5:36 PM
Hi Martin, Narasimham here , are you there?

6:03 PM
@Narasimham I am now.

6:23 PM
Hi, I liked your polygon inside polygon post

@Narasimham I am not sure which post you mean.
Maybe it's a different user with the first name Martin?
3

Update Won't include the trig as rather lengthy, but included as visual complement to give genreal idea: Note that a shutter on a traditional camera works on this same principal: Note also that Narasimham's observation of the paths taken offer visual proof of the conjecture, and for gre...

ok,ok

room topic changed to Martin Sleziak's room: Miscellaneous (not suitable elsewhere) (no tags)

6:55 PM
Hi there, can anyone help me with an algebra question

@KellyBlunie It is probably better to ask in the main chatroom or in algebra chatroom. (But the later is empty most of the time.)
You have bigger chance there to find someone who will be willing to answer.
If we want to see if a set of vectors spans a vector space $V$, then lets say the set $A$ spans a vector space $V$. If every linear combination of $A$ produces $V$, then $\text{Span}(A) = V$ Edit: if we forme the coeficient matrix of the system formed by $c_1s_1+..+c_ns_n =u$ where $s_i$ are the...
After looking in my book for a couple of hours, I'm still confused about what it means for a $(n\times n)$-matrix $A$ to have a determinant equal to zero, $\det(A)=0$. I hope someone can explain this to me in plain English. Many thanks.