1:05 AM
Yay I just got a gold badge!

1:37 AM
*unsung-hero

5 hours later…
6:30 AM
More like your answers tend to be underappreciated. At least that's the intent.
Realistically it means the people who accepted your answers didn't realize that they could (usually, should) also upvote them, so there's a bit of luck involved

6:45 AM
Hmm.. To me, it means "your answers sound good but aren't liked by the commuity--thus they're probably wrong". But yeah, your interpretation makes sense... I guess it happens whenever you answer a question fast enough that the OP is still online and just accepts it(w/o upvotes). The community largely tends to ignore accepted questions, i guess. Anyways, now I've got a quirky yellow dot on the screen! Who cares what the reason is ;)

2 hours later…
8:54 AM
Yeah, I guess you have a point there. Personally I consider upvotes to carry much more weight than the acceptance checkmark when it comes to determining correctness (though even the community gets it wrong sometimes). But having no votes on an answer definitely doesn't mean it's wrong.

1 hour later…
10:12 AM
Yeah, I feel the same about upvotes vs answers.. Though for some reason I feel that half my most upvoted answers are pretty stupid. http://physics.stackexchange.com/a/22254/7433 for example.. On the other hand, most of my favorite answers have very few upvotes :/

A zero-score-accept may also just mean that the _question_ wasn't interesting enough. If you see an answered question with a boring title, you probably won't visit it...
@DavidZaslavsky Oh by the way, if you missed it; I did write the script: meta.physics.stackexchange.com/questions/740/…
There's only one thing that may not work, and that's the editing auto-preview
I don't think that can be fixed with a simple top-of-the-page javascript insert; it will require a line of code buried somewhere.

11:01 AM
Is this a software glitch: For the last five minutes, all math formulas in LaTeX have been replace with the following text in red saying [Math Processing Error].

Idk, it happens to me
was happening right now as we
* as well
It usually happens on the mobile site for me... First time it happened on main
Refreshing usually doesn't help, you have to wait for it....
(It's back now, for me at least)
It's currently working on the mobile site as well
(for me)
@Qmechanic ping

11:28 AM

Alternatives:
- Edit it into the answer--may be rude
- Write a full answer yourself -- Feels evil to take inspiration from another answer.. Especially if the answer has awesome links and stuff you didn't know.

2 hours later…
1:29 PM
@Qmechanic yep, mathjax server down meta.stackoverflow.com/questions/125478/…

0

Should/Can we have MathJax on meta? It would be useful to implement stuff like this proposal. I do know the argument that it makes pageloading slow, so I propose that it only be enabled if a post has $turn_mathjax_on$ or something on it. I wrote a simple script that accomplishes this. There are ...

2:00 PM
Cool! I just got a question in the SE hot-questions dropdown!! tex.stackexchange.com/questions/47819/…
Weird thing is, its a pretty stupid question..
It's second in the dropdown. Strange...
Why aren't there any physics questions there?

3 hours later…
5:26 PM
I guess our site doesn't have enough activity to qualify anything for the hot questions list :-(
@Manishearth That's perfectly fine as far as I'm concerned. Everything is CC-licensed so there's no problem with taking pieces from someone else's answer to use in your own, just make sure to acknowledge your sources.

4 hours later…
9:24 PM
I'll say this: if you write entertaining exercices, not only will your students actually do them, but they might get some random stranger on the internet excited enough that he actually writes a detailed answer about it, even though he currently needs sleep much more than this :)
0

First part: From the formula for the radius, and the fact that magnetic field is the same in both cases, you get: $$B = \frac{m_1 v_1}{q_1 r_1} = \frac{m_2 v_2}{q_2 r_2}$$ Because you don't know the velocities, you want to get them from the potential difference. You also have  v = \sqrt\fr...

now I really hope I didn't make a stupid mistake right from the beginning :)