I was just trying to confirm to myself that the following density operator
$$\rho(t) = e^{-iHt/\hbar} \rho(0) e^{iHt/\hbar}$$
fulfills the Liouville-von Neumann equation:
$$\frac{d}{dt}\rho(t) = - \frac{i}{\hbar} [H,\rho(t)]$$
where $[H,\rho(t)]$ denotes the commutator of the Hamiltonian with th...
Backup Room – The h Bar
Backup Room – The h Bar