genius nonetheless).
Thanks for the papers. They will help. But, it is very late here, so good night.
 
4:59 AM
@rcollyer Sure. See you later. :)
 
5:09 AM
@J.M. Do you run linux?
 
@belisarius I'm on Ubuntu, yes.
 
@J.M. Do you have a few minutes to test a palette?
 
Okay, where do I download?
 
Bootstraping here
NotebookPut@ImportString[Uncompress@FromCharacterCode@Flatten@ImageData[Import@ "http://i.stack.imgur.com/gylFH.png","Byte"],"NB"]
It will create a nb
with the palette code
 
I've been able to produce the palette. When I tried it out on an old notebook, I get Java::excptn: A Java exception occurred: java.lang.ClassNotFoundException: org.apache.commons.httpclient.methods.multipart." and other error messages.
 
5:19 AM
@J.M. Ok. Do you use Szabolc's palette?
 
@belisarius Sometimes. The version I have is 107.
 
he uses the same classes
in fact ... it is his palette
oh. well. thanks for your time. I'll have to find a Linux to test it
 
Apparently. Szabolcs's works, but yours stalls. Oh well.
@belisarius you're welcome. :)
 
@J.M. MacOS follows! :D
 
 
3 hours later…
8:23 AM
@J.M. There's quite a lot of editing going on.
 
@Mr.Wizard Quite a lot. OTOH, weekends are slow, so methinks this is a better time...
 
Agreed. I was bored, and I see you joined in.
 
8:36 AM
This question has been flagged as "Off topic" -- I do not see why:
0
Q: The point on the sphere nearest to the plane

minthao_2011On the sphere $$(x-1)^2 + (y+2)^2 + (z-3)^2 = 25,$$ find the point $M$ nearest to the plane $$3x -4y + 19 = 0,$$ and calculate the distance $d$ from this plane. How do I tell Mathematica to do that?

@J.M. your thoughts?
 
@Mr.Wizard I've dismissed it. It's lazy, but on-topic...
 
 
4 hours later…
12:22 PM
@zeroth Yes, I'm here.
 
Ah, here... I created a room for us, but this is fine! :)
 
@zeroth No, lets go there.
 
ok. :)
 
 
2 hours later…
2:11 PM
@Mr.Wizard I'm starting to think he's using us to do his HW
Too many Qs without a clue of what to do in Mma ...
 
@belisarius I've restrained myself this time. If he still can't figure things out from the formula I pointed to, then there's little hope...
 
2:59 PM
@J.M. I think sharp and dull people should be helped alike, but laziness is "harina de otro costal" (ie is a completely different story)
 
"a different kettle of fish". :)
 
@J.M. I can't understand why he resists to write down Mma code in his questions
 
@belisarius You and me both.
 
4:02 PM
@J.M. resistant to any advice..
 
@halirutan Do you understand this one?
1
Q: Finding all invariant polynomials of $GL(2,\mathbb{C})$-action on $M_2(\mathbb{C})$

math-visitorI am trying to program Mathematica to do the following: Let g = {{g11,g12},{g21,g22}}; m = {{m11,m12},{m21,m22}}; I would like to make Mathematica to do the following for me: Find all polynomials in the entries of the matrix $m$ which satisfy $gmg^{-1}=m$. That is, MatrixForm[g.m.Inv...

Where is the poly in the condition?
 
4:18 PM
@belisarius Assume you have a poly which uses the entries of a matrix like the example:
p[mat_] := mat[[1, 1]] + mat[[2, 2]]
This poly fullfils the requirement
g = {{g11, g12}, {g21, g22}};
m = {{m11, m12}, {m21, m22}};
p[g.m.Inverse[g]] == p[m]

FullSimplify[%]
He wants to know all polynomials which do this ;-)
 
@halirutan So, a p[...] is missing in the requirement, isn't it?
 
@belisarius No, if you want to find all minima, you don't have the minima as requirement. He wants to find all polynomials. He doesn't know them before. He knows one single solution of maybe infinitely many which is the Tr[m] example.
 
@halirutan Ok, Thanks!
 
@belisarius I had invariant theory but forgot everything. Sorry.
@belisarius Why did the author removed the question this second?? I just wanted to edit his question to make it more clear to the audience!
 
4:39 PM
@halirutan sorry, gotta go. Thanks again
 
 
2 hours later…
6:46 PM
So many users, yet no one's talking
 
drN
@haliurtan This is in relation to a "parallel/cluster/ssh" question I asked a few days ago. Are there any open source clusters available for access?
 
@drN yes.. I wanted to ask you something about this
If I run a command with ssh -x .. do you know where this command is executed?
 
drN
@haliurtan ssh -x should run on the computer I am ssh-ing into...
 
So your setting was: Fast computer without Mma and slow computer with Mma..
 
drN
Yes, fast computer without and slow computer with....
And I run MathematicaScript
 
6:56 PM
And you wanted to make a ssh -x into the slow computer to what achive exactly?
 
drN
no.. Heres a breakdown of my problem: 1) My computer has mma but is limited on resources. 2) I have cluster access with lots of resource but NO mma. 3) I'd like to use the mma and MathematicaScript interpreter (???) FROM my slow computer to run mma script ON fast.computer and store data on fast.computer
So I guess, I won't be using ssh -x as I don't need the gui front end...
 
Yes, and I'm afraid exactly this cannot happen.
 
@drN that would not be possible... you'll have to get a new license
 
drN
@haliurtan Oh! Crappola! :(
@rm-rf Oh! Crappola! :(
 
@drN With Mma you have several possibilities:
1.
 
6:59 PM
@drN Director of Shitty Godfather?
 
drN
Any open source clusters available for me to use? I looked around and found one (nimbus... nimbius or something) but there is a charge...
@halirutan go on... with the possibilities...
@rm-rf I haven't actually seen "Godfather"...
 
@drN But in order to run Mathematica there you need a licence
So 1.:
You have a local licence for a pc and can run Mma there and nowhere else
 
drN
@halirutan Check (1): Local pc, nowhere else.
 
2. You have a local licence for several PCs than you can export computations to their Kernels.
 
drN
@rm-rf Oh, franci ford coppolla... slow, I am.
 
7:01 PM
One master and several slaves
 
@drN :)
 
drN
@halirutan (2) How so? one master several slaves? over a network?
 
Yes, over network
 
drN
@halirutan and I do that how? I remember seeing something... vague... StartKernel ish
 
@drN howto/ConnectToARemoteKernel
check this in the doc-center
 
drN
7:03 PM
@halirutan Just doing that actually....
 
@drN Are you a student and/or do you have a student license?
 
drN
@rm-rf Student. I have a student license.
 
Then you cannot install it on any cluster or work computer other than your personal desktop/laptop
 
drN
@rm-rf Sure. I understand that. Which is why I am miffed at our IT support. On campus I obv. have a full license but it isn't installed on any cluster.
 
3. You (like in our university) have a licence server running. When you buy this from Wolfram you get installation disks for all systems and you just install Mathematica locally but when you start it, it gets its licence from the licence server.
 
7:06 PM
WRI will not allow you to move your license to a different machine... been there, tried requesting, got declined. Same scenario — I wanted to run mma on a faster machine which didn't have a license and I thought I could install it only for my user... nope.
 
drN
@halirutan also, using a remote kernel, can I parallelize my NDSolve loop to run on several cores? Is that what happens?
 
@drN Yes you can.
 
drN
@rm-rf So my best bet for now is to turn really religious and pray that IT wakes up and gets mma installed on the clusters...
 
Even locally
 
drN
@halirutan I notice that mma pretty much uses 4 out of 8 cores without me having to parallelize it explicitly...
 
7:07 PM
@drN That never works... Try asking them or your advisor to pay for a single user license
 
@drN on some numeric functions, yes
We had this never ending question lately about it. Did you read it?
 
drN
@rm-rf IT is in some sort of impasse right now.. most of the intense simulation related work at my uni have stopped over the last 4-5 weeks and people are getting borderline suicidal.
@halirutan I don't think I read the question that you mention
 
@drN In M you have at least 3 different forms of parallelization. It's to much to explain it in one answer..
Thats why no one who could (like OleksandrR) answered it.
 
drN
@halirutan Will read it...
thanks
 
@drN So the short answer to your question is: I don't think it is possible to use the power of your faster computer when you have only one local installation on the slow one.
@rm-rf Does the factorization appled run on your pc?
 
7:12 PM
@halirutan yeah
 
drN
@halirutan Thanks. Very useful all this discussion has been
 
@drN You're welcome.
@rm-rf can you try it with this integer:
2614930428035201342411278280525965452621044417207937542347
 
drN
@halirutan So do you want to flag the question as closed or what happens next?
 
Factorization complete in 0d 0h 0m 5s
ECM: 2185028 modular multiplications
Prime checking: 34594 modular multiplications
SIQS: 14502 polynomials sieved
43917 sets of trial divisions
1508 smooth congruences found (1 out of every 343355 values)
18192 partial congruences found (1 out of every 28461 values)
1774 useful partial congruences

Timings:
Primality test of 3 numbers: 0d 0h 0m 0.0s
Factoring 1 number using ECM: 0d 0h 0m 0.8s
Factoring 1 number using SIQS: 0d 0h 0m 4.4s
 
@drN The question itself is not bad. You could have investigated a bit more what really happens with ssh -x but I wouldn't flag it.
 
drN
7:17 PM
@halirutan Ok.. I'll look further into parallel processing et al. However since that will probably take a back seat to other stuff that I need to do to progress my work, it'll be a while before I revisit this question.
 
@drN np
@rm-rf give me a sec
 
@halirutan I don't know what to make out of the applet's output... perhaps it too is doing a simple factorization?
 
@rm-rf But with these two big factors, what is a simple factorization?
 
7:35 PM
@halirutan oh, right. I was still thinking of the earlier integer. Here's an output from one more panel for the integer you gave:
2614 930428 035201 342411 278280 525965 452621 044417 207937 542347 = 97
913387 938680 010938 335707 x 26 706566 722753 457593 818813 677521

Number of divisors:  4

Sum of divisors:  2614 930428 035201 342411 278307 232630 088762 440691
037689 555576

Euler's Totient:  2614 930428 035201 342411 278253 819300 816479 648143
378185 529120

Moebius: 1

Sum of squares: a^2 + b^2 + c^2
a = 45643 658492 015225 557115 127705
b = 23056 167667 231424 089070 791719
c = 19
It does find it correctly. I have no idea why mma is slow
 
@rm-rf Me neither.. maybe it uses the wrong method for too long before switching. I have no idea. I never looked deeper into the whole prime factorization algorithms in Mma although I had a whole lecture in university about it.
 
Classic mma documentation:
> Timings can increase rapidly and unpredictably with the size of the input
Is it possible to do what the OP wants here?
 
7:51 PM
@rm-rf It's like firing a gun on your toes
@rm-rf What OS are you running?
 
OS X Mountain Lion
 
@rm-rf Do you care to test ride a small palette?
 
Is this for your palette?
heh
sure
 
Wanna the link?
 
drop it
 
7:54 PM
NotebookPut@ImportString[Uncompress@FromCharacterCode@Flatten@ImageData[Import@ "http://i.stack.imgur.com/gylFH.png","Byte"],"NB"]
run it, it will bring up a notebook
execute that notebook
and it will show a palette
 
A crap ton of java failed to load class errors when I try to upload a notebook
And yes, Szabolcs' palette works well
 
@rm-rf Most curious
the same happened to @J.M.
on Linux
On Windows it works ok
and it's using the same Java code than Szabolc's
in fact, I copied it from him
Well, thanks (anyway :p)
 
Heh, no worries :)
 
8:23 PM
Hmm... can someone try this: p = Plot[Sin[x], {x, 0, 10}, Frame -> True, FrameTicks -> {{{-1, 0, 1}, None}, {{0, Pi, 2 Pi, 3 Pi}, None}}]
Now add // FullForm to the graphics output and look at the structure of FrameTicks -> ... and compare it with that in p // FullForm
Why is there a difference?
 
@rm-rf have you tried to evaluate AbsoluteOptions[p, FrameTicks]
@rm-rf have you tried to evaluate AbsoluteOptions[p, FrameTicks]
?
 
@halirutan Yes, not now exactly, but I know what it will return...
I expected the contents of p to be exactly the same as the displayed graphics... why isn't it so?
 
@halirutan FrameTicks has a bug
try
p = Plot[Sin@x , {x, 0, 2 Pi},
FrameTicks -> {{None, {-1/2, 1/2}}, {{0, Pi, 2 Pi, 3 Pi}, None}},
Frame -> True]
and then
AbsoluteOptions[p, FrameTicks]
@halirutan It has already been reported here
 

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