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$(a,b)$ is a couple of twin primes such that $b=a+2$ and $a > 29$. Let $N = 4^b$ and $q$ the quotient which results from the division of $N$ by $a$ and $r$ is the remainder. We calculate $P = (q\bmod b)a+r-1$ Below we prove that $P = 3(10b+1)$ using Fermat's little theorem. $N=16\cdot4^a\equiv64...