The below code returns all distinct combinations based on the logic that 1,2,3 = 3,2,1 = 2,3,1, so it only returns 1 instance of that set of numbers.
However, I want to change that logic so that it returns ALL instances of all number sets.
What do I need to do to the LINQ query below "GetPowe...
What would be the best way to refactor this :
@busy.each do |b|
title = b.title
@events << {
:id => b.id,
:title => title,
:start => b.busy_start_time(b.start_date,b.start_time),
:end => b.busy_end_time(b.end_date,b.end_time),
:allDay => false...
I'm not sure how your algorithm works, but I can give you a couple of suggestions about modifications that you should to do.
First of all, I think that you should have separate methods. One for returning all possible combinations of a fixed size and one for all possible combinations of all sizes...
I hit the rep-cap today (+230, including 2 checkmarks, no bounties), and then I answered an interesting question that I couldn't help but answer anyway. As "lost rep" from the upvotes started accumulating, a thought occurred to me:
If I delete this answer now, and un-delete it after midnight ...
See Podcast #72
The daily reputation cap is partly there to encourage programmers to take a break. The goal isn’t to be on Stack Overflow, but to generally do things that make you a better programmer. While that certainly includes the fractional time slices of questions and answers that progr...
In one finance application I'm working on the requirements call that I truncate a decimal value at certain number of places and not round.
example:
11.685 truncated to 2 decimal places should be 11.68
I wrote this extension method, but was wondering if someone knew of an easier way.
public st...
from gurobipy import*
m=Model("cons_test")
# My data defined as a multidict
combo, oi = multidict({
(1,1,6,1,1,1): 100,
(1,1,6,1,1,2):200,
(1,1,6,1,1,3):200,
(1,1,6,1,2,1):50,
(1,1,6,1,2,2):70,
(1,1,6,1,2,3):70,
(1,1,20,1,1,1):400,
(1,1,20,1,1,2):450,
(1,2,6,1,1,1): 100,
(1,2...
Is there a more efficient way of writing this? It seems like so much redundancy that this can be greatly reduced. Basically the only difference is if isNodeWebkit is true then run a function using key code 113 or 112
if (isNodeWebkit) {
$(document).keyup(function (e) {
if...
