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9:24 AM
@MartinSleziak Hi, thanks for your answer. I never got this... I was by chance perusing the chat rooms and saw this. I wrote an answer, summarising my view on the question. Could you check if that's true? Thanks ;)
9:37 AM
@Anoldmaninthesea. Sorry, I don't have much time at the moment.
But since you mentioned the answer in this room, perhaps that improves chance that somebody will have a look at it.
Something similar was recently discussed on meta and using chat was one of the suggestions: How can I get others to review my answer? Is bumping considered appropriate?
 
3 hours later…
12:09 PM
@Anoldmaninthesea. I looked briefly at your answer and what you write there seems reasonable to me.
2
A: Lateral limits of an endpoint of the interval.

An old man in the sea.I think I get what Fujisaki is talking about. My definition of right limit is incomplete. I should have demanded, right at the begining of the definition, that $a$ be an adherent point to the set $D \cap ]a,+\infty[$, otherwise we get this problem, since $[b,a] \cap ]a,a+\delta[=\emptyset$.

My guess would be that in most textbooks either the authors defined the notion on functions defined on $\mathbb R$ or some open interval (to avoid this problem), or use exactly the requirement you mentioned.
It would probably take some time to take a few various textbooks and check how the authors deal with this problem. But at least the definition in the book I linked above is consistent with this.
It was just randomly chosen textbook - it was the first search result when I tried searching in Google Books for these keywords: one sided limit endpoint interval.
 
3 hours later…
3:13 PM
@MartinSleziak Many thanks Martin. ;)
3:52 PM
Hello all,
I've written an answer a one of my one questions. Is it correct?
0
A: In proving primitive by substitution, we demand $x=\phi(t)$ to be a bijection. In Integration by substitution we do not. Why?

An old man in the sea.There's no need to invoke bijectivity, in the proof we just need $\phi$ to be continuously diff, so that $\phi '$ be continuous and $f(\phi(t))\phi'(t)$ be a continuous and hence integrable function. Instead of the example above, I'll use the following integral: $\int^2_1 \frac{1}{\sqrt{e^x-1}}$...


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