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Teresa Lisbon
Teresa Lisbon
12:44 AM
 
 
7 hours later…
Prasun Biswas
Prasun Biswas
7:55 AM
Request for closure and/or deletion: https://math.stackexchange.com/questions/4215564/find-lim-x-to0-left-lim-n-to-infty22n-left1-leftf-circ-nx-ri

Very low-quality post. The problem is a classic one: the $x=\cos(\theta)$ sub is the simplest approach exploiting the cosine double-angle formula leading to $\pi^2/16$, yet OP refuses to elaborate and instead "ask for other approaches as it will be helpful to them and others of the community."

I'm amazed the only close vote on it is mine till now (though, with 3 downvotes already).
 
 
3 hours later…
Saad
Saad
11:06 AM
One more vote needed: C1
For closure: C2, C3, C4, C5, C6,
C7, C8, C9, C10, C11, C12
For deletion: D1, D2, D3, D4, D5, D6
@Peter I'm not 100% sure, and still waiting for mods to deal with my pending flags.
 
Teresa Lisbon
Teresa Lisbon
11:25 AM
@PrasunBiswas It's been self-deleted, the approach via the cosine substitution was available in an answer I found just yesterday, maybe the question was by the same author.
 
 
1 hour later…
Saad
Saad
12:51 PM
 
Shaun
Shaun
1:43 PM
reopen The answer given in the supposed duplicate uses the class equation. Here is the question.
 
 
1 hour later…
Peter
Peter
2:43 PM
 
user1729
user1729
3:40 PM
This trivial answer has a trivial error.
 
amWhy
amWhy
4:03 PM
@Saad All gone!
 
rschwieb
rschwieb
4:33 PM
This is a repost by the same user (I’m pretty sure it’s the same content, it’s definitely the same user): math.stackexchange.com/q/4215878/29335 I used to be able to get back to deleted questions via the RSS feed but since I’ve neglected to replace my broken reader I haven’t had that option. Are there other ways of finding recently deleted things without having bookmarked them?
 
amWhy
amWhy
5:15 PM
@TheSimpliFire Some times users post single observations here, @TheSimpliFire. whether humorous, or casual. Now: Scroll as far back as you'd like: when I post suggesting an action, I explicitly say so. Lighten up a bit.
 
Prasun Biswas
Prasun Biswas
5:59 PM
@TeresaLisbon Hmm, that might be the case. I knew the problem back from years ago on a math forum where I solved it, though it was formulated with $a_{n+1}:=\sqrt{(1+a_n)/2}$ and a seed $0<a_0<1$ with the limit expression being $\cos(2^{n+1}\sqrt{(1-a_n)/2})$ so that the answer would be a simple $\cos(\theta_0)=a_0$
 
Arctic Char
Arctic Char
6:39 PM
 
amWhy
amWhy
7:23 PM
→ 4 messages moved to ­Trash
 
Michael Albanese
Michael Albanese
8:16 PM
I notice that this question has received two downvotes and two close votes (missing context). It is a reference request, so I'm not sure what other context those users were hoping for. Any suggestions as to how this question could have more context?
Full disclosure, I answered the question because I thought it was fine. I found out about the downvotes and close votes because my answer received a downvote.
 
vitamin d
vitamin d
8:48 PM
 
Xander Henderson
Xander Henderson
9:04 PM
Per my comment at the bottom, I don't know that this question is on-topic. Is there some "Business SE" or "How to Get a Job SE" that we should send it to? or is it on-topic?
 
amWhy
amWhy
9:14 PM
@XanderHenderson It's no more on topic here than it would be on physics, or recreational math, or....
 
vitamin d
vitamin d
9:41 PM
 

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