1:06 AM
2

I'm studying lagrangian mechanics, and there's a property where you could obtain an equivalent lagrangian $\mathcal{L'}$ from $\mathcal{L}$ by adding a function which satisfies: $$\mathcal{L'}\rightarrow \mathcal{L}+\frac{df(q,t)}{dt}.$$ This lagrangian $L'$ would give rise to the same equations...

16 hours later…
4:42 PM
2

As far as I know, the electromagnetic field strength tensor is defined to be the simplest object involving the electric and magnetic fields that transforms properly under Lorentz transformations. However, I don't get why such an object should be an antisymmetric rank $(2, 0)$ tensor, in a mathema...