Instead the 2kg mass moves upwards, so obviously there has to be an upwards force larger than $2g$ acting on it. That force is the tension in the string.
@JohnRennie okay, what I thought was the 8 kg mass is pulled down by $8 g$ so the sting there is pulled by $8~g$, on the other side the string is pulled by $2~g$, therefore tension should $10~g$, isn't it?
@Knight tension at each point of a massless string is the same. Otherwise there would be a net force on an element in the string, which is impossible since F=ma=0a=0.
@JohnRennie Hahahha, yes that's right. So, sir can you just say something like this "Accept it now the way I have done and after some time (may be few years) you will realize the truth"
If you're looking at the whole thing from the ground it moves with v upward and some different velocity down the incline. So you use vector addition to find the resultant.
If you're looking from the lift, the block will just appear to slide down the incline with some acceleration
@NoseBleed lemme provide some context you might be missing out. This is a practice problem for one of the toughest entrance exams in India. And the most certainly do not allow a calculator inside let alone Wolfram alpha
I found hunger is so demanding a rogue - it haunts no matter what you are doing, sleeping, studying, etc. sun or rain - as long as more 6 hours have passed since last meal.
so the best way to solve hunger is an automaton which makes meals every 6 hours.
the unit bit is associated with the base of logarithm. I also asked the instructor why not use 4 as the base when there are 4 symbols, rather than 2 symbols, to be used, then he replied me if other bases are used, the unit changes accordingly.
