math.stackexchange.com/questions/3525067/… close

@user21820 they are trying to claim that c can be pulled out of an integral where c is any function.

How is that not being a crank?

By most math standards I've heard most people are cranks, myself included.

@user64742 I don't think that is what they are claiming. While it is not clear, I believe that they are assuming that $c$ is a constant. The assumption is that $f$ is an integrable function, and also that $cf$ is an integrable function. While $f$ integrable implies that $cf$ is also integrable for any constant $c$, perhaps they don't want to prove that, hence it is by assumption.

Moreover, since they are claiming that they know how to prove the result via a different technique, I think that this is really just a matter of the question not being sufficiently clear, rather than someone trying to prove something cranky.

@user64742 I agree with user21820. I don't see anything cranky there. I suspect (luckily) you've never encountered a real crank. See for example Underwood Dudley's book Mathematical Cranks or sci.math posts by Archimedes Plutonium (e.g. his "proofs" of the Twin Prime Conjecture) for the state of the art.

@XanderHenderson ah. I guess I’m just the other sort of cranky today.

@BillDubuque I’ve seen my fair share of stupidity. If I understand the phrase correctly 90% of this site is stupidity.

@user64742 You might be misunderstanding the meaning of "crank" in this context. See the Wikipedia page for an introduction.

I have nothing to add to Xander and Bill's comments about this post.

[ SmokeDetector | MS ] Offensive answer detected, potentially bad keyword in answer, toxic answer detected (159): Find such x so that set {sinx, sin2x, sin3x} coincides with the set {cosx, cos2x, cos3x} by John Horan on math.SE

@BillDubuque Indeed, I have long been aware of that user. They are now up for deletion. This nonsense (see Gerry's and @rschwieb's comments) needs one more delete-vote.

@user21820 Final nail in the coffin for that post.

@rschwieb: Thanks!

Delete: d1

Nonsense says that an integer is uncomputable. @RRL @BillDubuque @rschwieb

Bad answer.

@user21820 @JyrkiLahtonen @JoséCarlosSantos @XanderHenderson: DA - DP need votes. Thanks.

D1, D2, D3.

D4, D5, D6.

D7, D8, D9.

D10, D11, D12.

D13, D14, D15.

C1, C2, C3.

C4, C5, C6.

C7, C8, C9.

C10, C11, C12.

C13, C14, C15.

Hello, everyone! I'm Baaack! Hello to you, especially, @user21820 !

@XanderHenderson Hello to you, in particular, Xander!

@user21820 gone!

In your last post, @user21820, all D's are now deleted.

Who's in developer mode deleting Namaste from their screens ( sadly I can't).

I've flagged your post, @Roddy. Incredibly rude and unwelcoming!

Nice to see you back @Namaste

@RRL Thanks! good to see you too!!

Hard for me to tell a crank a troll or mathmatician on this site.

@RoddyMacPhee I'm referring to your second to last comment. Offensive, and flagged.

I see starred

@RoddyMacPhee I will take this matter above you. Live by the rules I have been required to live by.

@RoddyMacPhee @quid Please reference this post. My first day back; and I face this rudeness.

@RoddyMacPhee @quid, please see this as well. I don't much appreciate SE or SE wanna-be-developers harassing me within hours of my reappearance.

Hi, @JoséCarlosSantos! It's been awhile!

Yes, it has. And, yes, I agree that you got harassed.

@BillDubuque: This one is even better.

@darijgrinberg I already mentioned that doozy above. It needs only one more delete vote.

Where is Underwood when we need him?

@BillDubuque Gone!! (No pun intended!!) :-)

oh i see

her old posts aren't too bad

@Namaste Hah!

argh

> we can live in a space, and not know whether it's euclidean, hyperbolic or spheric

@darijgrinberg Ah, the perils of "prowling on the outer limits of my home-wrought hyperbolic geometry".

How's it going for you, @BillDubuque? Glad to see you participating here!

@Namaste It is nice to see you again. I am glad that you are back on MSE (and that you are still hanging around on MESE).

@XanderHenderson Good to see you here and "there", too!!

Hello, @rschwieb! Good to see you active in this room!

@Namaste that’s a bit of an exaggeration but thanks all the same. Welcome back.

@rschwieb Thanks! Good to see you here when you can! (Is that better? :-) )

math.stackexchange.com/questions/3526324/… Anyone with any close votes left, please see the linked question.