CURED

user12692

2:08 AM

@SimplyBeautifulArt I thought it means lol...

user12692

-11

Q: Show that if $(xy)^n = (x)^n(y)^n$ then $xy=yx$.

Show that if $(xy)^n = (x)^n(y)^n$ then $xy=yx$. (Please don't use induction method)

user21820

6:40 AM

This PSQ deserves to be closed and downvoted, but the answers may be interesting enough to warrant keeping.

Martin Sleziak

improve Is $\sum_{n=1}^\infty \frac{1}{2^{n^2}}$ is rational number? - this seems to be a similar case.

Both questions are somewhat interesting, both question can be solved using by looking at the number in base 2.

It seems that Approach0 is down at the moment, which makes looking for duplicates a bit harder.

user21820

6:59 AM

→ 10 messages moved to trash

@MartinSleziak Aww. Actually I think finding duplicates is a futile job haha..

@Jack: Have you yet taken a look at this? It makes 2 serious errors in 1. Firstly it implies that you can have subtraction of set sizes. Secondly it says that infinity minus infinity can be 1 (in fact, it can be anything). If you agree then we'd appreciate an extra downvote so that it can be deleted. =)

Martin Sleziak

@user21820 Well, as you probably noticed, looking for duplicates and closing duplicates is big part of what I do on the site.

But my life as a whole can be described as futile, so there is no surprise that many people see my activities on the site as such.

user21820

7:14 AM

@MartinSleziak Sorry I don't mean to imply anything about people who do it, since whatever you do will improve the site, and many crumbs make a cake. It's just that we don't have a high enough fraction of the Math SE users who do it.

Martin Sleziak

7:45 AM

@user21820 I am not offended or anything like that. (Sorry if it sounded that way.) I just saw the opportunity to post partly funny and partly pessimistic remark. Anyway, as not to distract from the actual purpose of this room, we can continue this elsewhere - if there's something to add.

user12692

11:48 AM

@user21820 Just did it. Here is another one: math.stackexchange.com/q/2111603/9464

user21820

@Jack Thank you! @amWhy @SimplyBeautifulArt: It's ready for deletion now! =)

Martin Sleziak

1:04 PM

@user21820 @Did I am not sure whether closing as a duplicate is the right choice. One question is about value of the sum, the one which was closed is asking whether or not it is rational.

The above is about 2379458: Is $\sum_{n\ge0}\frac1{2^{2^n}}$ rational? and 788772: How to sum this series to infinity: $\sum_{n=0}^{\infty} \frac1{2^{2^n}}$.

Martin Sleziak

1:28 PM

OTOH it was quite likely that the question was about to be closed for lack of context, anyway... shrug

user21820

@MartinSleziak I think I voted to close for lack of context, not as duplicate. Perhaps it doesn't show, or perhaps I clicked wrongly.

Martin Sleziak

@user21820 I think we discussed this before. Only one close reason shows. (This case might be different because it was using dupehammer, but for example if 2 users vote to close as off-topic and 3 users to close as a duplicate, than all 5 names will be displayed near the message that it was closed as duplicate.)

user21820

I see. I can never remember the tiny details of the workings of SE haha..

Martin Sleziak

Yes, we have talked about this here: chat.stackexchange.com/transcript/message/39048469#39048469 Or maybe link to beginning of that exchange is better: chat.stackexchange.com/transcript/message/39048317#39048317

Transcript for

$Mathematics$ CURED