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00:40
Dv/D likely an AI generated answer, ditto for many of the authors' other recent answers.
 
6 hours later…
06:55
[ SmokeDetector | MS ] Few unique characters in answer (89): Walk with disciplines, and logic together ✏️‭ by ee ff‭ on math.SE
[ SmokeDetector | MS ] Few unique characters in body (95): Walk with disciplines, and logic together ✏️‭ by ee ff‭ on math.SE
 
6 hours later…
13:02
I suggest to close math.stackexchange.com/q/5008344/42969 as a duplicate. I have provided two links to identical questions, and both have more questions linked to it, so this has been asked and answered multiple times.
13:34
How do I get people to upvote my questions? I'm currently question banned and I really need to ask some questions. I currently have 0 upvoted questions and a few down voted ones.
14:01
@MartinR the duplicate candidate you refer to is about the proving a given identity, this question is about the identity itself and how its "impossible to hold". I'm closing it, but for lack of context instead
 
5 hours later…
19:03
[ SmokeDetector | MS ] Link at beginning of answer (39): Spot it! and geometry over finite fields.‭ by mr.beast‭ on math.SE
 
4 hours later…
22:44
0
Q: Avoid unnecessary calculations when multiplying matrices if only need one element of resulting matrix

WeCanDoItGuysThe Problem: I need only the bottom left element of a product of matrices $(\bf{M_1}+\bf{I})(\bf{M_2}+\bf{I})\cdots(\bf{M_N}+\bf{I})$, where $\bf{I}=\begin{pmatrix} 1 & 0\\ 0 & 1\end{pmatrix}$, and $\require{cancel} \bf{M_i}= \begin{cases} \begin{pmatrix} 0 & x_i\\ 0 & 0\end{pmatrix} &i\equiv N\p...


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